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What is the value of the battery24TA 4 0<13Q20 V302240...

Question

What is the value of the battery24TA 4 0<13Q20 V302240

What is the value of the battery 24 TA 4 0 <13Q 20 V 30 22 40



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A battery charger delivers a current of $3.0 \mathrm{A}$ for $4.0 \mathrm{h}$ to a $12-\mathrm{V}$ storage battery. What is the total charge that passes through the battery in that time?

Hi. In the given problems, the circuit diagram is having first of all, our battery off emer sixfold. Then there are few resistors. The first, less disturbed, is having a resistance off six home, then in series with it, there is another resistance off, then home, then to own and join with negative dominance off the battery. This is four on and finally this cares eight armed resistance. Now there is one more branch off this circuit having a resistance off eight home, then the third branch having a resistance off six home. We are seeing this third branches the second branch. We need this having a 200 sister and one more branch as a diagonal. Off this the single which is having a resistance off eight home. And finally, this is another diagnosed with another rectangular loop, having a resistance value off six home. So finally, if we have to find the equally violent resistance off this combination, so we will do it in steps. So first of all, these two sisters having channel and two on values are in series. So as and home and to resistors Uh um Si es So they're never assistance, maybe 10 left to on means to say, This is 12 home now the 12 arm is in parallel with this six own. I live six on resistor. So no, the net value office parallel combination net present stance We'd be given by a formula, the product off the two resistors in Liberator and divided by the sum off these two resistors when only to resist Russell joint in parallel. We can use this shortcut. It becomes 72 divided by it is which comes out of the or home. Now this four own the net combination off these leaders is just which comes out to be four on This is in series with eight on So again bite. No, it's four arm is his CVS eight own resistors giving the next resistance off. Eight Loves four Leave 12 Warm again. Now the swell on. Overall, this drill home is M Baron with this six home again. Now his well, all is in parallel with six old, so their necklace instances again given by 22 6 divided by 12 last six. So it comes out to be call on again. Now this four on is in Siri's with this forum. It's called on is in CDs with a never forum getting our net resistance value off eight. Now the eight Omen is in parallel with eight, um, about a little bit, another eight on So their next resistance now is eight on Divided by two as an few identical resistors are joined in parallel, the next resistance consult Toby equal to the resistance value off one resistance, divided by the number of prices first. So here it comes out, Toby. For on finally, this four on is now this four ohm resistor is in Siris with six on resistor. Now the sport on Seles with our six home registered giving our necklace suspense or six own plus four means and home. And finally, this then on is in parallel with this eight home. Finally, this stand arm is in parallel Big eight home Yes, equally. Rent resistance off the circuit is given hands, then multiplied by eight. If I could buy 10 plus eight oh, or you can see are equivalent was toe 80 by 18 on. Hence, the current being taken out of the battery in the circuit is given by home slow as absolute by our equivalent perhaps elements the evening for the battery Waas sixfold and our equivalent, We have found us 50 by 18 Home Consult Toby six into 18, divided by 18. And here. Or you can see the current coming out of the factory is human Azman wine 35 and fear. I think this is the answer for the given problem. Thank you.

