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Three graphs are given below_ For each, choose its equation from the following:V = CSC2 TX y = 2cSCy = tan 2y = tan Tx + 2TX y=2secy =-cotEquation:Equation:Equation...

Question

Three graphs are given below_ For each, choose its equation from the following:V = CSC2 TX y = 2cSCy = tan 2y = tan Tx + 2TX y=2secy =-cotEquation:Equation:Equation:

Three graphs are given below_ For each, choose its equation from the following: V = CSC 2 TX y = 2cSC y = tan 2 y = tan Tx + 2 TX y=2sec y =-cot Equation: Equation: Equation:



Answers

Graph two periods of each function. $$y=\csc \left(2 x-\frac{\pi}{2}\right)+1$$

We're going to do problem number 49 in this question it is. The graphs are given in our book. So we have toe. Just try to the equation off this off the graph. OK, so let us right the information which we can take out from the graph. So if we observe the graph carefully then we can say that the graph is starting from the graph is is starting from negative. Why access? Okay, negative. I exist. This is the first information which we can say by absorbing the graph. 2nd, 2nd information which we can say is it is repeating itself. It is repeating itself in a period name period off. Bye bye. Four in a period off by by food. On its amplitude is its amplitude is 0.75 which is which in rational form can ability and has three by four. Okay, if you simplify it. So these are the three information which we can obtain from the graph. OK, so let us just write the graph the question of this graph. So let us say that is why the function is why is equals to Yeah, okay. The given standard farmers off a cost function cost bluff a possibility. This is the general question which is given to us now, putting the value of N B as indicates the amplitude so well right here. That is three by four. And it is starting from negative side. So we are going to put a negatives idea. And now, cause now, as the period is by by four So we're going to multiply 80 so that to pipe I ate. It will give us by by four. That will be the period. So this is our answer. This is the question off the ground, given in question number 49. This is how we write the question of the grab that side.

In order graph on the coasts. Eakins of X over to again. I like to try to go back to that table mentality in order to be able to graft this. So I'm gonna start off by looking at the sine function because that's one that's going to be the reciprocal here. What we're gonna do here is we've got zero high over two pi three pi over two and two pi. And so what we have here going on here is we've got 010 negative one and 01 of the things that we can see, however, is all of my X values here will be What What's happening is the frequency is 1/2 which means that if I was going to do an operation on the X values because it's inside of the function, I'm going to take the opposite operation multiplied by two. So I've got zero. Hi, two pi three, pie four pi. And since sign the output of when we want co seeking is gonna be the reciprocal. If I take the reciprocal of all these values, I'm going to get undefined going to get one. We're gonna get undefined going to get negative lawn, I'm gonna get undefined. And so when we go to graph this, we can see at zero. It's undefined. So we're looking for something where a nascent tote is at zero. We're looking When we get to pie, it's going to be at one. When we get to two pi, it's gonna be undefined. And we know since the sine function looks like this, the coast seeking function goes in the opposite direction. The sine function exists between negative infinity and negative one and one an infinity. So in this particular case, we're looking for a graft that has this sort of shape to it. And so we can see here that in this particular case, the answer that best resembles this question is going to be Question is going to be answer number one.

The first figure is a graph of Y equals kill CMT. The second figure is a graph of Y. E. Calls twice. Cool Scientific. The Empty Toodle dysfunctions to and the period has joe part. The 3rd figure is a graph of white equals Cozaar. In sweetie. The aptitudes is one and the pure areas two pi over three did she kills two thirds parts. The last of figure is a graph of Y equals cause I. T. Plus hi Overstreet The amplitude of these functions. one Period, that's two points and the shift is flyovers. Ray unit left.

The key to this problem is looking at where the graph starts. Um So as it starts at the origin or somewhere else, since it starts at the origin, we're going to look at a sign curve uh and it's going down first, so that's going to be a negative in front. Uh You can see that it goes down to negative two. So you know, that's that's gonna be your sign. Uh And then the last um last thing is where does the first cycle end? So as you look, the cycle ends at four pi. Um So the number that goes in, that's an X. Right here is normally the period is two pi and divided by B would give you the length of that full period, which would be for pie, if you do a little cross multiplication and divide the pies will cancel. And you would divide the four over to divide by four, reduces to one half two. Um And this should be your right answer. You know, y equals which corresponds to letter F.


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