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A solution is prepared by mixing 100.0 $\mathrm{mL}$ of $1.0 \times 10^{-4} M$ $\mathrm{Be}\left(\mathrm{NO}_{3}\right)_{2}$ and 100.0 $\mathrm{mL}$ of $8.0 M$ $\mathrm{NaF}.$
$$\mathrm{Be}^{2+}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons \mathrm{BeF}^{+}(a q) \quad K_{1}=7.9 \times 10^{4}$$
$$\operatorname{Be} \mathrm{F}^{+}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons \operatorname{Be} \mathrm{F}_{2}(a q) \quad K_{2}=5.8 \times 10^{3}$$
$$\operatorname{BeF}_{2}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons \operatorname{Be} \mathrm{F}_{3}^{-}(a q) \quad K_{3}=6.1 \times 10^{2}$$
$$\operatorname{Be} \mathrm{F}_{3}^{-}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons \mathrm{BeF}_{4}^{2-}(a q) \qquad K_{4}=2.7 \times 10^{1}$$

Calculate the equilibrium concentrations of $\mathrm{F}^{-}, \mathrm{Be}^{2+}, \mathrm{BeF}^{+},$ $\mathrm{BeF}_{2}, \mathrm{BeF}_{3}^{-},$ and $\mathrm{BeF}_{4}^{2-}$ in this solution.

Going on with electric chemistry here where essentially just looking at the movements of electrons throughout our system. First thing we're doing is calculating in East Cell Valley, where we have the style is e cathode reduction. Subtract e honored oxidation s. I'll do not 0.446 bolts. Subtract 9.242 volts. Eso is equal to not 0.204 vaults into the relationship between some potential and the free energy change. Delta G equals negative on F E South, where n is two moles. F is 96385 Sl is not 963850.204 so we can solve a Delta G by plugging in. All our numbers were dealt cheese negative 3.93 times 10 to the four jewels. Following this, we can take a look at the general formula announced equation that it's Esau particular to me. No, the track no point No. 591 divided by and multiplied by log Cute. Thank you is C R for two minus divided by 80 plus We have our products over our reactant. So we have moles That is too sweet. Plug in our values. So we have now have SL was not 0.242 because you calculated Dino struck No point no. 591 find by two of log cute So we're giving concentrations to plug in for C R 04 to minus and 80 plus Then we can solve for ESA that is not 0.352 volts Now, to find the concentration we can use announced equation where we have a lot of known information here we're solving for the c r. 04 to minors. Concentration that is are unknown. And so what we have is not 25 several four volts equal to 9.242 volts. Subtract no point no 591 bye bye to log C R 04 to minus divided by 1.0 small pelita. We then solve this concentration that's missing that is equal to 1.36 times 10 to the minus nine miles Paletta. Lastly, we're calculating the solidarity product of 80 cr four. So given the announced equation again, we have the equilibrium easily call sero. So what we have is no point, no no faults. It's equal to not 0.0.242 vaults. Subtract no point No. 592 volts, divided by two Log A G plus squad CR four to minus divided by a G To see our of four, where we saw for a G Plus squad CR four to minus start is equal to 10 to 8.1895 That is equal to 1.55 times 10 to the eighth on 1.55 times 10 to the eight is Thesis on Ability product for a G two c r 04