5

E8 IR F H 1 1 0 1 [ U [ 1 Ifh {} 004 1 7 { { [ 3 1 # { 8 L li 1 1 1 il 1 0 1 ] L | # 37 4 3 FLF 1 1 5...

Question

E8 IR F H 1 1 0 1 [ U [ 1 Ifh {} 004 1 7 { { [ 3 1 # { 8 L li 1 1 1 il 1 0 1 ] L | # 37 4 3 FLF 1 1 5

E8 IR F H 1 1 0 1 [ U [ 1 Ifh {} 004 1 7 { { [ 3 1 # { 8 L li 1 1 1 il 1 0 1 ] L | # 37 4 3 FLF 1 1 5



Answers

$\operatorname{Lt}_{x \rightarrow 2} \frac{x^{2}+2 x-8}{2 x^{2}-3 x-2}=$ (1) $\frac{1}{5}$ (2) $\frac{6}{5}$ (3) $\frac{3}{2}$ (4) $-\frac{1}{6}$

So in the given question we are told that there is an expression that we need to evaluate which has given us limit of eggs. Thanks to two Of X. to the power -8 Names, One by 2 56 Divided by X -2. So this is what is given. And we need to find the value of this expression right? So we can use a property or formula by which we can right limit of ex tends to A of X to the power and -8 to the power and is divided by x minus A. Will give us the value of this expression as and times and pains A to the power and -1. So we're going to use this formula or here. So what we should know over here is that over here? It is the numerator is X to the power minus eight minus one way to 56. Right? So this can be written as limit of ex tends to do X to the power -8 2. 56 is actually the eighth Power of route A great power of two. So we can write one point to 56 us to to the power minus eight and it is divided by X -2. So now according to this property, the value of this limit would be equal to 10 times 8 to the bar and -1. And over here is eight times a is 22 to the power minus eight minus one, which would be well to minus eight. Do I did bite two to the power lion. Right, So this is the required answer. And now when we take two to the Power in iron, what we get is yeah 512. And before that we can write eight as to Cube. So two cubed, divided by tourist to -1, divided by tourists to six and two to the power six is equal to 64. So the required value of this expression is -1 divided by 64. So I hope you understood the method. Thank you.

To find these two matrices together. Here. First thing we need to do is check the dimensions will work. Okay? First matrix we've got is two rows three columns. That's a two by three. The second matrix is a three row one column matrix. These inner two dimensions have to match which they do. That means is a resulting matrix will be dimension the outer dimensions. Okay, So we're gonna have to buy one. Matrix is our answer just two spots here. Okay, we'll fill in the first spot. This is gonna be row one. Column one. Okay, so everything in row one thinks everything in column one negative one times six plus zero times negative four plus seven. Thanks one. Okay, this should give us negative six plus zero plus seven. That should give us a one in that first little spot right there. Okay, The second guy this is gonna be row two column one. Okay, so we're gonna take everything in row two times that same column right there. So three times six less negative five that was negative for plus two times one spent 18 plus 20 plus two should give us 40. Okay? So one in the first row, 40 in the second round, and that is the result of this modification.

