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7.) An electron is moving in uniform magnetic field. At the moment that its velocity is 2.50 x 105 m/s in the negative X-direction, and it experiences force of 3.25...

Question

7.) An electron is moving in uniform magnetic field. At the moment that its velocity is 2.50 x 105 m/s in the negative X-direction, and it experiences force of 3.25 x 10-14 N in the positive y-direction What are the x, Y, and z components of the magnetic field? If you do not have enough information t0 determine component, state that it is unknown.BxByBz

7.) An electron is moving in uniform magnetic field. At the moment that its velocity is 2.50 x 105 m/s in the negative X-direction, and it experiences force of 3.25 x 10-14 N in the positive y-direction What are the x, Y, and z components of the magnetic field? If you do not have enough information t0 determine component, state that it is unknown. Bx By Bz



Answers

A current I 5 15 A is directed along the positive x - axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.12 N/m acts on the conductor in the negative y - direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.

All right, let's consider a situation where we have a current I flowing in one direction and we have a magnetic field be orientated, perpendicular to the direction of that current. Ah, we were given that the force per unit length on the wire is point Black is 0.1 to Newton's per unit length, which in this will be meters. So this is basically f over length equals 0.12 so and what we want to figure out Oh, and our current has a value of 15 amps. So we want to figure out how strong this magnetic field is. Well, we can go to our force equation for a magnetic field with a current, and that is the current times the length of the wire times the strength of the magnetic field. So But if you notice over here we were given the F over l. So if we divide this l over here, we know that this is gonna be 0.12 equals the current times the strength of the magnetic field. So then, if we just divide the current off, the strength of our magnetic field is going to be equal to 0.12 divided by the current I, which is 15. You do that and we get the magnetic field has a strength of 0.8 Tesla's and that is your answer there.

Hello. This problem deals with a charged particle moving through a uniform magnetic field. And we just need to know our knowledge of forces on moving charges and a little bit of Newton's laws to figure out the direction the relative direction between the velocity of discharge particle and the magnetic field. So just drawing a, uh, diagram of what's happening we have will just same our magnetic fields. We're heading to the right like this, and it tells us that the direction between the magnetic field and the velocity is less than 90 degrees. So it might look something like this where we have our charged electron here will potable negative e there for description of the charge. And we could say Maybe it's heading, like up in this direction because then the angle between this velocity direction here and the magnetic field direction right be a factor here is gonna be less than 90. And so we just want to find that angle, Fada. But we remember from the textbook that the magnitude of the magnetic force being felt, um, by this charged particle is going to be equal to the absolute value of the charge of the particle velocity of the particle, the magnitude of the magnetic field to which the particles travelling and sine of the angle between the magnetic field, the velocity. That's the thing that we want to find that data. We are also told that this is the only force acting on this electron. That means that this force can be completely made up. Actually, this force completely makes up, then the net force acting on her object. And then if we know this is the Net force, then that's gonna also be equal to the mass of our electron times. Its acceleration and ratchet, given information about the acceleration of the object instead of the force on the subject, will want to use that. But we've given been given everything else. We know the charging electron. We know it's speed. We know the magnitude, the magnetic field, and we know the acceleration of the electron. We can also look up its mass from the Internet. So in the end, we just need to set these two things equal to each other and solve. Um, so we have a Q not the B sine veda is equal to m E times a so solving for theta. We see that it's the inverse sign of a big thinking. We have the mass of the electron times acceleration, divided by the charge of the electron, uh, times its velocity multiplied by the magnitude of the magnetic field. So let's plug all these things in what is the mass of an electron. It is 9.1 times 10 to the negative, 31 kilograms very tiny, multiplied by let's see its speed is given or its acceleration Sorry is given as 3.50 times, 10 to the 14 meters per second squared. So quite large electron is being accelerated quickly. We got a divide that by are absolutely I of the elementary charge 1.6 times 10 to the negative 19 Ghoulam's. Multiply that by the vocal speed given, which is 6.8 times 10 to the six meters per second and then the value of the magnetic field squeeze. This in here is 8.7 times 10 to the negative for Tesla's. So figure out what this ratio is. Take the Enver sign and we see in the end that the angle that this electron is traveling with respect to the neck Nick Field is about 19.7 degrees, and that is our answer

So let us right before us acting on the electron when the electron enters into the magnetic. So the force will be up. That will be equals two. You be be scientists time. No. From here we can write that scientist to Entity is equals two course divided by You. We be. So let us put the values here. In this equation. The force given his three 185 multiplied where 1034 of -16. Newton. You've heard it by the value of charts on electronic one point six. multiplied by 10 to the power of -19. Fulham Multiplied by the value of Velocity 6.8, multiplied by 1024 of six. 6.8 multiplied by 10 to the four of six m per second. Multiplied by the value of magnetic field is 8.7 8.7 multiplied where 10 to the power -4. Tesla minus 40 Islam. So after solving we can write Rita is equal to sine universe. My universe signing was Signing was zero 736 Or after solving, we will get to is equals two 19.7° 19 point 7°.. So this is going to be the required angle in this problem. Uh, and this is the angle made by the velocity of the electron with the magnetic. If you like this solution. Thank you very much.

This problem covers the concept of the a magnetic fools on a current carrying wire and the concept of the right and rule. So by using the right and rules, we can find the direction of the magnetic field, the forces acting along the uh negative Y axis and the current is along the positive X. Direction. Therefore the direction of the magnetic fig must be out of the page in the region. Okay, so let's find out the magnitude of the magnetic feed. So be easy cuba rental. Uh F. One L. Into one of them. I. Scientific. And in the direction of the Magnetic field and the current is 90°. We can eliminate this value since it has one. So B. Equals the first pollen Atlantis. Uh Zero point 12 Newton four metre. And the current in the wires 15 ampere. So the strength of the magnetic field is heat In to tenders -3 Tesla. Or you can see the magnetic field vector the is age in to tenders ministry Tesla along positive change direction are out of the page. Yeah.


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