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Arrm"JnAndtne qucslion will Sae thus response Lcyin;' [O0 $ LoineQuestion 18KDirotte thax 4 faameras?tullawing Genet {Jucu WhlahMin Food polsoning Tutserculost Lyine Disrat "d the comman coldGurtan 180/*

arrm"Jn Andtne qucslion will Sae thus response Lcyin;' [O 0 $ Loine Question 18 KDirotte thax 4 faameras? tullawing Genet {Jucu WhlahMin Food polsoning Tutserculost Lyine Disrat "d the comman cold Gurtan 180/*



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Answer Problem 30.17 for the thermal and photochemical cyclizations of $(2 E, 4 Z, 6 Z, 8 Z)-2,4,6,8-$ decatetraene.

Okay, so we have several solutions, and we have to rank then in decreasing prison point. Okay. Um, the important thing about this question is to consider the dissociation pattern and this substance. Okay, so the Friesen point change. Okay, follows this former. It's a constant. Okay, that depends on the substance. It depends on to solvent. There's a negative sign just to remind you that this is going down. So the freezing point goes down as you increase the concentration off the particles. Then you have the morality off the solution. Okay? And there's one extra piece que auction we we can represent as an I that I is used to taken account of dissociation What that means. Well, it really the collective properties, they depend on the number of particles in the solution. Not really. Then the number of molecules just started because molecules, you may have a big molecule, but when you put that in solution, that breaks into smaller particles. Okay, so the number off these smaller particles is what matters. So this I exist to take in account this association. So for example, in this case, I would be three, right? Because this big molecule here or Crystal or whatever is not. He broke into three pieces. Okay, so for each spaces, we have to consider whether or not there would be the association. Okay, so first, let's look at sugar. So the sea, Uh, let's see. Six age, 22. 06 actually, sugar. It's a molecule. Um, and there's no significant dissociation when you put that in water. So it's solid is right. A complete reaction. When he goes through the solution, it won't change the structure. It would just be solve aided by water. So I would be just one because one particle became one particle. Um, the tricky one among the list. And the question is C age three c o. Because this one actually establishes an EC equilibrium. Okay, so once it's dissolved in water, you can he can associates because it's an acid. It's an organic acid, so this hydrogen here can pop out. Okay, Uh, if you don't remember organic chemist er deaths here, C o h. That's an organic acid that's characteristic over an organic acid. Okay, so what can we say about I? We can really say the eyes equals one, because that would say that would be implying that the association here is complete, which is not the case. This association actually is quite small because organic assets are which, in a sense, that their dissociation is to his mo extend. So all we can say is that I is greater than one, but likely it's also smaller than, say to it would never get to being a weak acid. Okay, so let's quickly go through the orders. The under three are actually salt, so it's easier. So I'm going to write this in a simplified way. So, for example, if you have the they saw the salt, the sodium phosphate and it will pretty much completely the associate and to three. So Deion's and a false wait. Okay, so I, in this case, will be or all right for make news in chloride, Same thing that will break into magnesium two plus and to chloride. Okay, so I equals three. And finally we have sodium chloride that would associate into sodium and chloride. So I equals two. Well, so now what we have to do is trying to create a little table and put the I into consideration. So let's say let's see if we can do that. So we have the sugar first we have the organic acid. We have sodium phosphate, magnesium chloride, sodium chloride. Okay, we have the concentration. So point this is in more. That's more the morality. Uh, same thing here. Here we have 0.10. Here we have from 20. Here we have 35. So we have ice. This is one. All we know here is the greater than one hair. It will be for three and to So let's multiply across. So this one 0.15 this one we don't know, but we know it's greater than 0.15. It was certainly be smaller than points through three. Remember? Because I said that it won't get to it won't get to be too. This one will be point for this one will be 10.6. And this one will be 27. So I actually organized that already in order here because now you see that the freezing point would go down in this way because of these values here

Hello students in this question we have a pen which is filled with hot food And it is cooled from 94° integrate to 86° integrate into minute. Okay. When the room temperature is not equal to 20° integrates and we have to determine the time taken leaders. So this is time t. When it is cooled from 71° integrate to 69° integrate. So from the Newton's law of cooling we can write that even minus T. To develop a time T is equal to Stephen plus T. Two divided by two minus T. Note And molecular by this constant K. So this is that even this is the key to and this is time t. And in the next situation this is Stephen, this is T. two. So for the first case we can write that 94 minus 86 divided by two minutes. That is one 22nd. Is equals to care 94 plus 86 divided by two minus 20 and 42nd condition we can write that 71 plus 6. 30 79 minus 69 divided by time T. Dash. This is equal to K. And 71 plus 69 divided by two minus 20. Okay so after solving we get this time t equals two 40 seconds. Okay so option B will be the correct answer here. OK thank you

So we could do a little bit of algebra here and convert the equation that allows us to calculate Celsius from Fahrenheit to an equation that allows us to calculate Fahrenheit from Celsius. First will multiply both sides of the equation by 1.8 and get this here. Then we will add 32 to both sides, and we get this. 1.8 Celsius plus 32 is the Fahrenheit temperature.

For number 76. There's an 80 kilogram person that consumes 2500 kilocalories a day, and we would assume that 95% of that energy is converted into heat. And where to find what is their temperature Change home. So into it, heat temperature change. But the M C double t the heat. We're gonna keep it in kilocalories, and this isn't 95% of it. So I'm gonna take 95% of this 2500. That'll be the heat that increases the temperature. So the masses 80 kilograms. I looked on table 14.1 for the specific heat of the human body, and I did the one that was in kilocalories per kilograms, those 0.83 And I'm trying to find the change in temperature. I multiplied. I divided. I get that. The change in temperature was 35.7 degrees. It would be Celsius. And then I'm asked what is unreasonable but the about this result Well, that's it for it to increase 35.7 degrees. I mean, the human body temperatures around what, 37 38 degrees Celsius. So this is pretty much doubling that temperature or if you think of it in Fahrenheit, that's about 163 degrees for night. That's ridiculous. You know, when you have a fever when you're sick, that's 100 and four degrees fair knight. So 163 degrees is dead s. So that's what's unreasonable. This increase is way too much. And then the mask. Which of these assumptions responsible for that ridiculous answer? Well, for sure, it's this 95% 95% of the energy that you eat is not covered in the heat in your body. You need that energy to plump your book blood and debris than to move all day home. So that's the the unreasonable premise that gives us this unreasonable result.


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