5

Question 19CompleteMarkRSS RSS 5'ATGCATGCATGC CACAGTG 23bp ACAAAAACC ATACTTGCATAC TATGAACGTATG 3'TACGTACGTACGGTGTCAC-23bp _ TGTTTTTGG The schematic shows...

Question

Question 19CompleteMarkRSS RSS 5'ATGCATGCATGC CACAGTG 23bp ACAAAAACC ATACTTGCATAC TATGAACGTATG 3'TACGTACGTACGGTGTCAC-23bp _ TGTTTTTGG The schematic shows parts of V1 and DS gene segments that are going to be recombined as part of BCR gene rearrangement The partial sequence of RSS associated with V1 is also shown: The sequence of RSS associated with DS gene segment is not shown: Based on the schematic and the description which of the following options indicates the site(s) for RAG1/2 a

Question 19 Complete Mark RSS RSS 5'ATGCATGCATGC CACAGTG 23bp ACAAAAACC ATACTTGCATAC TATGAACGTATG 3'TACGTACGTACGGTGTCAC-23bp _ TGTTTTTGG The schematic shows parts of V1 and DS gene segments that are going to be recombined as part of BCR gene rearrangement The partial sequence of RSS associated with V1 is also shown: The sequence of RSS associated with DS gene segment is not shown: Based on the schematic and the description which of the following options indicates the site(s) for RAG1/2 activity? Flag questian Select one: Either A or C Either A or B Either B or C Provided information NOT enough to answer this question out 0f



Answers

A contig map of one segment of chromosome 3 of Arabidopsis is shown as follows. (a) If an EST hybridizes with genomic clones $C, D,$ and $\mathrm{E},$ but not with the other clones, in which segment of chromosome 3 is the EST located? (b) If a clone of gene $A R A$ hybridizes only with genomic clones $C$ and $D,$ in which chromosome segment is the gene located? (c) If a restriction fragment hybridizes with only one of the genomic clones shown above, in which chromosome segment(s) could the fragment be located?

In here us that the DNA is derived from a middle of a city and a loan of a 1,000,000 protein. So it asked us if we can determine that amino acid sequence of this portion of protein. So essentially it is not going to be possible due to the fact that from the information that we're given, we cannot determine the amino acid sequence here because of the three reading frames, all of which do not contain a start code on here. And that's the reason why we cannot tell anything about this particular sequence. Um, and that's going to be for part B. For part eight. Ask what's the sequence of DNA? And that's used in the sequencing reaction shown here. So we have four legs that show the products of sequencing reactions that contained the DDG D D A and DDT, which are video nucleotides, which are used in singer sequencing on Essentially in orderto determined the sequence itself. We look at what DeOssie died, the oxy I'm nucleotide that to be used for example, G g a. T versi here, and essentially whatever is gonna end up at the last year is going to be the sequence. So we go from bottom top in this particular case,

Hello everyone. Welcome to chapter 10 for the question number nine. Here we have two questions A. And B. First of all let's look at part one. The D. N. A sequence from its fine end to three and is right starting from the bottom of the jail Where the smallest d. a fragments mega rate each band results from the incorporation of the appropriate eight the D. U. S. Nuclear tides try false fate. And as expected there were no two bands that have the same mobility. This allows one to determine the D. N. A. Sequence by reading of the bands in strict order, proceeding upward from the bottom of the jail and assigning the correct nuclear tied according to which lane the band is in the nucleotide sequence of the top. Dead. Okay. Was behind the directly from the data of figure in question # nine and the bottoms dried was deduced from the complementary base pairing roots. So much for the question eight let's come to be the D. N. A. Sequence can then be translated into an immuno acid sequence using the genetic code. However there were two strengths of the A. That could be transcribed into R. N. A. And three possible reading frames for each spread. Thus there are six you know essayed sequences that can be in principle be encoded by this stretch of the A. Of the three reading frames possible from the top. Instead only one is not interrupted by a stop Carden From the bottoms. Just two of the three reading frames also have stop cordons. The third frame gives the following sequence. Now look at this sequence. It is not possible from the information given to tell which of the two open reading frames can response to the actual pertain encoded by the stretch of the age. What additional experiment could distinguish between these two possibilities. So much for this. Thank you for listening.

