In this solution, there is a figure given. So first I will draw this figure and explain the data. So you can see that in the figure there are three particles is given, whose mouth is, that is forage particle masses given that is 23 g. And these three particles are fashioned to three wards of length. That is given this equal to well centimeter. So here I'm doing this figure that is given. So this is the first particle, this is the second particle and this is the third particle and I can say that this is the first door whose land this status city, then this is the second door whose land is D. And this is the third door whose land is that is D. And yeah at this point masses for what for I considered these three particles that is Cuban. There is M is equal to 23 g. So and this is the point named SQL and at this point, oh so for the information is given, that is they're totally assembly protests around Point B. With anglo Israel is Cuban. That is omega is equal to 0.85 radiant per second. And so now you can see that in the kitchen three parts is given. So I will answering the all parts one by one. So let's start answering the execution. So in the part A. It is asking that we have to find the rotational inertia of assembly. That means we have to find the rotational inertia about point or of system. So it'll readiness. That is. We know that the rotational inertia for point about a vertical axis. There is if I consider that this is a vertical axis and this is the point at which the particle is situated with masses M. And the distances. Studies from the vertical axis, perpendicular distances. That is our then for particle, the rotational inertia about this vertical axis we reorganize there is M. R. Is square. So use this concept then I will say that the rotational inertia of the assembly will be written as there is I considered I one plus I to plus I three. So for I one the rotation inertia will be that is mass of particles for all for all three particles masses him. So that means given the Dcm and now our is changed according to particle. So for first particle that are well written eyes with respect to point. Oh, I considered I will wait at this day. That means the square. No, for then I do will be it nice. That is the rotational inertia for second point about point or will be I considered mass multiplied by distance with the square two point. Oh, that is I consider D plus D. That means today. So that means M. R. Square. That means emptiness of to the square plus. Now, similarly I three will return eyes. That is rotational inertia of third particle. So I considered mm times of total decisions with respect to point or will be that is D plus D. Plus D admits three D. It's choir. So mhm. No. Mhm. Simplify it. Then I will get the answer for party. That is answer is Mhm. After reading I will get that is 14 MD square. So now put the value of M. And these human there is M is 20 g and 23 g and these 12 sentimental. Then I can see that in as a unit. The M will return is that is 23 multiplied by 10 to the power of monastery kg. And they will be recognized in the A. C. Unit against the 12 times of 10 to the power of minus two m. So for this data, that is human in this step then I will get the rotation in this year of assembly about point or will be equal to at least 14 times of and will return as that is 23. Multiplied by 10 to the power of minus three kg. Multiplied by the square. That means 12 times of 10 to the power of minus two Holy square. So after swallowing final value is that is equal to 1.1, sorry, 4.6 times of 10 to the power of minus three kg meter square. So this is the answer for part A. Now come to the next part. That is part B. In which solution is asking that we have to find the magnitude of angular momentum of middle particle. That means mhm. For this vertical we have to find the magnitude of angular momentum. So we know that the angular moment of general formula is studied. L. Is equal to that is I Oh my God! So yeah, I will be for middle particle. I can say that that will be I two. And omega is given that is by which the assembly is rotating about 20.0. That is given omega angular speed. That is equal to 0.85 18 per second. So use this data and I considered it will be recognized that is angular momentum of the middle particle about point or will be organized. That is it will be that is I considered yes that is mm times of our square. I will be there is two days where that means I consider it mass multiplied by okay to the square then omega. So omega is given that is 0.85 Ready in per second. No for the value of mass M. Of article and that is the that is given length of war. So I will get the angular momentum mhm of mhm. Middle particle about point full. Yeah that is equal to that means L. Is equal to 23 times of 10 to the power of minus three kg. Multiplied by two, multiplied by 12 times of 10 to the power of minus two. Holy square multiplied by 0.85 So simplify it. Then answer is studies one point one time. So I'll stand to the part of monastery kg meters square once again. So this is a powerful part. B now come to the next part that is part C. In which it is asking that we have to find the magnitude of angular momentum of the assembly. So I considered the my needed of angular momentum of assembly will be written as that is equal to that is L assembly will be equal to I system times of omega. So I say to me which I had already. God in party value will be that is used this value from party and omega is given in the question that is 0.85 radian per second. So the data then I will say that the magnitude of angular momentum of assembly about white or will be recognized. That is I system is that is 4.6 times of mhm 10 to the power of monastery kg meter square multiplied by omega is that is 0.85 radian per second. So no simplify eight. Then I regret the answer that is equal to 3.9 multiplied by 10 to the part of minus three kg metal square per second. So this is as well for part C. That means magnitude of angular momentum of the assembly about point or will be written as that is 3.9 times of 10 to the power of minus three kg meter square parts again. So I had saw the question completely. Thank you.