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Suppose that X follows chi-square distribution with 24 degrees of freedom. Compute P (18sX <30 ) . Round your answer t0 at least three decimal places.Suppose aga...

Question

Suppose that X follows chi-square distribution with 24 degrees of freedom. Compute P (18sX <30 ) . Round your answer t0 at least three decimal places.Suppose again that X follows chi-square distribution with 24 degrees of freedom Find k such that P two decimal places_0.05.Round your answer to at leastFind the median of the chi-square distribution with 24 degrees of freedom. Round your answer t0 at least two decimal places_P ( 18 < % < 30Median

Suppose that X follows chi-square distribution with 24 degrees of freedom. Compute P (18sX <30 ) . Round your answer t0 at least three decimal places. Suppose again that X follows chi-square distribution with 24 degrees of freedom Find k such that P two decimal places_ 0.05.Round your answer to at least Find the median of the chi-square distribution with 24 degrees of freedom. Round your answer t0 at least two decimal places_ P ( 18 < % < 30 Median



Answers

Let $x$ be a continuous random variable that is normally distributed with mean $\mu=22$ and standard deviation $\sigma=5 .$ Using Table $A,$ find each of the following. $$P(24 \leq x \leq 30)$$

Hi. This question. We're gonna find the area between two critical values. So the 1st 1 is between the probability off 0.96 on boy 15 sending you freedom 85. So what I did here is using Microsoft Excel, and he is a function chi square that in verse, then whatever the very off probability here, you should put it as one minus p marks of that. So comma, the degree of freedom on it's gonna return this value. So in this case, he is the born 15. And here's the 150.96 So the area between the two values is the Chi square here, minus guy square here. So just close it as the value like that. So it will be 4316 minus 21 0.8 on the final answer is 21.8

We have a normal distribution with mean 15 and standard deviation 3.2. We want to find the probability that X lies between eight and 12 to approach this problem. More easily, we're going to think about probability in terms of Z scores, remember that a Z score is equal to the value of x minus the mean, divided by the standard deviation. So we can convert the bounds that we're considering here. Eight and 12 and disease courses follows. For eight we have Z one equals eight minus 15. Over 3.2 equals negative 2.2 approximately, and for 12 we obtain two is equal to negative 0.9 for approximately now, we can re express the problem in terms of Z score probabilities or the probability the negative 2.19 is less than Z is less than negative 0.94 Or equivalently probability of Z less than negative 0.94 minus the probability Z is less than equal to negative 0.219 Now, because we have the problem expressed in terms of these probabilities for individuals, the scores, we can use a Z. Look up table to identify what these exact probabilities correspond to doing so, we find that This is equivalent to 0.1735 -0.0143, or our final solution of 0.1592.

We have a normal distribution with mean 15 and standard deviation 3.2. We want to find the probability that X lies between eight and 12 to approach this problem. More easily, we're going to think about probability in terms of Z scores, remember that a Z score is equal to the value of x minus the mean, divided by the standard deviation. So we can convert the bounds that we're considering here. Eight and 12 and disease courses follows. For eight we have Z one equals eight minus 15. Over 3.2 equals negative 2.2 approximately, and for 12 we obtain two is equal to negative 0.9 for approximately now, we can re express the problem in terms of Z score probabilities or the probability the negative 2.19 is less than Z is less than negative 0.94 Or equivalently probability of Z less than negative 0.94 minus the probability Z is less than equal to negative 0.219 Now, because we have the problem expressed in terms of these probabilities for individuals, the scores, we can use a Z. Look up table to identify what these exact probabilities correspond to doing so, we find that This is equivalent to 0.1735 -0.0143, or our final solution of 0.1592.

Hi. We are trying to find the area under the care giving. That's we have Ah, the group Freedom of 12. Andi, we have the critical very off three points 571 and went in one. So basically what you have to do as take this number on subsided from this number. So the answer is 0.99 minus point off.


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