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(16 paint)Consider the fuuction 9(f) I / IFirihc fixel poitus of LuheLHHinis Uhne Eivcy fixe| ["Oitt s {tenn Qun () Vumua Fu tl F" H "(r4) will conve...

Question

(16 paint)Consider the fuuction 9(f) I / IFirihc fixel poitus of LuheLHHinis Uhne Eivcy fixe| ["Oitt s {tenn Qun () Vumua Fu tl F" H "(r4) will convergd" Bciefla fuitiftolr Fneatlna Y W;Y Wan- thut tu^ initinl GUA -is sufficienthclose to thc fixed Peilit

(16 paint)Consider the fuuction 9(f) I / IFirihc fixel poitus of LuheLHHinis Uhne Eivcy fixe| ["Oitt s {tenn Qun () Vumua Fu tl F" H "(r4) will convergd" Bciefla fuitiftolr Fneatlna Y W;Y Wan- thut tu^ initinl GUA -is sufficienthclose to thc fixed Peilit



Answers

The clcctronic configurarions of four clemcnts arc givcn as undcr: (I) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$ (II) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$ (III) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}$ (IV) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6 \mathrm{i}} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{1}$ Which of rhe following arrangemcnts gives thc corrcct ordcr in rerms of increasing clectroncgariviry of the clcments? (a) $\mathrm{III}<\mathrm{II}<\mathrm{IV}<\mathrm{I}$ (b) $\mathrm{II}>\mathrm{III}>\mathrm{I}>\mathrm{TV}$ (c) $\mathrm{IV}<\mathrm{III}<\Pi<\mathrm{I}$ (d) $I<$ II $<I I I<\Pi V$

Try to look at this question. It is given that among 143 subjects with positive test results, So let over here, let this be positive people who are actually positive like this with people who are actually negative. And let this be the test side. So who have tested positive? And these are the people who have tested negative. All right, So it is given that among 143 subjects with positive test results with positive test results, which means that the some of this column is 1 43. Yeah, right. In this case, Okay. 24 are false. Positive results. 24 are false. Positive results. Which means this is 24. They're actually negative by the tested positive. So what is the remaining one? 43 minus 24. That it's 119 after that, Among 157 negative results. This is 1 57 among 1 57 negative results. There are three false negative results. There are three false negatives, false negatives. What is the meaning of false negatives? That means that they are actually positive, but they have tested negative. So this is three. This is 1 53. Okay. How many subjects are included in the study? How many? Some things are included in the study 300. How do I find this? The addition of these two 300 subjects are included in the study. What is the next question? The next one is how many subjects had two negative result. How many subjects to negative result 1 53 1 53. After that. What is the probability that a randomly selected subject had a true negative result? The probability that the randomly selected subject had a true negative result. It will be 1 53 upon 300 1 53 divided by 300. Now, what is going to be the answer? In this case, we need to use a calculator. And so just give me a moment. This is turning out to be 0.513 By the way, what we're doing wrong is 1 57 minus three is 1 54. So this is 1 54. So this answer is 1 54. This answer is 1 54 and hence this is also 1 54. Now, let's try to calculate this 1. 54.300 0.513 This answer is zero point 513 These are my ancestors. Thats all I needed, right? Yeah, these are my answers.

This question now you just It says if one off the test subjects is randomly selected, find the probability that the subject did not use marijuana. Find the probability of the subject that he did not use marijuana. These are the total subjects who did not actually use marijuana. These are truly negative. These are the ones who are negative and who have also tested negative. But these are the ones who are negative but who have falsely been tested positive. So 24 plus 1 54 is 1 78 1 78 by 300. This is the probability that we want. And do we think the result affect the general population rate off subjects who do not use marijuana? I think the result is somewhat low for people who do not use marijuana. By the way, this value turns out to be 0.59 something zero point Faith Night. And this is my answer

Now in this question, I want to find out the probability. The probability that a subject tested negative or used marijuana subject tested. Negative. It is 1 57 1 57 by 300 all they used marijuana or means addition. They use marijuana. How many of them are actually used? Marijuana? It is 119 plus 3 +119 plus threes. What? 1 22 1 22 by 300. But is there an intersection? Yes, This three is the intersection. So I'll also have to minus. This is going to be minus three by 300 minus three by 300. And this turns out to be 1 57 plus 1 20 to minus three is 2. 76 by 300 to 76 by 300. And this value turns out to be 0.92 to be 0.92 This is my answer.

This time, I want to find the probability off the subject either testing positive or not using marijuana. So subject testing positive is 1 43 by 300 1. 43 by 300 by 300 or or means addition. Not using marijuana, which is the addition of these two 24 plus 1. 54 is 1 78 by 300. Is that Is there something common? Yes. This is the intersection part minus 24 by 300. So what does this turn out to be? This turns out to be 0.99 So this is the probability that I want 0.99


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