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Question 18 Not yet answered Points out of 7.00Nitrosyl bromide reacts according to the equation; 2NOBr(g) 2NO(g) Brz(g) . Initially; 2.00 atm of NOBr is added to a...

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Question 18 Not yet answered Points out of 7.00Nitrosyl bromide reacts according to the equation; 2NOBr(g) 2NO(g) Brz(g) . Initially; 2.00 atm of NOBr is added to an reactor: At equilibrium, empty NOBr the partial pressure of is 1.82 atm. Calculate constant for the the equilibrium reaction.Flag questionAnswer:

Question 18 Not yet answered Points out of 7.00 Nitrosyl bromide reacts according to the equation; 2NOBr(g) 2NO(g) Brz(g) . Initially; 2.00 atm of NOBr is added to an reactor: At equilibrium, empty NOBr the partial pressure of is 1.82 atm. Calculate constant for the the equilibrium reaction. Flag question Answer:



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A sample of nitrosyl bromide (NOBr) decomposes according to the equation $$ 2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) $$ An equilibrium mixture in a 5.00-L vessel at $100^{\circ} \mathrm{C}$ contains $3.22 \mathrm{~g}$ of $\mathrm{NOBr}, 3.08 \mathrm{~g}$ of $\mathrm{NO}$, and $4.19 \mathrm{~g}$ of $\mathrm{Br}_{2}$. (a) Calculate $K_{c}$. (b) What is the total pressure exerted by the mixture of gases?

So in this problem, we're given a reaction off the decomposition off an O b. R, which is not wrestle bromide which decomposes to give us nitric oxide and Brahmins. So we're given the volume of the reaction has cell as five points here later. Then we given the temperature of the reaction as 100 degrees C which in Calvin's scale will be 2 73 73 Kelvin and we're given the mass off each of the component here for in all b r the masses triple into to Graham for in all also decide the equally were massive. So for in order to grow amasses three punt oId graham and for bro mean the massive for when one in Graham is they could be a mess. So these are the data which given industry ation. So in first part of this problem, we have to find out the equilibrium, constant expression, Casey for destruction. So as they know that if you write down, they could be a constant expression forthis creation will, right. So, as you know, the decree from consciousness in the numerator contains the concentration of the products so the product is, and when we have to and on. That means two will be as a power off in all. And then we have bro means that this is the broom in concentration and in the in the as the to nominate er we'll have on the continent of the react and which is in no beer. And since you have two and a beer, the Twingo is a power. So this is the GSC expression for this Here. All these things are to the concentration off the person reactions. So first you have to know the concentration off each of the reactant and products to find out the value ofthe Casey. And again, the concentration is equal to number off more over volume. So we know the volume of the reaction vessel, which is given as five later. But we don't know the number of malls were given the mass off each of the components present and from their masses. We confined the molar mass off each of the components. So we'll first find the number of mole off. Each of these is the number of mole off in B. R will be as you know, the number of bullets. Maciver Moller, man. So the math. Off the air is 3.2. Program over the molar mass off. This is 109.92 Cramp our mall and this will give us develop 0.9 more. So similarly, if we just divide each mass by their molar mass Ah, for in all the masses again, it is three point or eight on def. Smaller masses 30.1 and grandpa are more, which will give us a value ofthe sirrah 0.1 or three mall. And finally for no bro mean the number of Molly Beam. There's 4.19 Graham over the molar mass of Ramin 1 59.808 Grandpa, our mall and this will give us a bell off. Is there a 0.58 more so these are the number of malls for each of the components present. Now we will divide each number of malls by the volume which is five liter. Get the concentration off each of thiss. If we just divide each number of moles by the volume will get the concentration for each of them. And in this way, the consummation off. You know, beer will find a zero point, um 0058 more per later or Mueller so just simply divided. How far in beer to are the number of malice not? This is zero point for beer, too. The number of bonus 0.26 more. All right now we're dividing each number of most for the volume to get there concentration. So the concertina beer will be part of the Zeta Phi Beta. Then the concentration off in or by the very number of malls off this bias by the volume will happen. 10206 more and then similarly will find the concentration of bra mean dividing its number of malls by the volume, which is part of your little fight too. So these are the number off the concentrations for each of the component percent Indus racial mixture. Now we can just plug his values here in this case. See, So we're just black, the palace of concentration for each one. And if we do that will find a kissy Vela's 1.9 zero times 10 to the poor, minus four. So this is the value of the kissy for the duration now. Ah, In second part of this problem, we have to find out the total pressure exerted by the mixture of gases. So for finding out the total pressure, we have to find out the pressure started by each component. And we can do that by using the ideal gas low, which is which gives us ideal gas equation be fecal toe energy. And from it, if we just to rearrange this equation has B and we just would feel on the other side, it will be in wave. You know, Murphy, I'm sorry, t and again, this envies our concentration, which you have calculated as this so envious concentration. We can write this as c r D. That means pressure is able to concentration times the reversal Guess constant and the temperature. So let's find out the pressure for each one or in no beer. No. For an O. B. R, it will be, Ah, the concentration off no beer, which you have calculated as Spartans citizen of 58 Moller are more barley eater times our anywhere. So guess constant in literature. Um, you need t zero Teo, eh? 20 a liter a t m far more. Mark Galvin times the temperature averages 3 73 Calvin, which is given as 100 degrees C, which in Calvin's killing me 3 73 Kevin. And in this hall we confined the pressure of the no beer, which is 0.177 for the team at most very pressure. So this is the pressure of Anna beer. And similarly, you can find the pressure off in Oh, if we just multiply the Constitution off, you know, by the universal against Constant and the temperature will get the pressure off. You know, a 0.6318 PM atmospheric pressure and then for from pro mean it will be zero point 159 Ciro atmospheric pressure. So these are three pressures for exerted by each of the component. That means the total pressure will be simply the some off these three. And if we just add this to together, we get a well off 0.9665 PM So this is the pressure exerted by all the components or the total pressure exerted by the mixture of gases. And then in Percy, we have to find out the mass of the original symbol ofthe no beer. So the mass of the original simple and very simply ah, the sum of the masses off the Caribbean components since you re actually know that no mess is lost. And, um so the amount of product we have here is basically the amount of the reactant, which was initial integration mixture. That means the total mass off in O B E. R, which is the reactant, will be equal to the sum of all the Caribbean messes. That means 3.22 Graham Glass, 4.1 in cramp less three point oId Graham. So the daughter will give us mellow off No. 10.49 Graham. So this is them total mass off the grim components. And since this is the total mass of the one component, that means this is also initial mass or the original mass off the reactant and O b R

