So for this problem, You have three different constitutionalist summers of a means with the structural formula of C3, age nine. And and you want to rationalize why these different structures have such variations in their boiling point. So remember that when you're thinking about boiling point, you have a higher boiling point is going to have stronger hydrogen bonding. And you're going to have this hydrogen bonding between and and hydrogen on the same molecule. So it's going to hydrogen bond with itself. So when you're looking at these structures, you have, In all three cases, you have been nitrogen in terms of this trim ethyl amine, there are no hydrogen for it's a hydrogen bond with. So because there are no hydrogen bonds, you know, it's going to be very easy to kind of break apart this structure, allowing for lower boiling point and by break apart the structure, I mean kind of break apart bonding or the attraction between one molecule of try muscle. I mean to another molecule try muscle, I mean, however, when you have Um problem in which is the boiling point of 48 And your ethyl methyl amine which has a boiling point of 37, they are considerably higher. And this is because both of these structures can form hydrogen bonds um within with themselves. However, because your proposal, I mean this is a primary, whoops primary mean, and this is the secondary I mean, and then this is a tertiary, you mean your primary mean is going to be less hysterically hindered. So because it's less hysterically hindered, it's going to better be able to form hydrogen bonds. So it's going to have a higher boiling point then your secondary mean? Which now has a little bit of Starik hindrance, but it still has a pretty high boiling point. But just know that you know, as you kind of get a more substituted I mean, so as you increase substitution, you're going to have a decrease in your boiling point.