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Cosrstant Bromothyol Ble' Lqutkbrium slightly to 226 EXPERIMENT 16 Gently swirl the probea sample Record the observed pl to the containing your probe = into th...

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Cosrstant Bromothyol Ble' Lqutkbrium slightly to 226 EXPERIMENT 16 Gently swirl the probea sample Record the observed pl to the containing your probe = into the 50 mL beaker rcading to equilibrate. Insert the [H*I,as described in the to the tip, and wait for the calculate the value of circulate solution instrument; Use this to reported by the the full accuracy data section_ and return to the jar; turning Introduction, and record it in your gently dry the pH probe finished, rinse and When YO

Cosrstant Bromothyol Ble' Lqutkbrium slightly to 226 EXPERIMENT 16 Gently swirl the probea sample Record the observed pl to the containing your probe = into the 50 mL beaker rcading to equilibrate. Insert the [H*I,as described in the to the tip, and wait for the calculate the value of circulate solution instrument; Use this to reported by the the full accuracy data section_ and return to the jar; turning Introduction, and record it in your gently dry the pH probe finished, rinse and When YOu are the contents of the 50 mL beaker: Use dropper to sealit Then discand of the absorbance of your sample: screwtop measurement is not clean, rinse with your Now vou Will need to take your - cuvette full with your solution; if liquid with Kimwipe_ to fill a clean, dry cuvette 3 /4ths Cap the cuvette and dab away any surface Ifit does not read sample solution before loading; and take reading at 635nm_ Insert your blank cuvette into the colorimeter; Then remove the blank cuvette: the calibrate button to recalibrate the instrument and the exterior is clean and dry: 0.O00," press the cuvette containing your sample is capped absorbance: Then remove Make sure measurement at 635nm. Record the Insert itin the instrument and take the cuvette and discard the sample: concentration of dye in the same solution You will now take second reading at lower small volume of Solution A (the pure 25 mL volumetric flask is not clean and dry, rinse it with your added dye). Then use your 10 mL volu- solution from the stockroom; not the sample to which vou 25 mL volumetric flask Fill to the metric pipet to transfer 10 mL of your Solution A-] sample to the Calculate the value ot [HBB]O for this solution and line with (pure} Solution A_ This is Solution A-2 record it in the appropriate space in YOur Data section _ Use dropper to load cuvette with Solution A-2 (rinsing the cuvette if necessary) , capping cleaning as described above: Use the blank to check the calibration of the colorimeter at 635 nm and (recalibrating if necessary), and measure the absorbance for Solution A-2. Record the value where indicated: Transfer the remaining Solution A-2 to a clean, dry 50 mLbeaker and measure the pH,as you did for Solution A-1 above_ Record the pH, and calculate the corresponding [H'1 Measurement of the Equilibrium in Solutions B-| and B-2 Repeat the steps above for Solution B to obtain solutions B-l and B-2_ At the conclusion of the experiment, you should have the absorbance at 635 nm and [H- for total of 4 cases: Solution A-1 A-2, B-l, and B-2. Analysis Your goal in Part I is to determine the extinction coefficient for ionized form (in strongly basic solution) at 635 bromothymol blue both in its nm; Use Beer" In Part II; law to determine these values your gOalis to calculate the equilibrium constant for trial (A-L,A-2,etc ) use Equation (16-5) to each set of conditions determine [BB- For each to determine [HBB]: from Then use absorbance data,and Equation (16-6) mation to calculate thepH to determine [Ht] (via Equation (16-91 the = equilibrium constant via Equation Finally, use this infor- (16-2)_ L.oc/o



