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Give the equation for positron (ß+)emission from 187Pt, accompanied by emission of agamma ray. Include all mass numbers. Thanks!...

Question

Give the equation for positron (ß+)emission from 187Pt, accompanied by emission of agamma ray. Include all mass numbers. Thanks!

Give the equation for positron (ß+) emission from 187Pt, accompanied by emission of a gamma ray. Include all mass numbers. Thanks!



Answers

Write a balanced nuclear equation for a. Beta emission by $^{161} \mathrm{Tb}$ b. Alpha emission by $^{255} \mathrm{Lr}$
c. Electron capture by $^{67} \mathrm{Ga}$ d. Positron emission by $^{72} \mathrm{As}$

This question. Do you want to write down if your reaction creation for a decay off your in your own two feet for in tutorial? No. We are given that 80 case by an emission off alpha particle, and we know that the offer Pargo has a new cannibal. Four Proton above two. No, we just need to look up the purity table for the respective total numbers off your in you just to just 19. No, make sure that d brought on numbers left inside the right hand side are equal. Go for 92. That's correct. S where is for the nuclear number to the front left and she's your bus for and he's this direction.

For the first reaction, we have got a linea um 1 48 undergoing Alfa Mission. And in the process, something will be left over. The mass number of something else needs to add up four right here to 1 38 So it'll be 1 44 and then the atomic number needs to add up to 64 with the two that is already here. So it will be 62 and the element that has the atomic number of 62 is Samaria. Then we have strong tm 90 undergoing beta mission. When it commits, the beta particles in the product will also have amassed number 98. And in order to get 38 with the negative one, it will have an atomic number of 39 in the element within atomic number 39 is the atrium. In the last one, we have aluminum 25. I'm trying the mission. So in addition to the positron, the other element is going to have an atomic number. While mass number of 25 the positron has no mass at zero and it will have an atomic member with this one that needs to add up to 13 which will be 12. And the element that has an atomic member of 12 is magnesium

Let's write the balance Nuclear equations for the following a Let that be. That mission of 1 57 your opium atomic number 63 beta admission zero minus one e atomic numbers. D mass number stays the seam and atomic number 64 elements 64 his gavel any, um, for B, we've got the electron capture of 120. Burying 1 26 Very, um, 56 electron capture be 1 26 and this would be 55. That would be cesium for see Alfa Mission of said Miriam 1 46 and Miriam is 62 off emission 1 42 60 Neodymium and D positron emission of berry um 1 25 positron emission. Be this 1 25 55 in that element would be

Positron emission occurs when a proton in an unstable nuclear is converted into a neutron on babysitter. This neutron that was synthesized will remain in the nuclear's, contributing to no change in the mass number. Off the new daughter nucleus. However, the atomic number off the daughter nuclear's will be one less than the parent nucleus. Let's look at some examples to understand nuclear reactions. Positron emission arcas Big John Silicon, 26 has the atomic number 14. If this contributes to procedure, an admission because of process. John has a zero mass on a plus. One judge and is similar to a electron is symbolizing with the E. The only difference is going to be the positive on instead of the negative on in case off Elektrim. So to figure out the daughter nuclei that was synthesized in this admission process, we have to balance the mass numbers on the at the make numbers on the two sides of the reaction. Since a positron has a zero mass, the doctor nuclear synthesized has to have a mask off 26 to balance the mass numbers across the do sites and the atomic number off the daughter, nuclear has to be equal to 13. Don't, um, add up to 14 and equal that on the left hand side. So this corresponds to aluminum. If we look out the atomic number 13 on a pretty arctic table, you see that it corresponds to Al Verena. So this is the nuclear reaction off Silicon 26 to emit a positron. Let's look at no examples. Let's say we hadn't core board 54 with the atomic number 27. If this unleavened positron emission, it would also synthesize the daughter nucleus with the atomic mass 54. I'm sorry. Mass number 54 on the atomic number 26. When we look at the periodic table, we find out that the atomic number 26 corresponds to iron. So we see that the mass number on the two sides of the reaction are both equal to 54 and the atomic number on the two sides are equal to 27. Next the cat a couple of in reactions that said he had rubidium with the mass number off 77 in the atomic Mass 37. If this unleavened positron emission it was from a daughter nucleus. If the mass number 77 Onda. I don't make Mass. 36. This corresponds to Krypton. Finally, let's look at another example. Jordi um 93. Did the atomic mass quantified can contribute to positron emission by forming a daughter Nuclear's with the mass number 93 Onda at the MK number 44 at the MK number 44 corresponds to rhodium.


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