In this question are going to be looking into the calculation of K. P. And K. C. for the reaction in which we have two miles off and off, We are at equilibrium two moles of N. O. Last and more off. Promise all of these are guys. So in terms of the partial pressure rather the K. P. This is the equilibrium constant. We're looking for K. P. Being equal to the ratio of the concentrations of the product to that of the reactions. And since we are dealing with gas is the concentration that we are going to be talking about is the partial pressure. So this is going to be equal to the pressure pressure of and or multiplied by the partial pressure of beatitude. These are our product divided by the pressure pressure of and or B. R. And we always have to remember to raise each concentration to the power of stick A metal quick for N. O. P. R. This is going to be too and for N two or for N. Or this is going to be equal to two. So remember all of these are evaluated at equilibrium. So we need to determine the pressures at equilibrium. So what we can do is to have our I see table where we have an opr forming an or and pr Sure. So what we need is the initial concentration then we looked at the change and some of those concentrations are going to be equal to concentrations at equally. So looking at this information, we need an initial pressure and before this creation starts we won't be having any any or any the trump. So let's say this decreases by victor of two eggs. If we are to look at this reaction we have two moles. If this decreases by two X. It means our N. Or is going to increase by two eggs. And our PR is going to increase by eggs by looking at the ratio of malls. So its equilibrium the partial pressure of and or B. R. Is he not miners X. And that of or is two eggs and eggs of that of promise. Now looking at this information, we have been told that 34 That 4% of an opr two has dissociated. So what this means is two X. Divided by peanut should be equal to 34. Is it? Therefore our peanut is equal to 5.88. So looking at this information, if we have this we know that at equilibrium. That is in general the total pressure of the gas minister is equal to the sum of partial pressures of the individual gases that are making up that system. So if its equilibrium with the pressure 0.25 It means that the pressure is coming from the partial pressure of N. O. B. Are at equilibrium plus that of N. O. Plus that off B. R. Two. So these are going to be the partial pressures at equilibrium since this pressure is also evaluated equally. So it means are 0.25 is equal to what is the partial pressure of an Opr equilibrium not minus two x. and our peanut is 5.558. So the partial pressure off an Opr equilibrium is going to be equal Job 5.88 x minus plus the partial pressure of N. O. Which is two X. Plus that obeah which is we saw for R. X. R. X. Is equal to 0.0 36. Now that we have our eggs it means the pressure pressure of N. O. P. R. Of the equilibrium. This is going to be equal to 5.88 two X -2 X. Which is equal to if we make the substitution of X. Into this equation we get our partial pressure being equal to that would want and that off and oh this is going to be equal to two, multiplied by X. And this gives us 0.072. And that of pr to this gives us Pressure a partial pressure of 0.0 36. And this is an atmosphere now that we have pressure pressure's let's just go back to this expression. This is now what we want to use because we now have our partial pressures at equally. So our K. P. The european constant. This is going to be equal to 0.072, multiplied by 0.036. All of these two budget by the partial pressure of and all pr Great which is opened. 1 4 quit. So the K. P. Here this reaction this is going to be equal job 9.55. 10 to the Power -3. Now moving on to calculating R K. C. We know that K. P. It's also equal to K. C. Multiplied by charity raised to the power of delta and where to go to N. Is the change in the number of most molecules in that reaction where we have here we have three and here we have to so that we're looking at the product and react. So looking at this information we have three minus 3 -2 which gives us one so our delta and is equal to one. We now have our temperature and our and we now have our K. P. So all we have to do is to make our Casey Subject of the formula head to get nine five x 10 to the power negative three divided by 0.08-1 which is our multiplied by the temperature which should be in tel Aviv. This is in atmosphere later pair more Children. So it means the temperature that we have to use here is in atmosphere is in Calvin. So this is equal to 25 Plus 2 7. 3.15. All of this should be raised to the power to japan which is apartment. So making that calculation our Casey here this is going to be equal to 3.9 by 10 to the power negative for.

