Find the fractional difference between g[1] and g[2].g[1] = 10.09 m/s2g[2] = 9.86 m/s2Note: Please be clear with your steps and writing....

Find the acceleration of each mass with the given total force. $$ m=11 \overline{0} \mathrm{~kg}, F=57.0 \mathrm{~N} $$

Okay, what's actually start by doing part B? Because I don't actually help us get part A. So what's know here that this is part B we're starting with. So acceleration is equal to the change in velocity over the change in time. So that's pretty straightforward in this problem. In this problem, the change in velocity our final velocity is 27 0.3, minus our initial velocity, which is 17.4 in the change in time. Well, the total time elapsed is 10 seconds. And when we plugged that into our calculator, we find that our acceleration 0.99 meters per second squared. That's pretty straightforward and it will actually help us get party. Let's use that acceleration for part A. There's a couple different equations you could use here. But for the sake of this problem, let's use this one where the final velocity squared is equal to the initial velocity squared, plus two times the acceleration times the distance. Now we know the final and initial velocities as well as the acceleration, so that should help us get X. And when we solve for X algebraic lee first you would subtract over the initial velocity. And then once you had two. X by itself, who just divide by two A as we do here and we get this equation. So it's plug in the numbers we have and find the value of X. So once again, 27.3. But it's squared minus 17.4. Squared all over to times are acceleration, which was 0.9 nine. And that gets us a final answer of 223 25 when we played that into our calculator.

Hello. We are to further the court is used the mass of an object. Is that issue of its mate to the next lesson? G. Moss is that issue of its weight to the exclusion G. Due to gravity. If the space probe With 8146 clue Newton 8146 Khloe Newton on Earth Where Z is 9.8 m/s sq one. It's right max and Katie. That is yeah. 9 48. Winter Park sickness Square. So Moss maybe 8.46 into 10. to the power three Newton Upon 9.8. So we will solve it eight six. But by 9.8 so this will be a cost to 0.86 .8632 into 10 to the power three Kg So much as well because to mass of the space prop Will be 8.6 32 Could you, Sorry? 63.2 Kg. 8 60 three 0.2. Could you? So this is the answer. I hope you understood. Thank you.

In this problem, we have to find the acceleration of each mars whether given total force. So in this Problem We have given mass, which is 210 Kg, and net force Is equal to 41 newton. So we know that force will be equal to mass into acceleration. So acceleration will be equal to force divided by months. Now here forces 41 continent masses 210 Kg. So this is a call to 41, divided by 210 41. Yeah, divided by 210 mhm, which is equal to 0.195 m per second squared. This is the acceleration.

This problem. We're converting 328 milligrams two grams. So in order to do that using the prefix table, we have to understand the relationship between milligrams and grams. Since milligrams are since grams is there standard unit of measurement, it's easy to figure out the relationship that 1000 milligrams is equal to one gram and vice versa. One gram is equal to 1000 milligrams. So we know that whenever we're converting, were using the power of 1000. So if we're going to a higher number, we will be multiple are dividing by 1000 for going to a lower number or a lower unit. Then we are divided multiplied by thousands. So we're going from milligrams two grams. So we're going to a higher unit. So we're going to be dividing our number by 1000. In the easy way to do that is move the decimal place as many zeros as there are in the number you're dividing by. If you're dividing my powers of 10 so we take 328 in our decimal would be there, move it three times. So our answer is 0.3 to 8 grams. So that is how you convert from this from milligrams two grams