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KNO3 is converted into KNO2 and elemental oxygen. if 489.170grams of KNO3 react, how many grams of KNO2 produced?...

Question

KNO3 is converted into KNO2 and elemental oxygen. if 489.170grams of KNO3 react, how many grams of KNO2 produced?

KNO3 is converted into KNO2 and elemental oxygen. if 489.170 grams of KNO3 react, how many grams of KNO2 produced?



Answers

How many grams of potassium chlorate decompose to potassium chloride and 638 $\mathrm{mL}$ of $\mathrm{O}_{2}$ at $128^{\circ} \mathrm{C}$ and 752 torr?
$$2 \mathrm{KClO}_{3}(s) \longrightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)$$

Where Kiffin, the decomposition Rational Porta. Same night tree. So you will give Ah, Katie open. That's a mock sigh. Nitrogen. And then also Jim. So assume we have this. This 0.6 kilogram are also your people use what would be the number Move up or there's a nightmare we need. And also the massive poker potassium nitrate. Okay, so first of all, we're going to convert our mass to, um, number Mose. So the limbo most off surgeon will be close to Freddie 6.6 time, 1000 years a kilogram. So, uh, we should have Ah, five, six, six Cyril, Cyril Graham. And then we have more than mass for oxygen. Will be two times 16 with 32 her. Uh, so we're 56600 divide by four. It's you. And then we should be able to find that is roughly around. Ah, 16 sort. 176 eight 0.75 mil for you. Okay, So the lymphoma off put potassium naturally, we need Ah, it would be way We will be. We have to find out from the well the way show. And you can see that the motorway showoff. Potassium? Um, yeah. Tree to oxygen is 4 to 5. You can also signify that this Ah, um on the way show and you should be able to finance 1 to 2. Important to 1.25 All right, so when the limbo most off hostage in ihsaa 1.21 point 25 then the limbo Most off Kay. I know three p one. So therefore Ah, where we have that many number. Most off our station. We're going to divide the whole number by, um 1.25 And then we would have won four 15 most off Kano 314 for five more care and awfully. So we would have Ah 176 nick, 1760.75 Do you want by 1.25? There were 1415 Most Okay, I'll three. Okay, so the mass Okay, off the real be half one of five. 1415 mold replied by our, um, molecule a mess. Uh oh. Starter motor mass. So the mother Massa would be one. The 1.1 Quinn for more and a mass off our, um both assumed, um, natural spring s pretty big, everyone. 40th Lee, um, poin of one. Kaito. Grab one for the sea from one kill Quick.

Looking at the following reaction for three cl 2 at six K O. H. Gives us K C L. 03 at five K C. L. That's three. h. So what we have is people on V. One is equal to P two V two. And again, we're calculating V two here where B two is equal to 784 millimeters of mercury multiplied by 138 liters, divided by 7 60 millimeters of mercury. Give us 142.35 liters privy to. So if we have 142.35 liters of cl two, we can calculate the malls of cl two That's equal to one, multiplied by one for 2.35. Find that by 22.4 We got 6.35 moles. So we have three moles of cl two that produces one mole of K C L. 03 So we take this value divided by three And we get 2.11 moles For. KC. 03. What the molecular weight of case yellow three Is equal 1- 2.5 g per mole. Multiply the moles by the molecular weight for the maths, Where the mass is equal to 259.50 g.

Okay, let's calculate how many leaders of oxygen will form from the decomposition. Potassium chlorate? That's right. The decomposition reaction to K C. L 03 to K C. L and three to. So here's their balanced chemical equation. Starting from 20.8 g of potassium clarets convert two moles. Solar masses 122 55 g k. C l 03 in one more K C l 03 start geometry and the mole ratio here. Two moles of K C L 03 to 3 moles of 02 and we're at, uh, STP. So one mole of O to support it to 22.4 leaders of 02 This will work out to 5.70 liters of oxygen produced upon the decomposition of 20.8 g of potassium chlorine

So to solve this question, we first want to write out the chemical equation that the question is giving us. So we know we start out with solid potassium chlorate, which decomposes into solid potassium chloride and oxygen gas. But we see that the number of atoms between these two sides are not. Even so. We have to balance, and we just multiply the amount of these molecules in order to even out. So we see that there's an odd number of oxygen's on the left side. We want to make that even so, we'll just multiply this by two. But that also multiplies the amount of potassium and chlorine atoms. So since there's two of them now, they're two of each. We wanna multiply potassium chloride by two. So now we have six oxygen's on the left side. There's only two on the right, so we just want to multiply 02 by three. And now our equation is balanced. So now we know that, um, we know that two molecules potassium chlorate produces three molecules of oxygen gas, and we know that we have 20.8 g a potassium chlorate in in our problem, and we want to know how many leaders of oxygen gas is produced from this. Well, to do this, we want to first convert potassium chlorate from grams to moles. So we do that through dimensional analysis, and we need the Mueller mass of potassium chlorate, which is 1 22.55 g per mole. So we know that in one mole there are 122.55 grass. All we need to do is just cross out like units and we calculate and we get Yeah, okay. Okay. 0.16 97 months. This is a large number, but well rounded down once we're done with the entire problem. No. And this is potassium court. Now we want to convert this value into the amount of moles of oxygen. And to do that, we multiply this number by the ratio of these two molecules. Since every two potassium chlorate, it's make three oxygen gas is just to over three or three over to in this case, Yeah, its three over to because we want to cross out the moles of potassium chlorate likes him. Okay, we calculate again and we get 0.25 for six malls of oxygen gas. All right, so now we have the moles of oxygen. And the question also tells us that our substances start at STP, which is standard temperature and pressure. And if you remember STP, the standard temperature is zero degrees Celsius or to 73 kelvin and the standard pressure is juan atmosphere. So temperature pressure moles and we need to find the volume. We can combine all of these units together using the ideal gas law. No deal. Gas law. Is this equation written out? PV equals NRT. And since we need volume where you're going to rearrange this equation equation to solve for volume All right, so now we can essentially just plug in. All of the numbers we had before 2546 are a 0.8 206 because the this is the constant associated with our units that we're using. So it's moles, leaders, Kelvin's and atmospheres. Remember that it will change depending on the units you'll use. Temperature will be in Calvin's, and the pressure is just one. You cross that out, since that's just going to give us the answer of the top section anyway, it's And now we just calculate. Bye. Multiplying all of these. Okay? And we get 5.7 leaders. Uh oh, too. There you go. That is your answer.


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