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Quaston 9 (of 15)Award: 10 out of 10.00 pointsThe sun is 150 *106 km from the Earth: How long does it take for light to travel this distance?O 5.00 * 1050 5.00 * 10...

Question

Quaston 9 (of 15)Award: 10 out of 10.00 pointsThe sun is 150 *106 km from the Earth: How long does it take for light to travel this distance?O 5.00 * 1050 5.00 * 1045.00 * 1035.00 * 1020 5.00 * 101

Quaston 9 (of 15) Award: 10 out of 10.00 points The sun is 150 *106 km from the Earth: How long does it take for light to travel this distance? O 5.00 * 105 0 5.00 * 104 5.00 * 103 5.00 * 102 0 5.00 * 101



Answers

Light from the sun travels $1.50 \times 10^{8} \mathrm{~km}$ to reach the earth. How long does its journey take in minutes?

In this problem, given that the speed of light, C is equal to 186, Triple zero 186 triple zero AM I per second. Distance traveled as is equal to 9.3 multiplication. Then to the past seven am I. We have to calculate the value of time, so we all know a formula and that is time is equal to as by sea. So just putting the value here, I can write it as As is equal to 9.3 multiplication. 10 to the past seven am I By C is equal to 186. The politburo AM I pulse again. One simplification. Finally, I get the value of the age, 500 seconds, so this is our final answer for this problem.

Let's do not see as the speed of light. Now this means that the distance that is given Toby 1.5 times 10 to the part 11 send the middle. This is equal to speed off the light, Einstein. So the time can be calculated by dividing their distance. Let's see, not substituting the values. So the morning ran you off the speed of light. So that's what we're gonna use. That is three times tend to the bar eight. You talk for a second to convert the distance to meter on, then substitute off the values. We want the units to be consistent so the length of dimension off land should be seen. Now the unit off length should the same. I'm sorry. Now, substituting the values he find the time to be 500 seconds. Now the time for light across the diameter off parts of it will be twice this number. So why you Soft is 1000 seconds now the astronomical only Rome are found at the time. Let's do not Nash. So he calculated Oh, he didn't mind the time to be toting 100 seconds on what you found the time to be Hunt 1000 seconds. So this is a little bit less than the astronomic determination, but he got reasonably close, so yeah, on the tie intact you found over here. 500 seconds. This is nearly 1/4 of a 5000.3 minutes. The 1000 seconds is merely called to 16 points experience. Thank you.

So the distance, which is the distance from art to son, is equal to speed off light times the time taken by light to cover the distance to travel from the sun. To our this means that he will be equal to be overseas. My day is going to be 1.5 times 10 to the part 11 bitter and see that it's a speed off life, the modern value of speed off life. So that is three times 10 to the party ate meat up a second. Storing the consolation, you find the time to be 500 seconds. Therefore, the time for light to cross the diameter off its orbit is twice this number. So be cross this choice off the Stein and therefore this is equal to do 1000 seconds. Now, if you compare this time So the one that Ole Roan was measured. So that is 300 seconds, so d no, I'm more so the astronomical determine the time to be talking under seconds. Therefore, your calculation is less than his value. So you can say that although it's less but a letter Mars got reasonably close to the actual time. Thank you.

Today's question, we are going to find how long it takes for light to travel from the sun to the earth. In the question they give us one piece of information that is the distance between the sun and the earth, which is 1.4 96 times 10 to the eight kilometers, and they want to know what is the time it takes to travel this distance. So we're trying to find time to find this. We need one other piece of information and that is the speed of light because that is what is traveling from sun to earth. So we can find the speed of light in our textbook and it is given A C equals three times 10 to the eight meters per second. And so before we can solve for the time it takes for light to travel the given distance, we need to transfer either the distance into meters or the speed of light into kilometers. In this case, we're going to transfer a distance two kilometers from kilometres to and to do that we do 1.496 times 10 to the eight kilometers and multiply it by the conversion factor for kilometers two meters. So we know that there are one 1000 meters per kilometer and now we can cancel our units to show that we have just meters. So unit sort of the same in the numerator. And the denominator of a question given we're just multiplying or dividing can be cancelled out similarly to what we do in algebra. So now we have our units of meters. The next thing we need to do is find out the amount of time to do this. We need tohave the time or seconds in the numerator and seeing as ah, the speed of light is a constant. We can inverted and do one second turn three times 10 to the eight meters and similarly to what we did with kilometres, we could now cancel out our units of meters, leaving us with just seconds. So this gives us an answer of 400 and 98 0.9 meters. But because we only have one sigfig in our speed of light value, we will round that to 500 meters


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