So here for part A, we can find the the flux and coil one. So essentially we can say the magnetic flux and Coyle. One would be equal to else of one ice of one divided by and someone This is equaling 25,000,000 Henry's multiplied by 6.0 milli amps, divided by 100. And so this would give us 1.5 Micro Weber's Ah, for part B, we confined the magnitude of the self induced E M F. So essentially we can say the IMF because they AMs of one equals the inducted, its ally else of one, multiplied by the change in the current someone with respect to time. So this would be again 25. Miller Henry's multiplied by 4.0 and peers per second, and this is giving us 1.0 times 10 to the second Millet bolts. Now, for part C, we can say in coil to we're doing the exact same thing so we can say that of magnetics. Yield in the magnetic fields up to would be equal to M m times i sub one divided by and so to this is equaling again. 3.0 Miller Henry's multiplied by 6.0 milli amps, divided by 200 instead of 100. And this is equaling 90. Nana whoever. So this would be your answer for part c. Your answer for a part b Your answer for a part. Ay and finally, four part D. We want to find the induced IMF in essentially coil, too. This would be equal to M times the change in the current in coil one with respect the time solicit again be 3.0 Miller Henry's multiplied by 4.0 and peers per second. This is giving us 12 Mila volts. This would be our answer for a party That is the end of the solution. Thank you for watching.