Part a serpent calculating the partial pressure of B R two initial, which is I defined us. We used the ideal gas law and Artie over V plugging her values. 0.974 contrary to six meters per atmospheres. Mole Kelvin temperature is 1000 Calvin over 1.0 leaders and a pressure would be 79.9 atmospheres initially, but also for the partial pressure of H two. And we're told that starting with 1.22 more, 28 to 06 leaders per atmospheres. Mole Kelvin 1000 Calvin 1.0 is your leaders that would be equal to 100 atmospheres Using this, let's set up a nice table each to guests, beer to guests, equilibrium with to h p r. We use their partial pressures initial from up above. We found that each to was 100 br to a 79.90 computer rice table. Let's define our kee p expression KP expression. Partial pressure of h B. R squared over the partial pressure of each two times a partial pressure br two. We're told that the liberal constant is 2.1 times 10 to the sixth two x squared over, uh, 3 100 minus x 79.9 minus X. Solving this quadratic equation will yield to roots. X would be equal to 100 and 79.9. We're gonna reject this route here. And if we go back to our ice table, the partial pressure of H two at equilibrium is going to be 100 minus 79.9, which is going to give us 20.1 atmospheres. The partial pressure of B R. Two at equilibrium would be 79.9 minus acts which 79.9, which would be zero. In the partial pressure, HBR at equilibrium would be two times X, which will yield 159.8 atmospheres at equilibrium for part B. Let's look at what one of the following changes will I for the equal of impart a Each of the following changes will increase the partial pressure of HBR. Choose the change that will cause the greatest increase on expenditure choice. So for part B, all three of these increase the partial pressure of h p. R. So if we great start by writing or equilibrium and we're told that it is XO thermic and XO thermic to each PR, I guess. And excellent. Eric, by back to the original question. 107.7. Kill a Jules. So we've got three changes that are going to take place. Uh, we could either, um, if we increase so change one is add one more 10.1 mole of each to so 0.10 Moeller of each to going up, or that's changed. One change too, is 0.10 Moeller of beer to increase and change three is to decrease the temperature, which would cause a shift. Now, all three of these cause a shift here temperature goes down. Uh, from initial temperature is 1000 to 700 a decrease of 300. Calvin, uh, decrease. So going from 1000 kelvin to 700 Calvin the one that's going to cause the greatest increase of HBR because we're focusing on this one here would be changed. Number three. A decrease in temperature would really causes equilibrium shift towards the products, adding an equal 30.1 miles of age to our adding 0.1 moles of B R two that would cause the seam increase towards the rate. So the one that's gonna cause the greatest increase towards the rate would be the decrease in temperature with which would cause the increase in.