So this question that we're looking at a gene with three insurance and we're hybridizing it ones are Luke Teoh during so under Arctic conditions, we have one strands that becomes our our loop. So let this be the our loot. Any other strands hybridize It's So we have it's trends and then we have it's compliment there. Yeah, it's as a compliment. And this this is SBT transcripts. Okay, so that's part a. This is what it looks like when they hybridize is on. Then for pop be not the we Are I slicing it, isolating it from we put raw prisms and looking at sits curing excision he wants to have look at when cytoplasmic remember names used. Okay, so way have instead of one big loop, we have small lips. We'll have one peach. Excellent. So there's the first Excellent on. And here's the first Intron Second X own a second room, both excellent, but in front on before Faxon and the other strands way a suit how firstly, in from work bonds back another look for it disconnects and of intron never leave repeats and then it bonds back. Okay, just doesn't make a huge amount of sense. And so we puts in b of a strands the compliment we have thus Dixon, second X on this m four. So as you can see the complementary strands Yes, uh, bypasses all the inference. Inference aren't included in our memoranda here. I m a runny and these disconnected parts here arms. So wherever the government's is bound, hit is an excellent or if we have these loops where the Enron isn't, bones is an intra.

Hi. There s O a lot of this problem you're gonna have to refer your textbook to see there is, um, not the picture, basically of the grap indicating the values that I'll be talking about here. But I thought that it's pretty easy to look at, right. The one that you're looking at is right underneath the problem that says mutation and sequence and mm absence and mm mm present. Um, from that we're gonna move on the let's. Okay, let's start out with, like, basically the set up of the problem. So you're looking for the operation called M M N. It has four sequences A, B, C and D, and it encodes to m sides one and two for this, right? The mutations in this sequence, um, have the effects of, like, a plus sign where that indicates that an enzyme and synthesized and a minus sign indicates which indicates that there is non enzyme synthesized on dso were given to questions. Basically, one of them is asking if it's induce a ble or festival. The operation, I mean and then be asked you to identify the regulator gene, the promoter structural gene for enzyme one and I'm sorry. The structural gene for enzyme to All right. So we're going to go through and talk about some of these, so I'm gonna put over a green dot over basically everything that's important. Um, we're going to start with a So the answer is that M m M is a repressive ble opera on. Um, I like to type things out. You need to pause, go slower. Whatever you need to do, it's totally fine with me. Um, but this way you can kind of have some notes to go on while at the same time, I'm going to further explain vocally, Uh, basically, where there's no mutation. Thean enzymes are synthesized in the absence of Mm mm. Whereas in the presence of mm. In the end, times are not synthesized. We can conclude from that that this operation on can act as a oppressor or co repressive who repress the opera on. So, in absence of mm mm, the operation is active. When? When there's the operation, is there? I mean, where there is? Mm mm. The opera on is repressed. So we know it's a repressive Alaa Peron. Yea, So moving on part B. So this one. There's a little bit more fun, in my opinion, basically trying to fill in the blank. Always a fun part of biology. So it starts out with the regulator gene, which I put as e I know. It's so exciting. In the case of the B mutation, there is, um, Constitutive Expression Constitutive Excuse me. Expression of enzymes one and two. This means that B is a regulatory gene. Okay, A mutation and regulatory gene does not allow the binding of a repress er to bind to that Be jean. This allows for conservative expression and the genes that are transcribed even in the process of eminent. So next up, we have to talk about Promoter de which basically the question was, What's the promoter? And then you put deep. And then if you want to understand why you say in case of de mutation, we see that the end times are not synthesized both in the presence and absence of mm. Remember, M m m is a repressive all opera on. Um, this means that there's a mutation in the promoter. It does not allow the binding of the RNA promoter being deep, by the way, allow the binding of RNA polymerase two promoter and hence there is no transcription of genes even in the absence of nml. So he is really important. Remember that it is the promoter moving on. So it asks you the structural gene for enzyme one. It's a so exciting. In the case of a mutation, we see that the end time to is synthesized and someone is not synthesized in absence of Mm mm. That operation that's irrepressible. This indicates that a code for NZ in one, um in the case for structural gene for the enzyme to it. See which, in case of C mutation, we see that the enzyme oneness synthesized but enzyme to is not synthesized in the absence of feminine. This indicates that c codes for enzyme to So, um, it's important to understand the concepts here, but it worked through some more problems like this. If you're still a little confused, you just want to be able to identify the regulatory gene, the promoter and the structural genes for the enzymes you're working with and whether or not it's repressive ble or an inhibitor. Anyway, um, I hope that, like helps you understand why this is important because this is kind of how we figure out how to design experiments, for one thing, and then just like understanding how enzymes synthesize is very important.


