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Zou Aym JO Aym {JSIDAUI LE JABY J szoavodajuI $,*4EH 3J*15 sea Jo12q1#N 08 02 09 05 07 OE Oz 011 0F 1 5 09 2 6 08uoqjung J41 [[E3 `Mopq 4der? J41 4! pazueuuns a1 EJEP J4L 'PIIA JO sapads pajaBuepua ue JOJ {81qEY [EJOL & BuJuiaJuo) EIep papa[[o We3} YPE3S31V (L

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Given $A(4,1), B(1,5),$ and $C(0,1) . S$ and $T$ are translations. $S :(x, y) \rightarrow(x+1, y+4)$ and $T :(x, y) \rightarrow(x+3, y-1) .$ Draw $\triangle A B C$ and its images under $S \circ T$ and $T \circ S$ .
a. Does $S \circ T$ appear to be a translation?
b. Is $S \circ T$ equal to $T \circ S$ ?
c. $S \circ T :(x, y) \rightarrow$$(\underline{?}, \underline{?})$ and $T \circ S :(x, y) \rightarrow(\longrightarrow, \underline{?})$

So we're told in 1915 the temperature was 13.5°C.. And we were also told that the the temperature has risen at a constant rate of .032°C per year. So in part they were going to try and find an equation um t of why, which gives us the temperature after some amount of years from 1915, so that Y is equal to zero, that corresponds to the year 1915. So the slope for this equation is going to be equal to the rise in temperature per year. So that's gonna be equal 2.032. And the reason for this is because after one year or at y is equal to zero, will have risen point oh 32 degrees Celsius at two years will have risen two times point out 32 degrees Celsius and so on. So this is going to be our um slope value. And so now we can say our equation T of Y is equal two point oh 32 times Y plus some constant be. And to find this constant be. We're just going to plug in the point that we were given which was 1915. Kama 13.5. But we're also told that why is equal to zero corresponds to the year 1915. So we're going to plug in, why is equal to zero and 13.5 is equal to t. So 13.5 It's equal 2.32 time zero plus B. And 0.32 times zero is just zero. So 13.5 is equal to be so we can plug this into our B value. And we'll have found our equation which gives us the temperature after why years. So T of Y is equal 2.32. Why? Plus 13.5. And for part B, what we're going to try and find is what the temperature is according to our model in the year 2010, And so since Y is equal to zero corresponds to 1915, we're going to have to -1915 to this 2010. To figure out the year that corresponds are the Y value that corresponds to the year 2010. So why is equal to 2010 plus or minus 1915? Which is equal to 95? So the Y value Equal to 95 corresponds to the year 2010. So you can plug in 95 for why? And we get .32 times 95 Plus 13.5. And so this this part of our equation will give us the amount of degrees that it has risen since the year 30 or 1915, and this obviously is the temperature in 1915. So this will give us the temperature In 2010, and so this is equal to 3.4 Plus 13.5, which is then equal to 16.54. So the temperature in 2000 and 10 in degrees Celsius would be 16.54 degrees Celsius, according to our model, that we found in part a.

Hello and welcome to this video solution of numerous. Here we are given a link comprehension. So here in statement one were given that and iron or a on roasting with sodium carbonate and lying in the presence of air gives to compound PNC. And you're from option the second part the solution be in concentrated. It's alan reaction with production furrows and it gives a blue color on precipitated of compound their cost solution of C. On treatment with considerate statistical gives a yellow colored compound E. And the compound even treat it with a seal gives an orange red compound F. Which is used as an ox raise anything. So you have to make certain predictions to come into the solution. So let me show you how it's made. So first of all we take for if he oh she had to poetry thus eight and a two freedom global neck And with air that is given seven or 2 good line gives you to a free two or three that's eight the name so Seattle four. That's it. It's a frustration. Next we have if we two or three reacting with concentrate sales that is given gives you who official three Last three H 2. Right now this official tree reacts with who before if he 10 6 that is protection fellow sign a great this gives you the blue solution pushing blue solution of if the four if he CN six whole trade plus 12 cases. Mm Next From three we have two any he wanted to see our well for That's 8/10 of food gives you we need to the odd 47 is the yellow color solution. Greatness in A. Two so four. That's it too. No you have in A to see our two or seven. Okay, last case here is the orange color substance of people pr two or seven that's 2010. So this is the so let us state what is A what is B. The first we have me is If you see a 23, this is a Next we have every two or 3 SCB or Yes. So this suits also be ready And in in 204 this is C. Right BNC. That is mentioned. Yes. Now this pushing blue books. Mhm. Yeah. Yeah. Whoa it is. Mhm. Okay. To see again this election with the this one your local er this is E and we have orange. What are some common? It does if Yeah. Right. I hope this is clear to you and have a very good rest of the day. Thank you.

We're going to find the component forms um going from .12.2. So each time we'll be taking our second point and subtracting the corresponding component from the first. So for our first factor we would consider that we do negative four minus negative six and a negative one minus negative. To notice those minus negatives end up being adding. So we get 2 to 1. So it can either be written with the brackets or we can write it in R I. J form which would be to I plus one J. And I don't have to write the one. If you just see the J. You know that there's a one there Kate. Now our next vector notice every single time we're going to be doing negative 1 0. Well this is already in kind of its component form because its origination is at zero. So we can really write our vector as just the negative 161 And if we write an I. J and k notation we could have a negative I plus six, J plus K. Now our third we'll have to a nine minus four A one minus one and a negative three minus negative three. So in the end I have no J and K. So in the notation that I've already written with brackets you would actually place in a zero where there are, you know, um no components of that form. But when you go to write it in I. J and K, you just write that as five A. If you don't write the J and K component, then it's known that those are zero.

Hello and welcome to this video solution of numerous. Here we are given the rules of silver and copper are constantly reducing their scalability in So we have got option A. S case in which is the correct option. Now using the in the Synod process, what we do is okay let's let's try to find out what in what is happening in case of signing process. So let us take the Argentina, which is a G two S. Plus. We have Casey in now for this occasion this gives us a complex of silver. This is okay, ain't you? Him two plus it works now. This compound that is formed is soluble in the solution. He's so little now this is thing for copper also. Thus we can have a quick and select option skc I hope this is clear to you and have a very good thank you.


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