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Set Uptne 5yskemequatlons and ten eolvo Itby usic nH eds[IANOna Laie inveatmat Pl 1074 Put 7ul; 4nd4 Mare ruy Imostmcnt nJy? [84 nerinvesmente How much should sho i...

Question

Set Uptne 5yskemequatlons and ten eolvo Itby usic nH eds[IANOna Laie inveatmat Pl 1074 Put 7ul; 4nd4 Mare ruy Imostmcnt nJy? [84 nerinvesmente How much should sho invcd 21 cach @te?omjcAonFdldd

Set Uptne 5yskem equatlons and ten eolvo Itby usic n H eds[IAN Ona Laie inveatmat Pl 1074 Put 7ul; 4nd4 Mare ruy Imostmcnt nJy? [84 nerinvesmente How much should sho invcd 21 cach @te? omjc Aon Fdldd



Answers

Use $U=$ universal set $=\{0,1,2,3,4,5,6,7,8,9\}, A=\{1,3,4,5,9\}, B=\{2,4,6,7,8\},$ and $C=\{1,3,4,6\}$ to find each set. $$ \overline{B \cup C} $$

We need to find see? Compliment. Sit. And that means Ah, we need to. CV Chairman's are not common between the universal search and the SETC. So elements which are not part offset See, we can write it as ah in the universal set, we can see that zero is not common. 1346 are part off sexy. So we should award that So to then 34 are part offset C five is not a part off search. See then seven A trend night. So this is see compliment such elements.

Here. We need to find the sitch off elements which are part off a compliment. So when we say a compliment, that means the element should not be part off. A How are they should be part off the universal set you. That means the element which are part off you but not in set A can be found from from these value given values. You is from 0 to 9 and a elements are 1345 nights. So the elements which are not present insert a and present in you. She is zero. That means we're taking that notch. Common elements. So since one is common between you and a we're not considering one. Then two is only presenting universal search you not in a then 345 and nine They are present in set s so we should skip that those numbers so we can write six, seven on and eight. So these elements are not a part off set a Howard their part off the universe and such you. So this is the a compliment

Hello and welcome to this video solution of numerous. Here we are given the rules of silver and copper are constantly reducing their scalability in So we have got option A. S case in which is the correct option. Now using the in the Synod process, what we do is okay let's let's try to find out what in what is happening in case of signing process. So let us take the Argentina, which is a G two S. Plus. We have Casey in now for this occasion this gives us a complex of silver. This is okay, ain't you? Him two plus it works now. This compound that is formed is soluble in the solution. He's so little now this is thing for copper also. Thus we can have a quick and select option skc I hope this is clear to you and have a very good thank you.


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