Similar Solved Questions

5 answers
Point) LetA =5] and B =Find the matrix C of the linear transformation T(z) = B(A()).
point) Let A = 5] and B = Find the matrix C of the linear transformation T(z) = B(A())....
5 answers
A chemical reaction occurring in a cylinder equipped with moveable piston If the cylinder contains 0.130 mol of gas before the produces 0.621 mol of a gas: what is its volume after the reaction? reaction and had an initial volume of 2.18L7 Assume constant temperature and pressure and that the initial amount of gas completely reacts: -
A chemical reaction occurring in a cylinder equipped with moveable piston If the cylinder contains 0.130 mol of gas before the produces 0.621 mol of a gas: what is its volume after the reaction? reaction and had an initial volume of 2.18L7 Assume constant temperature and pressure and that the initia...
5 answers
How many molHOX a needed 01 neutaze 6,5 TL360 M 9
How many mol HOX a needed 01 neutaze 6,5 TL 360 M 9...
5 answers
Metitc epacesProblems Let (X,d) be mnetric space: Define e : X x x _R by e(z, y) min{1, d(, 9)}, V €,y € X Prove that e is a metric on X
Metitc epaces Problems Let (X,d) be mnetric space: Define e : X x x _R by e(z, y) min{1, d(, 9)}, V €,y € X Prove that e is a metric on X...
5 answers
UUsing Normal Distributions the specified normal In Exercises 39-44,answer the questions about distribution 39. Heights of Women 20-29), the mean survey height was 64 of women in the United States (ages inches inches with standard deviation 0f 2.71 (Adapted from National Center for Health Statistics) What height represents the 9Sth percentile? (6) What height represents the first quartile?
UUsing Normal Distributions the specified normal In Exercises 39-44,answer the questions about distribution 39. Heights of Women 20-29), the mean survey height was 64 of women in the United States (ages inches inches with standard deviation 0f 2.71 (Adapted from National Center for Health Statistic...
5 answers
Wlat bup For nonempty sets A,B € R,determine which of the following statements are tue. Prove the true statements and give a counterexample for those that are false: sup(A 0 B) < inf{sup(A) sup(B)} sup(A 0 B) = inf{sup(A), sup(B)}- Sup(A U B) > sup{sup(A), sup(B)}. Sup(A U B) = sup{sup(A), sup(B)}
Wlat bup For nonempty sets A,B € R,determine which of the following statements are tue. Prove the true statements and give a counterexample for those that are false: sup(A 0 B) < inf{sup(A) sup(B)} sup(A 0 B) = inf{sup(A), sup(B)}- Sup(A U B) > sup{sup(A), sup(B)}. Sup(A U B) = sup{sup...
5 answers
Would requiremolecules of Hz to fully reduce a molecule of:
would require molecules of Hz to fully reduce a molecule of:...
5 answers
UTEoGAoldne mahu
