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Which will have the fastest reaction rate? A. Ba(OH)2 (s) + 2 NH4Cl (s) → BaCl2 (s) + 2 H2O (l)+ NH3 (g) B. 2 Ca (s) + H2O (l) → 2 Ca(OH)2 (aq) C. OH-...

Question

Which will have the fastest reaction rate? A. Ba(OH)2 (s) + 2 NH4Cl (s) → BaCl2 (s) + 2 H2O (l)+ NH3 (g) B. 2 Ca (s) + H2O (l) → 2 Ca(OH)2 (aq) C. OH- (aq) + H3O+ (aq) → 2 H2O (l) D. S (s) + O2 (g) → SO2 (g)

Which will have the fastest reaction rate? A. Ba(OH)2 (s) + 2 NH4Cl (s) → BaCl2 (s) + 2 H2O (l) + NH3 (g) B. 2 Ca (s) + H2O (l) → 2 Ca(OH)2 (aq) C. OH- (aq) + H3O+ (aq) → 2 H2O (l) D. S (s) + O2 (g) → SO2 (g)



Answers

Which of the following reactions are oxidationreduction reactions? (a) $\mathrm{H}_{2} \mathrm{CO}_{3}(\mathrm{aq}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(1)+\mathrm{CO}_{2}(\mathrm{g})$ (b) $2 \mathrm{Li}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(1) \longrightarrow 2 \mathrm{LiOH}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})$ (c) $4 \mathrm{Ag}(\mathrm{s})+\mathrm{PtCl}_{4}(\mathrm{aq}) \longrightarrow 4 \mathrm{AgCl}(\mathrm{s})+\mathrm{Pt}(\mathrm{s})$ (d) $2 \mathrm{HClO}_{4}(\mathrm{aq})+\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq}) \longrightarrow$ $2 \mathrm{H}_{2} \mathrm{O}(1)+\mathrm{Ca}\left(\mathrm{ClO}_{4}\right)_{2}(\mathrm{aq})$

Chemistry is the study of matter and the chemical reaction between substances. And we also do concern ourselves with the composition, structure and properties of matter. Here, we're looking to balance out some equations. So what this means is having the same number and type of atoms on the left hand side, with our reactant, as we do on the right hand side, which is our products. So in this fast example, we have an A to S uh to see you and oh three. And this gives us to NANO three and C U S. The next example, we have three, N 2, H four and this gives us for NH three is a gas, Ammonia and N two. Also as a gas continuing on with starting off with hydrochloric acid, hcl add to up to gas. What this gives us is two H 20 As our liquid, and two cl 2 as a gas. Finally, we have F E S. Is a solid to H C L. What this gives us is FECL two And H two s. As a gas.

So we've got some reactions here. We're going to try to identify them as to type. So in the first one you can see that we're reacting in a mean, right. You can see that from the telltale nitrogen surrounded by carbon and hydrogen. So amines are always week basis. True. And we're reacting that with hydrochloric acid, which is one of our strong acids. Right? So using the key we would say this is a strong acid week based reaction. Mhm. And the next one, the calcium hydroxide has hydroxide in it. So that's clearly a strong base. That's where you C O H minus. Okay. And we're gonna react that with a weak acid. Hydrofluoric acid is a weak acid. So, again, using our key we can say that this is a weak acid, strong base reaction. All right. And the next one we have we have calcium hydroxide and we have sodium phosphate. So one of them is a base but the other one is not an acid. Instead, what we have is that we're going to go ahead and form of precipitate. And so the precipitate of calcium phosphate is going to form from those two solutions. So this is a precipitate reaction. Okay. And the second and the next one the silver sulfate in the barium chloride. Same thing. We're going to make a precipitate of silver chloride. So that's a precipitate reaction. Okay. And then the last one we have to acquiesce solutions which do not form a precipitate. They are not acids and bases. So since we have no precipitate forming it's just gonna be ions floating around in solution. So we're gonna go ahead and say no reaction.

Before me like a P is equal to K C R T Delta End K P is equal to K C Onley when Delta N is equal to zero. So for a until toe end would be equal to four moles of gas in the products minus formals of gas in the reactant, so equals zero. So for a K P is equal. The Casey for be Delta end would be equal to three moles of gas in the products subtract two moles of gas in the reactant sweats equal the one here cape. He is not equal the Casey. And for C Delta End, we have one mole of gas in the products minus one mole of gasoline. Reactant sis. And here K P is equal the Casey. So KP and Keesee are the same for equilibrium A and C.

In this video, we're going to be identifying types of Aquarius reactions and identifying whether or not it precipitate is formed in these reactions. So we can have a few choices to choose from strong acid, weak base, weak acid, strong base, no reaction. And you can also have strong acid strong base. So let's do the first example. So we have ethyl amine reacting with hydrochloric acid. Ethyl amine is a weak base and hydrochloric acid is a strong acid. When these two react, the proton from the hydrochloric acid will be transferred to the methyl amine and then it's going to result in the formation of assault. So this is not going to be a precipitate. It will instead be an adequate solution because it is assault. Mhm calcium hydroxide is a strong base because it is a hydroxide of the alkaline, earth metal, calcium and Hydrofluoric acid is a weak acid. And it's one of the exceptions to the acids form from the Holiday Inns. So when we react an acid and base, we're going to get water and the salt and the salt is going to be an Aquarius solution. So there is no precipitate. So again we have the strong base calcium hydroxide and then we reacted with sodium phosphate. Yeah, so in this case the sodium phosphate has the phosphate ion in it and fast food i on is a weak base. So the important part of this reaction is going to be the formation of a precipitate. So in my drug side is soluble, however, calcium phosphate is going to be a solid. So therefore there's a precipitate and that's based off of the solid ability rules because the fast feet of the calcium is going to be solid and insoluble in water. In this reaction we have the sulfite ion which can be considered a weak base and so can the chloride ion. However, the important part of this reaction would be whether or not a precipitate forms. If we refer to the solidarity rules, we will see that when self is paired with the barium ion is going to be acquis. Silver chloride, according to the rules, is also Aquarius. Mhm. And because both of the products are acquis, when we write the net ionic equation, we're going to have all of the ions cancelling out so we can write no reaction. Mhm.


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