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ResourcesGIA Upssignment Score: 733/1700Question 5 0f 17Suppose you havcsamples that an: equal wcight; 26.8 g V and 26.8 g Al,Os.Calculate thc number of moles of ca...

Question

ResourcesGIA Upssignment Score: 733/1700Question 5 0f 17Suppose you havcsamples that an: equal wcight; 26.8 g V and 26.8 g Al,Os.Calculate thc number of moles of cach subslancemolmolAL,0,TOOLS

Resources GIA Up ssignment Score: 733/1700 Question 5 0f 17 Suppose you havc samples that an: equal wcight; 26.8 g V and 26.8 g Al,Os. Calculate thc number of moles of cach subslance mol mol AL,0, TOOLS



Answers

Calculate the number of moles of each compound in the following samples. (a) $1.56 \mathrm{ng} \mathrm{NH}_{3}$ (c) $21.5 \mathrm{~g}$ calcium carbonate (b) $6.98 \mu \mathrm{g} \mathrm{Na}_{2} \mathrm{CrO}_{4}$ (d) $16.8 \mathrm{~g}$ strontium nitrate

Uh, here in this question, we have to calculate the number of more severe substances in a given species. Same. But so here for part. We have the morning myself. Mueller Moss. Uh huh. Magnesium chloride is equal to 95.2 gram per remote using its smaller mass. The number of moles is calculated is here number of moles of imagination. Glow right is equal to for 41.5 ground into one more. Divided by 95 point 21. Grand music director 0.436 more mall of indignation. Color right solution for partly here. Mhm. Yeah, The Mueller myself. Lead him oxide. Mueller must of lead him Oxide. Yeah, is equal to 29 point 88 Drum Permal Using your smaller mosque, the number of Maltese calculated his Yeah. Number of wars of lithium oxide is equal to 1 25 milligram. Multiply 1 g divided by thousands milligram into one more. Divided by 29.88 Go is equal to 4.5 to multiply. 10 raised to the power minus three mall Bleed him oxide. Yeah. Yeah. And so for Farsi. The mother must have come from is Muller Moss, right of chromium is equal to yeah 52.0 ground paranoid using the modern mosque. The number of moles is calculated s yeah, number of moles. Chromium is equal to 1.21 kg into 1000 grounds divided by one kg into one mall divided by 52.0. Camp is equal to 23.3 Moules of Romeo solution for party The mother myself is to support sulfuric Is it Moeller moss of sulfuric acid? H two s 04 is equal to 98.8 grand per more using a smaller mass. The number of Moore's is calculated is number of moles. Okay, The stories of four is equal to 62.5 g into one more. Divided by 98.8 ground. Is it? Well too little 0.637 right? No love is too so far for body. But he did murder myself. C six 86 is equal to 78.11 Brown Parma Using your smaller months The number of moles is calculated is number of moles. Yeah. C 686 is equal to 42.7 Graham Multiply one mall divided by 78.11 ground. Is it well too? 0.547? Yeah. Mhm more C six. It seeks. Yeah, pencil for part of the mother myself. Hydrogen peroxide. It's two or two. Is it good to 34.1 Go on Baltimore using its mother mosque. The number of moles is calculated as here. Number of moles. How is too or two is equal to 1 35 g into one more, divided by 34.1 g musical, too. 3.97 malls of H 202 Yeah!

Let's calculate the number of moles in each of the following in a We have 11.51 grams of titanium divided by the Moler mouse. 47.9 grabs Prum old with shields, 0.240 Moles of titanium For B I got 29 0.127 grams of sodium times, 23.0 grams per mole, and that will give 1.27 moles of sodium and for C 1.477 kilo grounds of uranium was first convert this tick rams in one kilogram. You've got 1000 grounds times the molar mass of uranium 2 38.0 grams per mole, which will yield six point two.

Hi there. This problem is actually actually six individual problems, but in each problem, we're doing the same thing. We're converting from grams of the substance, two moles of a substance. To do that, we're going to have to divide by the molar mass of each one. So let's go ahead and get started and later A. We have 53 0.8 g of brilliant looking at the periodic table. I can see that in one mole of brilliant, there are 9.1 g of brilliant. I knew that I wanted to put grams in the denominator because I want grams of early, um to cancel and my answer remaining. Then in most of brilliant. All I need to do now is the actual calculation, which will give me 5.97 Moles of beryllium, which is our answer for part a moving on to part B in Part B were given 781 g of C three h, four c l four. You need to look at the masses for each of these elements on the periodic table to calculate the molar mass so that in every mole of C three h four c l four you should get 181 0.83 g grams will cancel. The only units remaining are moles, and our answer will be 4.3 own goals of C three h four c l four in part C. Yeah, We are given zero 0.756 grams of calcium hydroxide. Calcium hydroxide should be written as C A with a two plus charge, which means we need to hydrates with that or to hydroxide. Rather. So it should be C a. O. H. Two again finding the molar mass of calcium hydroxide. It's gonna be 74.8 g calcium hydroxide for every mole. So you should be starting to see that writing the formula correctly is important because the formula determines the Mueller Mass. Without the correct Mueller Mass, you would not get the correct answer, which, for this problem is going to be 0.0 102 moles off the calcium hydroxide in Part D. We have 9.94 We have 9.94 g of cobalt three bromide. So that's gonna be CEO VR three. Because cobalt three means it's oxidation. State is plus three for the cobalt. That would require us to have three bromide ions so that the compound would end up neutral. Calculating the Moller Mass of C O. B R three gives me 298.63 g of cobalt bromide and every mole of it. This will give us an answer, then, in moles of zero point 0333 of the cobalt three bromide who? Okay, moving right along. We have e and f remaining. It's got a letter eat for letter E. We have 8.80 g of ammonium di chrome eight. So that's going to be NH four for the ammonium. And I'm gonna need two of those because ammonium is a plus one charge, whereas the CR 207 ion has a negative to charge. So I mean, so I need to of the ammonium calculating the Moller Mass. For this, I find that in every mole of N h. Four to cr 207 there are 382.19 g. Solving this after canceling my units, grams solving this will give us an answer and moles, and we will get point 0 to 30 Moles of the NH four to C R. Two 07 Alright, Finally onto letter f letter f We have 28.3 g of magnesium per chlorate Magnesium has a two plus charge per chlorate This cielo four with a one minus charge that we will need two of those in every mole of m G C l 04 to there are 223 point to one grips again. I am getting Moeller masses from the periodic table by adding together each element that is found in the compound taking into account how many of each element there is. How many of each Adam there is right solving for this final answer, I get 0.1 to 7 moles that is of the magnesium per chlorate. Okay, Final answer True. We made it. Hey, thanks for hanging with me. This was a long problem but you did great. Thanks so much


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