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If you mix 30.3 mL of 0.320 M solution ofK2CrO4 with 48 mL of a 0.320 M solutionof AgNO3, what mass in grams (g) ofAg2CrO4(s) (MM=331.732 g/mol) is formed? Giveyour...

Question

If you mix 30.3 mL of 0.320 M solution ofK2CrO4 with 48 mL of a 0.320 M solutionof AgNO3, what mass in grams (g) ofAg2CrO4(s) (MM=331.732 g/mol) is formed? Giveyour answer with three digits to the right of the decimal point. Nomarks for the unit.2AgNO3(aq)+ K2CrO4(aq) →Ag2CrO4(s)+ 2KNO3 (aq)

If you mix 30.3 mL of 0.320 M solution of K2CrO4 with 48 mL of a 0.320 M solution of AgNO3, what mass in grams (g) of Ag2CrO4(s) (MM=331.732 g/mol) is formed? Give your answer with three digits to the right of the decimal point. No marks for the unit. 2AgNO3(aq)+ K2CrO4(aq) → Ag2CrO4(s)+ 2KNO3 (aq)



Answers

If 25.0 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.842 g of precipitate, what is the molarity of silver ion in the original solution?

First thing we will do here is to dissolve this compound in border will miss it, the conductors to see if the solution carries and electrical current. If solution is conducting, then we can determine whether the solution is a strong or weak electrolyte. By comparing its convicted, it's with that off unknown strong electrolyte, or it can also be done by using the APP critters shown in a textbook.

The balanced nutrition is CSL to win acquis solution, plus to a general thing in a quick solution gives calcium nitrate in a quick solution and select chloride as solid precipitate. We need to determine the limited reactant here. 80 plus unsealed my NASCAR mine in one issue one more relation to produce agency. Let us calculate the amount off 80 plus NCL miners in the solution moral of easy Plus in the solution will be 1.50 into 10 part minus three more 80 place and more off seal minus will be 9.0 multiplied by 10 par minus three more seal miners. It is clear here that a d n a tree is a limiting the active. Therefore, only 1.50 multiplied by 10 point Ministry Mullah Free Giselle Conform which converted toe mass will give 0.25 g off ages seal

Okay. Question that everyone should be. Won't give up to a set of solution. Study mu of casual. All right, boy, one by boyfriend. Find him. And another one fitting me. We'll see when I Dre by one by 1 a.m. and we need to find a myself. Civil law gray civil arrive precipitate. And before we do guy, we don't eat some creation. We have to fight, which was a limiting reactant. And I said you guys should come like the more off the something first because we started right Our equation. Okay, we remember what this formula, Amigo. And over v So answer me. You go m v by so on this formula, we can copulate Qassam, Lawry and silver nitrate. Remember, you have to come for the military to two later before we do it. Why? Because modularity is moreover leader not moreover, merely leader. And after we calculate, is that the more off Qassam Lawry amount and we're mouth ups, even nitrate. Then we write equation, we try a question. So we had to fight of more radio off the southern in the equation from the small radio, we should find which one limiting reactant And you can tell here if we had two months off silver nitrate, we've got only one month causing all right. And now if we have one boy, If I come 10. 33 more Silvani. Dre. So we only got seven. Boy, if I Tom finality folks because you know right, so this speed a limited So that's why Because because, you know, right reaction react when the question less than the amount costume. All right. They give us so calcium. Nora is a set creation and silver nitrate limiting reactant. We calculate the we also calculate US amount of silver. Glad I to and we had the same a mouse. Even I Dre more how you can get this number. You have to do some light here, but it's on the equation. OK, make those. And now we have they give us one boy if I time 10 ity more civil and I j and this equation we had two month cause, you know, right? Hi. No, it should be there that this to ma goes um Lawry and we had revival. Two more civil and I trade. We do conversion. We go cross. Okay, because it this syrup ocean, No radio. So we will have seven. Boy, if I zero Tom Kennedy for well, and this in it will want to aggressive On I drink we do in the same way. Yeah. And now And ive I fall divided by one more silver nitrate and we gotta send a Mao. And now we just have to find a mass off the civil floor. I receive you today. It go by Eva to be going more Suva night work. All right, Tom. Mother, must we do many time before? And what can we have? We should have Boeing 50 time 10 93 mall by the time for then I got with this. So was you have Unless he do 15 5 10 They got the Oh, but, uh, I forgot the but this one. Time for 3 to 32 cramp over, More off civil and I dry, okay? And so that this one should be You go and we have Well, I boy 215 grand

Series are given data and I just like to highlight what the reaction actually as we have A G. And it was three knee acquis phase at K C L. Also in the acquis phase that is in equilibrium with a G c L. Solid phase at K N 03 in a crisis phase. So from this reaction we see one more of a G n 03 that is able to react with one mole of KcR. So what we can fastly do is calculate the number of moles corresponding to the 15 mL of not point to mola a G N 03 solution. So the polarity is equal to the moles of solute divided by the volume of solution and liters. So we can rearrange for the moles of solid that is equal to the polarity 9.200 more like multiplied by the volume of solution and liters multiplied by not point not 150 liters. What we get is not point not not 300 moles. So we have not point not, not 300 miles of a G N 03 that can react with not point not not three zeros over miles of K C. L. Because we're considering the 1 to 1 stroke geometric relationship. But the massive castle is equal to the malls of cases multiplied by the molar mass of K. C. L. Where the mother massive Kaycee ellis 74.55 g per mole. So the massive K. C. L. Is equal to the moles not point not not 300 moles multiplied by the molar mass 74.55 grand mal. That gives us not 0.2 to four g. So here we have not 40.224 grounds of K. C. L. That we need to precipitate the silver irons from 15 mils of not 150.200 ramallah A G N 03


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