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Uonenba |eIquaaJJIP 041 jo uonios 2 SLEAtoS'SHd(x_a+xae) E +Ke + = SHTxewakkuxa ZMMNNIxecnKe + ^ uonenba IeqJuaJayip 34} Jo uonnios 2 S! XE_?HHKey Mous)...

Question

Uonenba |eIquaaJJIP 041 jo uonios 2 SLEAtoS'SHd(x_a+xae) E +Ke + = SHTxewakkuxa ZMMNNIxecnKe + ^ uonenba IeqJuaJayip 34} Jo uonnios 2 S! XE_?HHKey Mous)

uonenba |eIquaaJJIP 041 jo uonios 2 SLEAtoS 'SHd (x_a+xae) E + Ke + = SHT xewakkuxa ZMMNN IxecnKe + ^ uonenba IeqJuaJayip 34} Jo uonnios 2 S! XE_? HHKey Mous)



Answers

$$ \mathbf{u}=\mathbf{i}+2 \mathbf{j}-2 \mathbf{k}, \quad \mathbf{v}=4 \mathbf{i}-3 \mathbf{k} $$

It was valuable, but iyc agenda I rest three j minus two Gay How can register and you know, 13 months Q And if it'll be we crocheted to I minus tree K. I can understand you choose romanced three and from here you can find the length on a better A by phone Long interpreted the one square best three square plus minus two square Then we get Nico Junior square Root off the 14 something for the be getting Could you square it under two square Best their square vestments three square and event in coach in the square Root on uh, Dean um recording the because I am the angle which Ilija vetters in coaching Ida B over the Lanham that many times their land and be so I dont be we get a culture one times two plus three times There are blessed minus two times with the ministry they running bind a square under 40 in Times Square on a 13 And now on the tom again, Echo Children two plus six They could you ate dividing by the square root on, uh, far too many times it could you one I did. You doesn't mean stand the angle. Tita echoed a course. I inverse off the eight over 182 and then we get a good Jew. Go sign DOESn't equal Jew £53.63 degree.

In this problem, I'm writing the Got it reaction. So just look at it carefully. The correct reactions are he had assad CO three solid plus K to Seattle flowers plus a C. Oh, it will react to form no PPT. So this is a corrective statement as well as Bs here, too. Plus a C. O reg plus get to see God or forward will react to form yellow PPT. So option A and D. R. Correct here.

So in this question, we had asked to calculate the Q value or the energy released in this reaction, uranium 2 35 plus a neutron goes to rubidium 93 plus CS 1 41 plus two in your account. So the Q value in this case would be The mass of uranium 2 35 plus mass of the neutron minus Mass of Rubidium 93 minus mass of cesium 1 41 -2 times the mass of neutral. And this whole thing multiplied by C squared. And so looking up the values from the question and appendix, This cure value comes out to be 179 95. Hey, maybe so, this is the answer for the question.

Okay. So for figuring out whether a symbol replacement reaction is going to occur, the first thing you want to do is figure out if aluminum is going to be reactive enough to replace your lead. So if you look at the table of the book, you can see that because aluminum is higher up in the table, it's going to be more reactive, and so it can react with anything that's under it. So one of the elements that is under is lead, so you know that this reaction is going to occur. So yes, you will have a single replacement reaction. So the next thing is that in a single replacement reaction, this aluminum is going to be taking the place of lead. So now, for your product, aluminum is going to be forming new bond between your N 03 And so for this, you know that aluminum has a charge of plus three. A nitrogen has a charge of negative one, not nitrogen, but I know three as a whole has a charge of negative one. So in order to balance this out and make this neutral compound, we just need to add subscript of three And now this aluminum nitrate. We're also going to add solid lead, So this is going to be our reaction. Now we want to go through and balance it out. So if you look in our reactant ce, we have two moles of n 03 and in our products we have three. So least common denominators for coefficients will add a two in front of our aluminum nitrate and a three in front of our lead in a tree. And so now we have n 03 is balance on each side. So now we just have to balance out our medals. So aluminum, we just have to add it to and for our lead. We have to add a three and we can also double check that we have the lowest rate of our coefficients because we have a ratio of 2 to 3 to 2 to 3. There's no way to reduce that any further. So we're good


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