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You made 100.0 mL of a lead(II) nitrate solution for lab butforgot to cap it. The next lab session you noticed that there wasonly 71.3 mL left (the rest had evapora...

Question

You made 100.0 mL of a lead(II) nitrate solution for lab butforgot to cap it. The next lab session you noticed that there wasonly 71.3 mL left (the rest had evaporated). In addition,you forgot the initial concentration of the solution. You decide totake 2.00 mL of the solution and add an excess of a concentratedsodium chloride solution. You obtain a solid with a mass of 2.080g. What was the concentration of the original lead(II) nitratesolution?___ M

You made 100.0 mL of a lead(II) nitrate solution for lab but forgot to cap it. The next lab session you noticed that there was only 71.3 mL left (the rest had evaporated). In addition, you forgot the initial concentration of the solution. You decide to take 2.00 mL of the solution and add an excess of a concentrated sodium chloride solution. You obtain a solid with a mass of 2.080 g. What was the concentration of the original lead(II) nitrate solution? ___ M



Answers

You made 100.0 mL of a lead(II) nitrate solution for lab but forgot to cap it. The next lab session you noticed that there was only 80.0 mL left (the rest had evaporated). In addition, you forgot the initial concentration of the solution. You decide to take 2.00 mL of the solution and add an excess of a concentrated sodium chloride solution. You obtain a solid with a mass of 3.407 g. What was the concentration of the original lead(II) nitrate solution?

So here we have a volume off silver nitrate solution that reacts with excess potassium chloride solution. We yield a number of grams of precipitate and then this podcast we're determining the minority of silver iron in our original solution. So the first thing we can start out with is our chemical equations. We have a G and 03 at K. C. L is in equilibrium with a G c l a k N 03 So first we've got the massive gcl, which is not 0.842 g. We have our molecular weight, which is one for 3.32 g per mole. So then, from this we can determine our mola value, which is mass over em are so we have no point. No, not 59 moles. So then we can determine the moles off a G plus cattle which is the same as a G C. L. So the exact same figure with a volume that are not point not to five liters where we are looking at S I units, which is why we have to convert from milliliters. That is not s I units. We need to use liters here in order to generate the correct answers. So then our concentration of a G plus is malls divided by volume, which is not 0.235

So in this example we have a volume of lead two nitrate solution where the two just represents the oxidation. State led on a completely reacts with excessive amounts off sodium iodide solution. So we yield a degree off precipitating grams. So in this podcast we're determining, the majority have led to iron in the original solution. So we have our chemical equation, which is PB. I know. Three to add to Anna is an equilibrium with P B I to add to an a n 03 So then we have our calculation upon the screen. I've included just for our reference, in case anyone gets lost, our needs to backtrack with some equations. So then this leaves me with my final equation line when we have 1.36 times 10 to the power of three moles PB and 032 divided by not point. Not 385 liters. Which leaves me was not point not 35 p b two plus

So in the first part, where we are calculating the amount of P B I to formula. So we have is 461 multiplied by 2.5, divided by 331 g on that is equal to 3.5 g. So that is the fast part done in the next pop. What we're calculating is similarity of a No. Three minus solution that is equal to 9.98632 Following this, the majority of the K plus there's not 0.108 Next we have the majority of my miners. That is not a point, not to 16

So in the first part, where we are calculating the amount of P B I to formula. So we have is 461 multiplied by 2.5, divided by 331 g on that is equal to 3.5 g. So that is the fast part done in the next pop. What we're calculating is similarity of a No. Three minus solution that is equal to 9.98632 Following this, the majority of the K plus there's not 0.108 Next we have the majority of my miners. That is not a point, not to 16


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