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Purification of proteins for use as biopharmaceuticals is often accomplished by ion exchange chromatography, in which a process fluid passes through a column packed with small resin beads whose ionic surface charge causes them to adsorb some stream components more strongly than others. An ion-exchange run takes place in two steps: (1) the load step, in which the process stream flows through the column and the target protein (the product) and some undesired impurities are adsorbed onto the resin; and (2) the elution step, during which another fluid passes through the column and desorbs the impurities and the protein from the resin. The elution fluid consists of an aqueous solution of a solute known as Tris diluted with an $\mathrm{NaCl}$ solution, with the NaCl-to-Tris ratio starting at 0 and steadily increasing with time. The impurities desorb into the fluid when the NaCl concentration is low, and the effluent is collected in a waste vessel. As the NaCl concentration increases, the target protein desorbs. When analysis of the effluent reveals the presence of the target protein, the flow is switched to the product collection vessel, and the effluent is collected until no more product is detected in the effluent. The collected product is then subjected to additional process steps to further isolate the protein, and the column is cleaned for reuse. Consider an elution step in which solutions of 1 M $\mathrm{NaCl}$ (solution A) and 50 mM Tris (solution B) are mixed and fed to a loaded ion-exchange column. The system is programmed to keep the total volumetric flow rate $\left(\dot{V}_{\Lambda}+\dot{V}_{B}\right)$ into the column constant at 120 Lh while linearly increasing the volume fraction of solution A in the feed from $0 \%$ to $20 \%$ over a period of 33.6 minutes, at which point the elution is declared to be complete. The flowchart is shown below:
(a) Calculate $V_{\mathrm{t}}(\mathrm{L}),$ the total amount of solution fed to the column. (b) Derive an equation for the volumetric flow rate of solution $A, \dot{V}_{A}(t),$ assuming that the densities of both fluids are the same. Use the calculated value to determine calculate $V_{\mathrm{A}}(\mathrm{L}),$ the total volume of that solution fed to the column, and $m_{\mathrm{A}}(\mathrm{g} \mathrm{NaCl})$, the total mass of $\mathrm{NaCl}$ fed. Then determine $\dot{V}_{B}(t)$ and $V_{\mathrm{B}}(\mathrm{L})$ and $n_{\mathrm{B}}(\text { mol } \text { Tris) }, \text { the total volume of solution } \mathrm{B}$ and total moles of Tris fed, respectively. (Hint: Once you've done the calculations for solution A, those for B should be trivial.) (c) Suppose in one run product is detected in the effluent at the same time impurities are detected $-$ that is, product protein starts desorbing earlier than in previous runs. List up to five possible causes of the problem.

Explain why the connection without good excites and we've been excited. It's two different products. Let's look at the mechanism with our without backsides but the Nation actress first step and it produces Benzie like Come Pick a Time which is further stabilized by untraditional. Were fifteens in it in, for instance. Oh, structure was shows conjugation and this camera car time is most stable with public art time at this common, which is making conjugation with the benzene in. That's why this the assured direction off the reaction and a combination with BR minus gives you the major product in the prisons or both sides they have taken. Spacious is different. That's the radical of woman and unethical of woman. Also wants toe form Benzia political fishhook, and it's, ah, most able than medical at this carbon. For the same reason that would be liking education off the benzene green. And then on the next step over chain propagation, the medical reacts with them. HBR Junior is another. They are dark and gives the product

So the first thing we're taking a look at it is not in technology here, so sensors were able to detect even the very small amount of chemical vapors. A few different equations that we'll need up on the screen while we take B is equal to pi the cube over six. We substitute in the Valley for volume in Equation one, you get equals density pie. Three. There's a six he had absorbed. That is Q. Is, um bracket that? And we are integrating within the limits. TMP I'm 25 degrees Celsius Have C p of the solid T d t at the doctor h hot bad the integral T v P T M p cp Liquid T t T at Delta H B. What we find is that we got an expression cube. There's 1.827 times 10 to minus 17 D A nanometers. Cute jewels. In the second part, we're rearranging the second equation that is up on the screen, this one just like this one now, using the next one. Where was solving for 40 nanometers? The minimum? Probably a on peace 1.552 times 10 to the four jewels per meter squared 23.9 watts, respectively. And then we we have 80 nanometers. Fn p. Minimum values are not playing 4783 times 10 to the four jobs per meter squared on 7.37 What's doing the exact same thing for 1 20 nanometers? Don't put 1/4 too One times tense. The four jewels for meat squared on 2.19 watts. So we use the laser power that is intermediate between those needed to pay a price. 40 and 1 20 nanometer particles such as the listed for 80 nanometer particles, so the large particles that have a greater diameter them on 29 m will remain in solution.

Predict results for the two foreign reaction. One finger prep. In with its shell, it's you will return it while a figure prepping and bread use a more stable Ben Zizek crocodile ritual. Capture CR minus on Give the world the alternative. Kavika Tile at this carbon would be less stable because of the leg off education with it benzene for hundreds inoculation. The reaction proceeds through Make uranium on the press. The charge will be distributed between America and roaster gerbils, and this carbon will have more positive charge because it will be better. Gillick allies back in education with the benzene. So this position, well being attacked with water with the bunt with maker comes off on America is a benched through the other carbon and then deport the nation and removal, or for America by reducing agent Junior it in Alcohol River Bridge Group in the bin Zigic position

Predict the falling borders off penetration. Hey, for each group is Ah, Ortho PETA director, and she is free group that's met the director. So it's a case off consistent orientation. So that letter group enters with this Brothers Bay like trial is that met the director and this will free H is a metal director. Let's again consistent orientation in the latter group interests this position. See him in the struggle. Is it met the director. It directs into this position and horses figure is the offer. Period Director directs the order positions and the prayer position. The donor Rene's over except when it comes to orientation. Substitution to the Ortho position. Prevent Letter Group is not favorable because over stone edit from accepting activity or from in a group, so the product would contain the latter group into this position. They can be really a very minor impurities within matter. Group entering the close positions


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