So here essentially were given a specific chemical reaction where N O B R uh made associate to form nitric oxide and grooming. And we have all gashes species. And were given that we have a container of 10 leaders and everything in terms of essentially grams and mass units. So we have to convert everything in terms of concentration. So first essentially we have information that we have 6.44 g of NODR. Yes at equilibrium. So 644 g. This has a molar mass of of approximately essentially 110 g per mole Civ 6.44 divided by the molar mass. Then divided by the volume would give the concentration. So we have a concentration equilibrium of about 0.59 molars for nitric oxide which has a molar mass of approximately 30 g per mole, We can see that this has a concentration of about 0.011 molars. For essentially bro mean uh essentially bromine has a molar mass of essentially approximately 160 g from also 8.38 g divided by Uh the following them divided by the volume. To yield the concentration is about 0.0052 molars. So we're dividing the constitution products by the reactant, adjusting for storage geometric coefficients. Okay, and by doing so We can see that our equilibrium constant with respect concentration is about 0.018. So in our second part we're asked to find the total pressure. It's basically exerted by the mixture. So essentially we should convert everything back into moles and then uh or we can directly use concentrations. So it's important to remember that PVS essentially equivalent to NRT. We're going to use our ideal gas equation. So pressure equals the number of moles divided by volume. RT So this would essentially be equivalent to the concentration. So we just have to multiply all of our following numerical values here by essentially artie then summing everything up, which would give essentially the total pressure. Since we're going to assume everything is an ideal gas and by doing so And were given information that were under 373 Kelvin's as our temperature. We can find that the total pressure is essentially about 0.68 atmospheres. And in our last kids is important to remember that essentially the equilibrium constant with respect to pressure is related to the equilibrium constant with respect to essentially concentration by the falling quantity. And we see that the change of number of moles of gas is essentially we have an increase of one increase in one mole of gas. So this is equivalent to the following. And now we can use this information to essentially solved and using this information to solve, We can see that equilibrium constant with respect to pressure is essentially a about 0.55. And this gives our final answers

First we will write the equilibrium constant expression K p. It's going to be equal to the pressure of the product. N O C L squared because of the coefficient divided by the pressure of Eno, also squared And then times the pressure of Cl two. And then we can plug in the values to calculate the value of the constant. So um NOCL is 1.2 atmospheres, So it's 1.2 squared. We omit the units for the K expression you have, N O is Um 0.05. Okay. And we'll square that. Yeah. And then cl two is 0.3. So then we just have to calculate 1.2 Squared, Divided by .05 Squared And then divided by .3 Is 2, 2 significant figures, 1.9 Times 10 to the 3rd. Okay. And that is the value of K p.


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