Submie 1 3 H 1 to sludy 1 1 1 Question 8 | Iicioscopy | 1 1 suructura 0 (TEM) to study Ine uetaled orqane movemoni 1 1 1 | 1 1 1 cells 8 8 Concept 6 cell (Page 94)...

Calculate $E^{\circ}$ for the following cells: (a) $\mathrm{Mn}\left|\mathrm{Mn}^{2+} \| \mathrm{H}^{+}\right| \mathrm{H}_{2} \mid \mathrm{Pt}$ (b) $\mathrm{Au}\left|\mathrm{AuCl}_{4}^{-} \| \mathrm{Co}^{3+}, \mathrm{Co}^{2+}\right| \mathrm{Pt}$ (c) $\mathrm{Pt}\left|\mathrm{S}^{2-}\right| \mathrm{S} \| \mathrm{NO}_{3}^{-}|\mathrm{NO}| \mathrm{Pt} \quad$ (basic medium)

This a question. We're asked to use road transformations to transform the following matrices. So we see two missing values in road shoes. We have real one wrote to and row three. So to get to these two values in road to we can basically take are to minus three times are one from this first matrix. So we have three minus three, which is 08 minus three, which is five. And then for this element. Here we have 10 minus 12 which is minus two. And for our last element, we have three minus. All right, three times minus one. So you get be it. Six. So that's our second row in the second matrix. Now, for the third role in our second matrix, we can calculate by using the third robe in our first matrix. So we have our three minus two, and then we add plus two are one. So we get zero by minus two plus two, three by one plus two and then for the next two elements, we have 12 plus two times four, which is 20. And for our last element, we have six plus two times minus two, which is four so that gives us all of the values for our second drinks. Now moving on from the second metrics to the Third Matrix, you basically see that our first role remains the same. Second row is everything from the second row of this matrix divided by five. And for our third role, we see that everything remains the same. So we have 03 24 and these are all our matrices, and this is the answer to the question.

Wherever you sell the cell. It was. Probably would have to do first. So I need to write out the equation. The happy closed for half years. So I know you have coffer foreigners close because we worked on those copper. You the new triple yourself. Okay, but I also don't have the concentration for copper. Plus, so I can calculate that. So if I have K S p that equals a concentration of, um here, see you toes. So mercury is P is for one. No, I you You're okay. So now one of those things Q. Same thing here. This is his copper. The and alluded. Sorry. Use. It was the same day Because you have a copper of the air. Knows a copper with the capital. You do you work?

If we have the matrix With the elements 10 -30 to negative two, 87 negative 50 16 0 10 for one The determinant of this matrix is -2. This would mean that it does have an inverse.

So in this question, were given the following three matrices and were asked to transform. Yeah, so we see in our first row of the Matrix, we start off with 24 83 and we end up with 1 to 4 and three over to right here, which is basically are 1/2. So we used that to fill our values here. So are 1/2 basically to for and 3/2. So we have all off the rose for the first two matrices. And now for the last Matrix. Thank you. Received for our last room 02 We see it's actually from the first matrix for three minus our one. So we have two minus two, which gives us 06 minus four gives us two for minus. Kate is going to give us minus four and nine. Minus three is going to give us six. So that's the values for the last row of the third matrix. Now, for the final value here, you can see that it's a result off the two roles are one and our two here. So we basically have are two minus our one. So we have one minus one. That gives us zero minus three minus four. That gives us minus seven and two minus 1.5. That gives us half. So here are two minus. Our oneness are too minus our one, which is minus three. So that's her value right here. And these matrices are the answer to the question.