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In a AC circuit, ther is a 10kilo-ohm resistors withs frequenzy of 65H. The peak voltage is 135V. What is the coltage across 5ms? the sine was has a 0 phase...

Question

In a AC circuit, ther is a 10kilo-ohm resistors withs frequenzy of 65H. The peak voltage is 135V. What is the coltage across 5ms? the sine was has a 0 phase

In a AC circuit, ther is a 10kilo-ohm resistors withs frequenzy of 65H. The peak voltage is 135V. What is the coltage across 5ms? the sine was has a 0 phase



Answers

An $L C$ scries circuit has a voltage source given by $E(t)=30 \sin 50 t \mathrm{V},$ an inductor of $2 \mathrm{H},$ and a capacitor of 0.02 $\mathrm{F}$ (but no resistor). What is the current in this circuit for $t>0$ if at $t=0, I(0)=q(0)=0 ?$

In this tournament is given Getting 80 Working. Are we ready? What If you put somewhere on the wire offer this date? You have you. We have to complete. We're ready. Hey, I'm in bed, Mom. Put it away. Week, Bedwell Parental over. Justified Its The men were board is divided by its registration. You can love one raises when he went that this stays in people. So when will we will get by five MPs? No, we have to make the argument that opening arguments been worked. Guarantees Big Ben. What? Divided by that It Why fight fight? Dubai, everybody. Bhutto, who is one wife for one foot on. Suddenly you wouldn't get one United View Who in the white beat Benoit current is 25 years and are instead work charity wine every night and fears Thank you.

Hi. In the given problem, the voltage amplitude across in doctor, he's given us 180 world and the voltage amplitude across capacity has given us 100 and 20 world that 180 Emphasis 120 world and the voltage amplitude that grows resistor that has given us 100 and 60 world and instantaneous potential drop across in doctor at any instant that is given as a revolt. So using all these parameters, they have to find in spontaneous potential drop taking place across resistance and the gross that passenger. So first of all, using the expression for instantaneous potential drop across in doctor that is given as real Izabal too. We l means voltage amplitude across in doctor into and that is minus real in to sign omega t So sine omega t comes out to be, we help. I minus b l. So it becomes sine omega T is equal to 80 by minus 1 80 which becomes minus zero point for 44 So I only got the will be given by signing verse of minus zero point 444 which comes out to be minus 0.46 or eight Young's So using this value of omega T now we can find the instantaneous potential drop across the resistor, which is given us. We are means voltage amplitude across resistor into cause omega T. So it becomes 160 world into cause sign off minus 0.46 radiant. So it will be given by 143.4 walls. This is one of the answer for the given problem. Then we have to find we see also means instantaneous potential across capacity and that is given as we see into sine omega t. So we see here is 120 in the value of silo Negative was already known to us, and that was minus 0.444 So this is minus 0.444 So it comes out to be we C is equal to minus 53.3 volts, which becomes second answer for the given Rodman. Thank you

Have? Current in the register equals two. I Equals to 8.0 sign 45 45 p. and the voltage in the register v equals to 60 world ST. 45. Okay. 45. So for the part of the question in which we have to determine the resistance value. So resistance value are will be equal to the note by my notes. From the equation we have been not equal to 60 year old. And from the equation we have I not equals to 8.0 MP. So from here traditions are equal to 7.54. Okay. Now For the party of the question in which we have to determine the frequency and voltage of uh frequency and period of the voltage source. So from this situation we have this value is equal to omega. Omega is equal to f. And it is equal to 45 from the equation. So from here After solving we get frequency f equals to 20 Hz. And the time period capital T. Is given by one by F. So one by 20. So from here we get a time period equals to 0.05 seconds. Okay, this is the answer for the part. So now moving to the part C. So in the party we have to determine the average power delivered to the resistance. So the power average this will be equals to be RMS multiplied by I. R. S. And we have peak values so we can write that we not divided by hutu, multiplied by not developed by route. So from here we get we not I not divided by two. So we have both. The values of power embrace. This will be equals two. We not which is equal to 60 world and I note which is equals to eight mps, divide by two. So from here we get every power delivered to the resistance equals 2 to 40 watt. Okay, so this is done some 40. But see, So this is the value for the registrants, and this is the frequency and time period, and this is the average power delivered to the register. Okay.

So we have a C A si voltage. Um uh, voltage of eight hundred forty bull A one hundred and eighty volts and a resistance of three hundred and ten homes. So are you. Peak current will equal the peak voltage divided by the resistance. Salutes will equal one hundred eighty, divided by three hundred and ten. And this will equal point five eight one amps now are our route means squared Current essentially will equal the peak current divided by radical too. So this legal point five eight one divided by radical too. And we're getting point for one one amps. So these will be your two answers for this question. That is the end of the solution. Thank you for watching.


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