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Scientist measures the standard enthalpy chang= for Ihe following reaction134.7 kJNINO,(aq) ~NO(g) + 2 HzO()Based on this value and the standard enthalpies of forma...

Question

Scientist measures the standard enthalpy chang= for Ihe following reaction134.7 kJNINO,(aq) ~NO(g) + 2 HzO()Based on this value and the standard enthalpies of formaticn for the other substanees the standard enthalpy of fortnation of NHANOs(aq) is kJlmol:

scientist measures the standard enthalpy chang= for Ihe following reaction 134.7 kJ NINO,(aq) ~NO(g) + 2 HzO() Based on this value and the standard enthalpies of formaticn for the other substanees the standard enthalpy of fortnation of NHANOs(aq) is kJlmol:



Answers

The standard enthalpy change for the following reaction is $436.4 \mathrm{~kJ}:$ $$ \mathrm{H}_{2}(g) \longrightarrow \mathrm{H}(g)+\mathrm{H}(g) $$ What is the $\Delta_{f} H^{\circ}$ of atomic hydrogen $(\mathrm{H}) ?$ (a) $872.8 \mathrm{~kJ} / \mathrm{mol}$ (b) $218.2 \mathrm{~kJ} / \mathrm{mol}$ (c) $-218.2 \mathrm{~kJ} / \mathrm{mol}$ (d) $-436.9 \mathrm{~kJ} / \mathrm{mo}$ Determine enthalpy of formation for $\mathrm{H}_{2} \mathrm{O}_{2}(l)$, using listed enthalpies of reaction :

So we are provided with four equations in total, adding equation 23 and four. The new formed equation will be ESP lust two or two less edge, too gives out s 03 Unless it's to on the new change in Intel, B will be negative. 6 81 0.5 Killer. Jules, we calculate the intel appear for the action. So we have calculated changing and tell a few off the reaction the new Intel opinion is represented. So now we add equation one and five. So the new equation after adding those will be s plus two or two. Let's edge too. Give us X two s or tree on the new change in and tell people basically negative. 909.3 Killer Jones.

Hello students in this question we have to calculate the and help your formation of the reaction. Okay. So we can write that and help your formation for the reaction. It is equal to and help your formation for the product minus and tell the information for the reactant. Okay, so we can substitute the values So for the NFL free dental P. Of four missionaries minus 113 plus and help your formation for the HF. It is three more blurb- of to 69. Okay. And- And therapy of formation for the reactant and reactant has only -3 which has been formed. So it's in therapy of formation is -46.2. So after solving the situation we get and therapy of formation for the reaction is equal to -873.8. Kill a dual mode. Okay. So it means from the given options option B is the correct answer for this problem. Okay. And in the product we have have to chlorine gas which has been not formed because it is in the original form. So it's entropy of formation will be equal to gear up. That's why it has not been included in this reaction. Okay, thank you.

Were given to reactions on were asked to solve for the Delta h of the other reaction for this is just a traditional Hess's law calculation. The two reactions that are given to us are two moles of S 02 plus two going to two moles of eso three Delta H Negative 1 96 a fourth of a mole of s eight solid plus three moles of +02 going to two moles of eso three Delta H is negative 7 90 killer jewels. If we reverse the first reaction, multiply it by 1/2 which is what is necessary in order for us to get eso to product and in the target reaction we need s 02 as a product. That's why we need to reverse it within divided by two. Because we only need one bowl of eso to and we're starting out with two moles of eso to so we'll reverse it, multiply it by 1/2 and get this chemical reaction with the Delta h of positive 1 96 divided by two. Then for the second reaction, we're going to need to multiply it by 1/2 because we need to have 18 of s eight on the react inside. Where we do that, the Delta h will then be negative. 7 90 Then we can sum up these reactions and the eso threes will cancel. We had three halfs of 02 here and 1/2 of 02 here, so 1/2 will cancel from both of them. Remember, because this reaction reversed and what we left with just one mole of 02 So we get our 1/8 mole s eight and one mole eso to reacting to get so I want eight ball s eight and one mole. Oh, to react to get one mole of eso to to sum up our modified don't each values and we get negative to 97.

Oh, so today we're going to be calculating. That will be a formation of, ah, chlorine oxide using the bond and trophies of Corinne oxygen, chlorine, chlorine, oxygen and client oxide. So, first we're going to write the reaction that is taking place. So have to chlorine. Their decline is die atomic. It's bonded to each other. We have not a die atomic oxygen, and then we're forming to Klein Oxides. So we're breaking one coin bond court coin coin bond breaking one oxygen oxygen bond informing too cloying oxygen bonds. So this is for two chlorine oxygen's. So this would be to time understood until P information. So it would just be the bonds that are formed, which takes energy and subtracting the energy that is released from the bonds that are formed. Formed so bonds broken, subtracting bonds formed. So we have 246 to 0.7 plus 498 0.7. Then we're subtracting to 206. And so if we do some math and we see that we have 329 0.4. So now, since this is for two molecules of chlor ide ox, chlorine oxide we divide by two. We see that we have 164 0.7 killer jewels. Permal. And since this is a positive quantity, this isn't endo thermic reaction and requires energy.


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