uTEo G Aold ne mahu...
5 answers
0 Sr(CIO3)2 EONX CaBr2 NHACl 2 Which answers of the I salts will not produce produce basic basic solution solution when dissolved in Water?
0 Sr(CIO3)2 EONX CaBr2 NHACl 2 Which answers of the I salts will not produce produce basic basic solution solution when dissolved in Water?...
5 answers
20 /20Sckilde gosterildgi gibi L=] (n)uzunlugunda "5 0 | (g) kutleli homojen bir cubuk ortasindan donebilecek sekildc sabitlenmistir Cubugun Iki ucunda K560 (Nlm) sabitli iku yay baghdr Yaylann dger uclan sabitlenmistir ve yaylar Uzam amni; haldedir Cubuk denge konumundan 0 < Olacak sekila de dondurulup scrbest biraklyor Cubugun acusal frckans] kac (rads) dir? g = 10 (m/s? )A) 10B) 12C)ISDBOE) 60
20 /20 Sckilde gosterildgi gibi L=] (n)uzunlugunda "5 0 | (g) kutleli homojen bir cubuk ortasindan donebilecek sekildc sabitlenmistir Cubugun Iki ucunda K560 (Nlm) sabitli iku yay baghdr Yaylann dger uclan sabitlenmistir ve yaylar Uzam amni; haldedir Cubuk denge konumundan 0 < Olacak sek...
5 answers
Sketch the graph of f by hand and use your sketch flnd the absolute and local maxlmum and mlnimum values of f (Enter Your answers fx) = > X2Kmnlne~separated Ilst: If an ansrier does not exlst; enter DNE: )absolute maximum valueabsolute minlmum valueDNEmaximum value(s)DNElocal mInlmum value(s)DNE
Sketch the graph of f by hand and use your sketch flnd the absolute and local maxlmum and mlnimum values of f (Enter Your answers fx) = > X2 Kmnlne ~separated Ilst: If an ansrier does not exlst; enter DNE: ) absolute maximum value absolute minlmum value DNE maximum value(s) DNE local mInlmum valu...
5 answers
(ModuloElectric Cumant ard ElotncExercite 27.15{90t70Canatndudon Fom 4araiuur (Fquu Whal eed % 0l |SorICh mIPanter_IOAEaetatFen{rm A 68sntBaa_4 AnimPen @DELLmalertcdmallcnGrotatloLCLSEntom40BTD 54 plItoudteUtrFcHhan AaSurnlrteu AntalMarnat; 1n #aun; 5 Arannctt neneinttaOuemPiote Fecdoack
(Modulo Electric Cumant ard Elotnc Exercite 27.15 {90t70 Canat ndudon Fom 4araiuur (Fquu Whal eed % 0l |SorICh mI Pante r_IOAEaetat Fen{rm A 68 snt Baa_4 Anim Pen @ DELL malertcdmallcn Grotatlo LCLSEntom40B TD 54 plIt oudte Utr Fc Hhan Aa Surnl rteu Antal Marnat; 1n #aun; 5 Arannctt neneintta Ouem P...
5 answers
If a human cell is undergoing fermentation, what is the final product that is produced?PyruvateAlcoholGlucoseLactic acid
If a human cell is undergoing fermentation, what is the final product that is produced? Pyruvate Alcohol Glucose Lactic acid...
5 answers
3 (ZOpts) Use the Laplace transform to solve: y" + 4y = 9(t), %(0) = 0,y (0) = 2,and f 0, 0 < t < 3, g(t) = t _ 3, t23.
3 (ZOpts) Use the Laplace transform to solve: y" + 4y = 9(t), %(0) = 0,y (0) = 2,and f 0, 0 < t < 3, g(t) = t _ 3, t23....

-- 0.022270--