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SCC Chemistry 015 THE PRORLEM OF THE UNLABELED BOTTLES Nane:Set 1: KC1 AgNO;, Ba(NO;h. CuClz. d CuSOiWrite nct-ionic equations for cach of the possible reagenl Comb...

Question

SCC Chemistry 015 THE PRORLEM OF THE UNLABELED BOTTLES Nane:Set 1: KC1 AgNO;, Ba(NO;h. CuClz. d CuSOiWrite nct-ionic equations for cach of the possible reagenl Combinations in Set Comparc the products formcd with thc experimnental rcsults, and idcntify each reagcnt based On iheir chernical and physical properties_ Specify the identity of each unknown rcagent below and write the net-jonic equations that helped YQu in your identification,BotileIdentityNct-ionic Fqualions (Basis for identification)

SCC Chemistry 015 THE PRORLEM OF THE UNLABELED BOTTLES Nane: Set 1: KC1 AgNO;, Ba(NO;h. CuClz. d CuSOi Write nct-ionic equations for cach of the possible reagenl Combinations in Set Comparc the products formcd with thc experimnental rcsults, and idcntify each reagcnt based On iheir chernical and physical properties_ Specify the identity of each unknown rcagent below and write the net-jonic equations that helped YQu in your identification, Botile Identity Nct-ionic Fqualions (Basis for identification)



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The labels on three bottles containing different solutions have fallen off. The labels read "calcium nitrate", "hydrochloric acid" and "sodium carbonate". Describe how you would identify each solution by mixing them. Write the net ionic equation for any reactions you expect to observe.

Taking a look at general reactivity off our kids and all kinds in this podcast. So these sort of bonds are possible if we utilize the extra two p orbital's that we have present on our carbon atoms and so on. All keen is a double bond on an Al Qaeda is a triple bond. And here we're taking a look of some chemical transformations using an alky in structure. So our first chemical transformation we have h 30 plus in H 20 We generate alcohol structure. Next we have HBR hydrogen bromine. We have the edition about Brahman atom. Next, we have a L to h 20 generate the following product. Lastly, we have one more chemical transformation where, firstly, we treat with BH three and th and then our second start is H 202 on HR minus. What does yield is he following structure the primary alcohol

Mixture of this compound was prepared in that solution. The first one is given there to see you next three on five. As for for we are and the second one is Ceo and it's free All five We are correct. The number of moles of I and J R both have terrible yeah, In that two liter of solution. So modernity will be 0.01 and zero point by volume. So there is the correct option.

So here we are given a series of names. And what we'd like to do is construct some chemical formulas. So the first one we have for calcium carbonate is C. A. For calcium, C. 03 for carbonate. Following this, we're looking at magnesium hydroxide. So the metal MG for magnesium. Now we need three had we need to hydroxide to balance out the charges in the ionic species. Thanks. What we have is acetic acid. So we have CH33 C. 0. 2 H. Following this we have sodium hydroxide. Well we have A for the sodium metal O. H. For the hydroxide functionality. And lastly we have zinc oxide just said. And oh!

More clays in reactions. So you have this. See? It's three seats to sit too. Ask there. Reacting thiss finalist there. So of course we only have one nuclear file. That means the other one is going to be the electric file and full generate This 13 key to Esther is her product for bur starting with same nuclear filic us through reacting that with this ass turn. So actually, in this case, because they're asking for the clays in reaction thiss ethanol has to piece the leaving group which remains this acid 10 access. The nuclear file in this case will end with a 13 Dikky tone. Oh, for see? They're only giving us one product. So you're going to go ahead and guess this is either cycle ization or home A cupholder reaction. It's too much to see it too. So thankfully they did this Germinal dime Ethel substitution to limits our nuclear Philip Carbon Teo. Only one side, which is here. That means the other one is going to be Elektra file. So if account we have 12345 is going to be a five member drink on the five position we have our car venial for position. We have our general dime, Ethel. And on our one position, you have our us there for a d. We have a little smaller technically file correcting with this car. Vinnie ALS, Of course. This one has to be our electric file. Here's our new bond. Oh, look at that. So he generated some symmetric product, Mr Compounds. That's nice. You were starting off with a cyclic Esther, also known as a lack tone. Contracting with this s there. Of course, this is the only Alfa Carbon which has any protons. That's going to be the nuclear file attack. Kick off this group and we're ending with this 13 Esther Aldo Hide. Not sure if there's a specific name for that. That's pretty cool. Finally, f we have this cyclic key tone reacting with claro or throw for made. So it's called thiss chlorine on one side, a thaw CSI on the other side. No Alfa carbons here with any protons. So this is going to be our nuclear file. Of course, the other side is the same. So the question here is which of these two leaving groups is goingto leave chlorine is much better. Leaving group. That's the one that's gonna pop off and will generate this 13 key to us there. Great.


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