Question 19Binary choice For each; choose the letter of the best choice: Physical Property ChoiceChoice BChoiceWould mixwhen combined:HzO and CsHsHzO & CH-OCH3H...

Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair that has the higher boiling point: (b) $\mathrm{C}_{3} \mathrm{H}_{8}$ or $\mathrm{CH}_{3} \mathrm{OCH}_{3}$, (c) $\mathrm{HOOH}$ or (a) $\mathrm{C}_{6} \mathrm{H}_{14}$ or $\mathrm{C}_{8} \mathrm{H}_{18}$ $\mathrm{HSSH}$, (d) $\mathrm{NH}_{2} \mathrm{NH}_{2}$ or $\mathrm{CH}_{3} \mathrm{CH}_{3}$

And this question we're comparing the effect of inter molecular forces on the operation cooperation basis. Uh huh. Molecular wasn't remember vapor pressure defines the boiling point because if liquid only boils when it's flip operation is the quality of the atmospheric pressure surrounding that liquid. So for us to determine the effect of intermodal forces on the operation, it means if the inter molecular forces are with we forces call to high vapor pressure because an increase, this is a decrease in the strength of course is equals an increase in the ease of evaporation. And if a liquid is easily evaporated, it means there is a higher the cooperation. So moving on this is basically what we'll be looking at. We look at the strength of the inter molecular forces that are prevailing. The stronger the force, the lower the rate of evaporation means the lower difficult operation. So moving in the first set mm we've been given B I C L bri and we are going when we are looking at this, these are non polar compounds, many polar compounds. As a result, the inter molecular forces that are dominant here, are there decision faucet. So for both compounds dominant, inter molecular forces at the dissipation forces. And we know that what then differential is strength of the molecular forces of the inter molecular forces. The size Oh, molecules yeah. Higher the science or the bigger the science equal to the higher the strength. Oh, the forces. So when we look at these two, we can tell that B I. Pr A. Three, you ca done B I see all going. So it is easier, it is much easier to evaporate BICL three than it is to evaporate B I Pr happening as a result, B A C opening is called higher the preparation BSL three has got here. I have a question then be a happy opening. So just to go through that again briefly because this is the same principle that we're going to be using. But the remaining molecules assets, we look at the inter molecular forces that I had to play for this one. We have been given the A. C. L. Three and P. A. We are doing. And both of these are non polar compounds and for non polar compounds, the most dominant inter molecular force at the dispersion forces. So they are at papa they are equal when it comes to the dominant inter molecular forces. But what then differentiates them is the size of the molecules. P A P R three has got bigger molecules than P I C will bring. As a result, P A P R three has got stronger participation forces, strong participation forces. If it has got strong anticipation forces, it means it is more difficult to evaporate it as a result to have oppression is lower. For PHP are trying so when we are looking at this Be a SEAL three has got a higher population because it is easy to evaporated. And why is it easier to evaporate? It is because the strength of the test patient forces. Uh huh. Weaker than those of B. I. Pr. So moving on comparing C. O. And the bottom. When we are looking at this we know that ceo is non polar, man, Paula. No ceo is polar. This is a polar compound. C. O. Is polar. As a result I would expect it we have dip alta typo was it? These are the dominant inter molecular forces. Then you also look at it the auto when they are looking into the ocean comparing it to see or to see or to to comparing it to see all. we can tell that the dissipation forces that are in C. O. Or the table to table forces that are in C. O. Are weaker than the forces in coton. As a result, it is much easier to evaporate ceo than it is to evaporate CO2. As a result we've got higher vapor pressure of ceo. Yeah, more than one comparing and to end and all. And true is nan Paula. It is a non polar compound. Therefore the most dominant inter molecular forces are dispersion forces and or on the other hand is polar. Therefore the most dominant into molecular forces are departure. Hey paul forces and when we look at the strength of these forces, we can tell that dissipation forces are weaker than the day poor today paul. What as a result it is much easier to break the inter molecular forces in nitrogen than in in so it is much easier to vaporize into done and all. As a result we've got a higher population into them and all moving on to protein. We've got meet al format middle format again I said to that's it. So these are very interesting compounds because these two have the same formula and formula and on the same side. Bye. What's interesting about this is ascetic acid forms hydrogen boy. But little format cannot. So we can just assume that the dominant inter molecular forces mental form and uh decision. What's it? So when we compare the strength of the inter molecular forces that I had to play within these two molecules or these two compounds, we can tell that these hydrogen bonds are stronger than the inter molecular forces found in middle from it. As a result it is easier to evaporate or to vaporize middle formatted energies to reprise ascetic, because the inter molecular forces at play are weaker in middle format than they are in a setting us. As a result, the rate of evaporation of middle format is higher than that of ascetic acid. Hence the population middle format is higher than that of ascetic acid.