So this is the circuit and I have Jews in the currents are shown in the sty. Graham. Now let's apply Coach of function, drool, disjunction. We're old, the currents meet So from back they get I go to the equal Do I want less? I three Now let's apply new rule. So these two loops. So I'm taking for the force, Luke. I'm choosing the direction, Toby. Like so And for the second Lopez Well, I'm just in the direction toe we gotta block weighs now. Ah, plane blew through into the first slope. I have some going opposite to the direction off current at our three. So this is the circuit and I have Jews in the currents as shown in the Steiger. Now let's apply Coach of Functions rule the disjunction where all the currents meet From back the gate I tow to buy three artery Then I'm going along the direction off cunning that are one. So I have negative I want our one and I'm going positive to negative inside the factory. So I have negative even that it's a quick aceto. Similarly, for the second No, I'm going negative to positive inside the battery So I have plus E to and I'm going along the direction off current at our two so minus I don't talkto so I have less I three artery then I'm going along the direction off cunning that are one. So I have negative I want our one and I'm going positive to negative inside the factory. So I have negative even that it's a quick Placido. Similarly, for the second look, I'm going negative to positive inside the battery So I have plus e to and I'm going along the reduction off current at our tree say again minus our three tree artery equal cassio Now if there is no current in flowing through back everyone, this means that I won should be equal Stra Zito on this means that I do is a cold Oh, I tree I would like to happen So the substitute Oops So we saw these two questions with our one equally do 10 homes on our two equal do 20 bones on DDE Let's do that So we have and I'm going along the reduction off current at our tree say again minus r i tree are clean equal to zero Now if There is no current in flowing through battery one. This means that I won should be equal insta Zito And this means that I do is a goto I tree I would like to happen of I told our two minus he want to be called a zero for the forced to question this one on applying these Ondo this ruling Over here we have e to minus toe I do are two equal dizzy because they're equal jobs mso we substitute Oops. So we saw these two questions with our one equally do then homes and our toe equal to 20 homes on DDE It's still back. So we had in the steak over hell. So this is actually our tree And here I have I to are to bless our tree because I do Is he going Do I tree but are too is not a cold, dry tree. So don't make the mistake that I didn't know So now we saw these two equations So let's first things The simplistic question the force of I told our two minus he want to be called a zero for the forced to question this one on applying these Ondo this ruling Over here we have Ito minus two. I do are two equal dizzy because they're equal. Opps a Madonna and express I do in God himself e one on our tree. So that will give us in the second question you want over our three times arto bless our tree to be called Stasio. So I'm just a mistake over here. So this is actually our tree. And here I have I to are to bless our tree because I do. Is he going? Do I tree, but are too is not a cold, dry tree. So don't make the mistake that I didn't know. So now we saw these two equations. So let's first things The simplistic question the 1st 1 and express I do in God himself e one and arteries in that equation. I mean, move on to the next base. I got Italy to be equal to anyone. Times are toe over our three plus one. So from here, we can solve for our tree. So we have Otto over our three press one to be equal to over even. And hence a tree will be equal to are to always a two over even minus one on. We're already provided with the value off are too. So that is going to be 20 owns on then even and Ito ARJ 20 and 50 bulls respectively. So I have a date simplifying that a question. Let me move on to the next base. I got Italy to be equal to anyone. Times are toe over our tree. Bless one. So from here, we can solve for our tree. So we have Otto over our three press one to be equal to over Even from hence, our tree will be equal to are too always a two over, even minus one on. We're already provided with the value off are too So that is given life on this Gives our tree till the equal do 13 point three rooms. Thanks. Thank you. The 20 owns Oops on then even and Ito ARJ 20 and 50 bulls respectively. So I have 50

So in order to find the voltage difference. First we need to find all the currents I one eye to an eye tree on. We do so by using questions 27.18 through 27.20 So using these three questions refined Ivan, I do and I treat on Those are basically called through these three expressions and then we plug or substitute all the values that are needed and fine. I want to be 0.275 appear. I tow is equal to 0.255 years and I become so Toby Negative. Sit up. Going to five Ciro Amperes. Now that we have the three currents we can find, the world is difference. VD minus vz by taking the friend parts. So here I have given two examples are basically two questions. So we can either use this equation the 1st 1 on Duh. So this one and find really minus V c to be called toe I two times out with and substitute the values on dhe find disorders difference, Toby. Plus their 20.25 months all we can use this a question on find video minus V C in storms off by three artery and the E. M f. And we get the same results that way as well. So it's up to you whichever of my third or whichever route you want to choose. But the answer should come out to be saying I must be quite a 0.5 force.

We are considering the circuit that is shown with resistance is Andy Mfc um that are given. And we want to figure out what is the voltage difference between points D. And C. And the voltage difference across. Sorry, between points D and C. Is just going to be equal to the voltage drop across the resistor to Which is going to be given by current I two times resistor. R two of my owns law. So in order to figure out and answer this question, we need to figure out what the current I two is so that we can then use that to figure out the voltage. So in order to do this we need to use Kirk offers laws and right some expressions for the loops. So for the right side loop I'm going to make a circle and we end up with EMF two Plus I two R 2 Plus I three R 3 Is equal to zero. For the left hand loop, We end up with -13 R three Plus I one R 1 -8F 1 is equal to zero for the big loop because I may as well write everything out now we end up with -8F 1 plus EMF two Plus I two. R 2 plus I one R one equals zero. And using the junction rule we get that current I two. I'm using the junction rule at point D current I two is equal to my one plus I three. So we have plenty of equations here to be able to solve for what we need. Um and so it's going to just be a lot of algebra from here on out. The first thing that I did to solve was to plug in the current into the left hand loop. So I solved the current equation for I won and got that I one is equal to I two minus I. Three and then we can put that into our left hand loop, which was the second one we wrote here and that will allow us to rewrite the second hand loop in terms of I ones and I two's um once I do that I then solve that second hand loop or sorry that left hand loop for I three and get the I three is equal to I two times R one minus E M F one, All divided by our three plus are one. Now that we have this expression for I three. I plugged that expression into the right hand loop. So I plugged this I three in up here. So now in the right hand loop we would have only I two is our unknown. You can solve for I too and you should get that I too will be equal to I didn't simplify it. So I ended up with I two being equal to E M F one R three divided by R one plus R three minus IMF too. All divided by R two plus R one R 3 Over R one Plus R three. So pretty messy. But when you plug that into the calculator you should get 1/40 or 0.25 amps as the current. And then of course we can use that current back up here, multiply by our two and get that the voltage that we're interested in is Equal to 0.25V.


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