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Question

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Answers

Phase and Phase Difference A pair of sine curves with the same period is given. (a) Find the phase of each curve. (b) Find the phase difference between the curves. (c) Determine whether the curves are in phase or out of phase. (d) Sketch both curves on the same axes. $$ y_{1}=20 \sin 2\left(t-\frac{\pi}{2}\right) ; \quad y_{2}=20 \sin 2\left(t-\frac{3 \pi}{2}\right) $$

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This question were given an equation of the form. White was a sine omega T minus fee, two equations of that form. We have to find the phase. These difference between the two equation were given, and we have determined whether they're in and out of fades. And then we have to sketch them, find the figures. We're gonna be looking for the number that's in the fetal position. So in the 1st 1 that's going to be high thirds for the second equation. High over six is in thes position, so the phase is high over six. To find the phase difference, we're going to subtract this. You're gonna have pie thirds buying his Pirie six in the equals high over six. So that's going to be the phase difference. Since the phase difference is a non equal to zero, the two curves are out of phase. We can see that whenever we graph it. So here, if we look at this graph, we have the first equation being the red curve, and the 2nd 1 is the blucher, and you can see that they're out of phase

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In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.


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