Explanation for the question. Yeah we have to identify the thai are types of inter molecular forces and then select the substance which is greater boiling point from each pair. So here in part A. We have given substances are C three H eight all and beauty and butane. C four S. Train. So here in this given pair the inter molecular enter molecular forces in both molecules, both molecules as dispersion forces and a substance which is higher boiling point is N butane because you test larger size and greater surface area. Okay, next for part B. S. We have given substances are die a tile eater. Here's formula is CS three CS 2 or CS two CS 3 And the next one is 1 beautiful and use formula Ezio CS three CS 2 CS two & c. s. two. Oh it and this given pair here are dying it. I peter has here die by the terrorists die paul, die paul di paul. The whole day I fall in dispersion forces forces. And next we have you can all yes hydrogen bonding hydrogen bonding along with along with die paul die paul and this person forces. So when we will compare this vote inter molecular forces present in each given pale. So the molecule saving hydrogen bonding the molecule which is hydrogen hydrogen bonding will have higher boiling point. So that is. And beauty north. And you to know. And next to we have part C. We have given pale is s. 0. 2 R. s. 0. 3 Sulfur dioxide and sulfur dioxide is 03. So cell phone. Try oxide. Yes Die paul self try oxide. His dispersion forces. Yeah dispersion forces. And sulfur dioxide has Die paul di paul. Okay. And dispersion forces. So here sulfur dioxide is this present forces. So sulfur trioxide will be. Can say that they saw a tree sulfur trioxide. We'll have higher. Hi you're boiling burning point because it is larger size. Yeah. Uh huh. Larger size. And next we have body Given pair a molecules or c. two c. O. This is foggy. Our next one is formally height is to see oh and here 14 contained Die Paul, Die paul, di paul and dispersion forces. And for men the height have also die cold dive all and dispersion forces. So here for jim we'll have higher boiling point because it is larger size. So it is are you boiling point because it is larger size. Mhm.

There are three common types of inter molecular forces. Dispersion forces, which are the weakest that are present in all molecules, then disciple disciple forces which are present on top of dispersion forces in polar compounds and then the strongest of all is hydrogen bonding, which occurs when a hydrogen is directly bonded to a nitrogen oxygen or flooring atom within a molecule. The first compound is c eight h 18. Any time we have a hydrocarbon that is made up of just carbon and hydrogen, it is a non polar compound as a rule of thumb and only contains London dispersion forces as its strongest inter molecular force. The next compound is a hydrocarbon with a chlorine on it. Chlorine is very electro negative, introducing a die pole to this molecule, resulting in it being a polar molecule and having diet pulled, I pulled into molecular forces. The next one suggests a carbon is directly bonded to an oxygen. I'm sorry, a hydrogen is directly bonded to an oxygen. We could redraw this way, showing a hydrogen directly bonded to an oxygen so it is polar, and because the hydrogen is bonded to an oxygen, and hydrogen bonding exists for the last one. Because of the oxygen right in the middle of the molecule, oxygen being fairly electro negative, the molecule is polar, exhibiting dipole, dipole, inter molecular forces of attraction.

In a let's consider the two different compounds were working with here. We're working with K two s, which is gonna be an ionic compound, and we're working with C H three three I am, which is Covalin. So the predominant molecular forces that are going to take place here Well, in K two s, um, Ionic is gonna be our predominant I am s and in see it 33 and we're gonna have dispersion forces as being are predominant high on meth. And this is just a matter of remembering whether Ionic or dispersion is a stronger force that we're working with. And we need to remember that Ionic forces are always greater than other IMF's when it comes to what we're working with. And that means that key to S is gonna have higher melting point in the we're considering between B r Q, which is molecular roaming, and C h three ch two ch two see age through. That's gonna be it, man. That's gonna be butin that we're working with. Um, so here we need to consider again which of our forces were going to be working with predominantly. So in b r. Two, we're going to have, um, dispersion forces. And in butane, we're also going to have dispersion forces. So now it comes down to a matter of which one is gonna have larger dispersion forces. Well, for this, we need to consider how many electrons there are on those, bro means and how big that electron cloud is gonna be compared to beauty. And the fact of the matter is, booming is much, much larger. So we are going to get a much stronger attraction taking place as a result. So thus we see that bro Ming is gonna have a higher melting point.