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# Of Chapter 510-18 and the major exercisesAssume that the parallel lines and lar segment MM' Prove have that MM' is the common shortest ' perpendicu: ...

## Question

###### Of Chapter 510-18 and the major exercisesAssume that the parallel lines and lar segment MM' Prove have that MM' is the common shortest ' perpendicu: any point of and any point of /' . (Hint: In segment between first dispose of the case in which showing AA' is MM' perpendicular ' AA' , result about Lambert quadrilaterals to [" by means other case by Exercise 22, Chapter and then take care of the 4.) Again, assume that MM' is the common tween / and

of Chapter 5 10-18 and the major exercises Assume that the parallel lines and lar segment MM' Prove have that MM' is the common shortest ' perpendicu: any point of and any point of /' . (Hint: In segment between first dispose of the case in which showing AA' is MM' perpendicular ' AA' , result about Lambert quadrilaterals to [" by means other case by Exercise 22, Chapter and then take care of the 4.) Again, assume that MM' is the common tween / and ' _ Let A and B be perpendicular segment be- any points of and drop perpendiculars AA such that M + A * B and BB to [' Prove that AA (Hint: Use Proposition 4.13; see Figure 6.16.) < BB' . n1J4 # Figure 6.16 and m: Given points A and B that lie on the Given parallel lines P on L, A and P are on opposite side of m from [; Le, for any point opposite sides f m. Prove opposite sides of m, and B and P are on (This holds in any Hilbert that A and B lie on the same side of L plane_ through P and let X be point limiting parallel ray to Let PY be seem intuitively and (Figure 6.17) . It may ' through X_ but this _ on this ray between P parallel _ ray obvious that XY is & limiting not been justified. have Justify the steps that quires proof:

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