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2) A circuit with a resistance of 240 ohms is given a voltage of60 Volts. What is the calculated current, in amps, that will runthrough the circuit?A) 0.25 AB) 4.0 ...

Question

2) A circuit with a resistance of 240 ohms is given a voltage of60 Volts. What is the calculated current, in amps, that will runthrough the circuit?A) 0.25 AB) 4.0 AC) 2.5 AD)14,400 A

2) A circuit with a resistance of 240 ohms is given a voltage of 60 Volts. What is the calculated current, in amps, that will run through the circuit? A) 0.25 A B) 4.0 A C) 2.5 A D)14,400 A



Answers

The voltage in a circuit with alternating current is given by $$V(t)=160 e^{-20 t} \cos 120 \pi t$$ where $V$ is in volts and $t \geq 0$ is in seconds. (a) What is the initial voltage when $t=0 ?$ (b) What is the frequency of the voltage? (c) Solve $V(t)=100$ graphically.

Hi In this given problem there are two resistors. R E and R B. Both are unknown. We're joined in cities first of all with a source of old age providing 6.0 volt. Total voltage is 6.0 volt provided voltage and potential drop taking place across the first resistor. Yeah that is given as we is equal to four point zero. All no equivalent resistance of this serious combination will be given by R. E. Less RB mm Net resistance in this series combination will be equal to I is equal to be by our equivalent All the this is 6.0 or equivalent resistance. This is R. E. Less RB. No if we consider the resistance are only the current passing through that means I that would be given by home. Slow as I is equal to V. A. By R. E. And yes I A. Will be equal to I only as we know current remains the same in series. So using these two equations situation one integration to We conclude that because the value of VA is also given to us in place of we can we can use 4.0 world divided by R. A. Is equal to in place of I. We can use 6.0 old divided by R. E plus R B cancelling this. We finally we get or by R. E. is equal to six by our A plus RB. Now making a cross multiplication. We get four times of our Plus four times of R. D. Is equal to six times of our a. Or we can say rearranging the terms four times of RB is equal to two times off are A. Or finally E. Is sequel to rise off R. B. This is one of the relations between do the sisters? No, these poor sisters are joined in parallel and it is given that current passing through resistor R. B. It has given us 2.0 ampere. It implies using arm slow again because in parallel potential in the same. So for the resistor R. B., the potential will be seen as 6.0 world. So this is 6.0 world divided by resistance R. P. Which is missing And that is equal to 10. But finally we get the value of this artie as 3.0 Home. So using this are even come out of it two times of RT means two times soft. 3.0 home In 6.0 home. These two are the missing resistors of this even problem. Thank you.

Hello and welcome to Chapter 18 Problem number 44 Holt Physics and this problem were given to unknown resistors A and B and two different scenarios. One where they're connected in series and one where they're connected in parallel and were asked to find the value of each of their resistance is so, uh, we're pretty much just gonna be using OEMs law and this and some properties of parallel and resistors and Syriza's well, so to start things off, we're gonna actually calculate Be first for ease. Since we have a current And we have Since A and B are in parallel here, we know that they have the same voltage, so we'll be able to really just jump right in it to find our first resistance resistant. To be Do that we isolate are are are in r V equals ir equation. So we have that split voltage between them to parallel components. Six volts this time, uh, over our current that we were given two amps so that I'll just give us our first resistance, be three owns. Now we're going to get a little more complicated because we need to take, uh, the information we gained this RB our resistance here. I need to apply that into our Ah, the first scenario here. So start things off. We know that the six volts has to be used in our entire circuit, so we're gonna have four volts. We know we were given that across a so we can just do simple voltage difference subtraction to find out that we have two volts across this Ah resistor be here. So I have that calculation just right off the bat down here. Up next, we're gonna dio is used vehicles ir again. But find the current running through our entire circuit here on. That's because resistors in series they have the same currents they do not in parallel. But in our case, in this first scenario, the same current running through a will be the same current running through B, and that will help us greatly. So to do that, we use that That's new Delta V for B r voltage across our big resistor on. We'll divide that by r resistor for be that we calculated up top of three amps of three OEMs. Excuse me. So we'll have a current of 2/3 of an amp running through our entire circuit, and so we're pretty much done. We just need to use vehicles ir again, but this time isolating for our A. So we'll do that down here we have our A is equal to the voltage difference across a divided by that currently just calculated so before over 2/3 to give us a total of six homes of resistance across a.

So we've got owns law that says voltage measured in volts is equal to, um, the current I measured in amperes times the resistance measured in homes. So this is direct variation. It fits the format y equals k times. That's why equals K Times X. Um so it fits into this unit. Well, eso were asked to find some things. Find the voltage if the current, which is I measure Nan furs is 24 the resistance is to home. So we have to do years 24 times two and the current or the voltage will be 48 volts. All right, so that's the answer. The first part of our question and then be says I find the resistance if we have a current of 24 fears and a voltage of 18. So now we know the voltage is 18. We know the current is 24 but we don't know the resistance. So this one we have to actually divide both sides by 24 and that comes out 2.75 So 18 divided by 24 is 240.75 as in 0.75 What are we measuring resistance and owns, so O. H. M s 00.75 owns would be the resistance that the voltages, um, 18. And the current is 24. Toughest part about this is just making sense of each one of the variables and making sure you're getting plugged into the right, uh, spot.

So there are two things that is required over here. First thing you should know is if you connect to the distance over here, both of them are are. Then the equivalent resistance becomes too are on. If you can do resistance in palaces, then the equivalent distance becomes our over to. So now we get solved. This problem we have got I know this is right fast, but one do three four of article sections. We have got to armed resistance here, and two armed resistance here, so base to we'll give you four own resistance. Remember that. Now we have got four home here as well. So this section will have four and 14 Paladin so they could wind resistance over here would be to our. Now you have three over here on one. Over here. All of this. We are asleep. Thus wanted was for us to equal six. And now you have six over here. So thank you. And resistance over here would be six and probably the sixth over here. So the equivalent resistant over here with the three home on. Do you have one over here? So that means the equivalent resistant over here will be three for these side of the branch and whatever here. So that's four home. Andi knocked uprising. Yet there is four here. So the equivalent resistant upto this point will be four in value. It four over here. So that's two on. And we have one home here and 30 years old wife last three, thus to that, becomes totally six or so are equivalent of disarticulated six. Now they're asking, what is the current through here? So that's a visually I one understand that forest were to find the top is going I equals that voters Voltage 24 voltage divided by the article and six home it was for the ampere. So we have four ampere passing over here. We get divided to have two here and two there. So that was diverted to have one year and one there who gets divided into half and half. So finally we have I want the current go to home register ease. It gets divided once to ice three times. So from four, it becomes to over here on each arm, one over here in each arm and half over here in that arm. So that becomes half ampere or zero going five ampere. What is the kind of the forearm registers form register over here. That's I do that. Say we know that I do. It was I want because the time gets divided into equal parts over here. So we will also have I do equals 0.5 ampere.


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