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You are on a foreign planet (let's call that planet Alzoc III).Alzoc III has no atmosphere and thus no air resistance. You drop arock from a height of 1.0 m. I...

Question

You are on a foreign planet (let's call that planet Alzoc III).Alzoc III has no atmosphere and thus no air resistance. You drop arock from a height of 1.0 m. It reaches the ground after 0.5 s.What is the gravitational acceleration on that planet? (inm/s^2)Please show work and explain!

You are on a foreign planet (let's call that planet Alzoc III). Alzoc III has no atmosphere and thus no air resistance. You drop a rock from a height of 1.0 m. It reaches the ground after 0.5 s. What is the gravitational acceleration on that planet? (in m/s^2) Please show work and explain!



Answers

A 15-kg rock is dropped from rest on the earth and reaches the ground in 1.75 $\mathrm{s}.$
When it is dropped from the same height on Saturn's satellite Enceladus, it reaches the ground in 18.6 $\mathrm{s}.$ What is the acceleration due to gravity on Enceladus?

The first step is to find the initial height that the rock is dropped from and so on. Earth we have time of scent is one point seven five seconds. The acceleration is nine point eight meters per second squared. The initial velocity is zero meters per second and find the initial height. We're going to use the can back equation next. My sex not is equal to be not times time plus one half. So our Asian Times, Times Square x, my sex not as are unknown and so this is equal to will be not a zero. So that turned us away. So we had one half times nine point eight Time's a time squared and we employ this into the CAC there you get roughly fifteen meters and so we know that the rock on the moon is dropped at the same height and so it's going to drop to fifteen meters. So now we know x my sex nine is fifteen meters. We have a new time and that's eighteen point six seconds. Our initial speed is still zero because being dropped from rest and now accelerations air on them. We're going to use the same chromatic equation, except we have a different unknown. This time it's still exploited Sex not is he could've beena t plus one half. So a Russian times time squared. So you have fifteen is equal to one half a eighteen point six squared and then we sell for a We get zero point zero eight seven meters per second squared, and that's the final answer.

On the surface of the miles the position of rock and written, it's the initial question of raw Plaster, initial velocity of the rock and the time T -1 of the gravitational acceleration of MARS MGm into the square. And since the initially the rock was released address, so we can neglect this term and when the rock hit the Martians office, we can also neglect. The final version is zero. And from this the initial portion of the rockies half of the gravitational acceleration of MARS GM. And to that I'm a false square. Now we can substitute the values so half of the gravitational acceleration is three point 699 meters per second squared Into the time of all. That is 0.81 9/8 sq. Or the initial position is equivalent to 1.243 m. Or we can say the height of fall for the rock is 1.243 m.

Geo the planet is given by. There's a constant mass upto planet over radius of the Fanis. Where of that? So that 6.67 times stand to the negative to seven guys. We are trying to find the mass of the planet so massive that cops out to be gravity of the planet that is of the planets pled invited by G equals trying for any times radius what for? Two times 10 to the seventh square of that divided by 6.67 That stands, does it? It was three boy A a. Then stand to the 25 you know that.

The discussion were simply comparing the acceleration due to gravity between off and settled. Sudden Ah, Moon called Enceladus. So you have and unknown height, Debbie. I actually releasing the rock from now. Given that on the off we know the governor, he's 9.1. You just for a second square acceleration on enough. He should be refined. What? I see height using the question s goes to U T plus half a T Square. So the initial velocity zero So they stop me. Cyril, if halftime snipe 0.81 times they told the time off. 1.75 squid. So evaluating this, we should get a height off about 15.2 Meet us by using this site. We can Then look at what I see. Acceleration on ah and sliders. Using the same equation s goes to ut puss half a T square. By this case, we are using the Antone G due to from and so this It's just another on fine and all t In this case, the time taken. It's given us 18.6 seconds. So if you reject this should get g two b 0.6 Tesco second screen


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