So in the living question we are told to evaluate Limit of ex tends to one of the expression X cube -6. X Square plus 11 X -6, divided by x squared minus five weeks plus four. So first what we should do is to just substitute the value of one in the numerator and what we would get is one cube as 11 minus six times one square six plus 11 times one as 11 minus six. So what we would get is 12 -20 which is equal to zero. So what it means is that X equal to one or the value one? S a route of the cubic equation which is given an Which is given in the numerator. Right? So in order to find the other factor of the cubic equation of the numerous active, we can divide it with X -1. So when we divide it with X -1 the cautioned what of this division would be required factor. So in order to eliminate X cubed first we are going to multiply x minus one with X squared. So we have x cubed minus minus one times X squared minus x square. And then we subtract these storms. We would have zero minus six X squared minus of minus x squared minus six X square plus X squared which is minus five X square. And then we have 11 x minus six. The next step we are going to eliminate minus five x minus five X square. So we are going to multiply x minus one with minus five X. And we would have minus five X squared plus five X. Which would be equal to zero. When you subscribe this we would have zero plus 11 X minus five exist. 6. 6. Right so plus 6 6 -6. And in the last step, in order to eliminate success, we multiply x minus one with six and what we have is six x minus six and the remainder is zero. So they required expression of the numerator in terms of its factors as x minus one times X squared minus five X plus six. So in the next step, what we do is we have now simplify the numerator. So let's now simplify the denominator. Right? So the denominator is the denominated is given us, the denominator is given us X square minus X squared exclude minus five X -5 X Plus Forward. So this would be an equal. Do what? So this can be written as x squared minus for x minus x plus four which we can simplify and write us x times x minus four -1 times x -4. Which would be equal to X -1 times X -4. So now the expression given the question can be simplified and written as limit of extends to one Of X -1 Times The Numerator is X -1 times x minus one times x squared minus five X plus six. So we can write it over here, X squared minus five weeks plus six. Right X squared minus five weeks. Last six, divided by X -1 times x -4. So we can cancel the common factors from the numerator and the denominator. And what is left is this expression for which the value can be calculated by just substituting the value of X as one. So we would have one squared minus five times one plus six divided by one minus four, which is equal to six plus one is 77 minus five is two and one minus For S -3. So the required value of this expression would be -2, divided by three. So this is the required value. I hope you understood the method. Thank you.

Matrix modification here. This time we got the zero matrix times F. Okay, If you don't already know the zero matrix times anything, we'll leave the zero and all of our spots. We'll just see why hand. Okay, so let's go through and do matrix modification. Row one, column one, zero times three. Zero times negative one. We know that's going to be zero. Okay, next spot in top right. Row one. Column one. Well, that's the same calculation. We just did we know that's going to give us zero. Okay, we can avoid a little bit of work there. Bottom left road to column one. Again, the same calculation we've already done because of how the numbers are falling here. The multiplying by zero in each spot is given a zero everywhere as well. Okay, last time, row two, column to again, pretty easy to see. That's gonna give us there. Okay? It's the same with real numbers at multiplying zero by anything, we'll give you zero. Just in this case it gives us the zero metrics rather than the real number zero.


Similar Solved Questions

5 answers
# Hii 8 } 8 H 1 IH Iz 83 1 20 1 1 2 1 1 1 1 1 1 iim I 28 Il 22 1 U 1 1 1
# Hii 8 } 8 H 1 IH Iz 83 1 20 1 1 2 1 1 1 1 1 1 iim I 28 Il 22 1 U 1 1 1...
5 answers
QUESTION 16Compute the Discriminant_x2_ 3x-3=0 21-3~21
QUESTION 16 Compute the Discriminant_ x2_ 3x-3=0 21 -3 ~21...
5 answers
Question BWater is pumped out of a holding tank at a rate of Se 0.12t literslminute, where t is in minutes since the pump is started If the holding tank contains 1000 liters of water when the pump is started; hOw much water does it hold one hour later?Question €Use the information given in Question B to calculate the pumped from the holding average rale at which water is tank over the first 30 minules.
Question B Water is pumped out of a holding tank at a rate of Se 0.12t literslminute, where t is in minutes since the pump is started If the holding tank contains 1000 liters of water when the pump is started; hOw much water does it hold one hour later? Question € Use the information given i...
5 answers
3x} = 3t5 #--42 L x2 X-42 +043 2+487'451p)fka}
3x} = 3t5 #--42 L x2 X-42 +0 43 2+487'45 1p) fka}...
5 answers
Obtained at 400 MHz in CDCLChemical Shift (6) Integrated IntensityProton LypeaMultiplicitvb#of protons on adjacent atom(s)
Obtained at 400 MHz in CDCL Chemical Shift (6) Integrated Intensity Proton Lypea Multiplicitvb #of protons on adjacent atom(s)...
5 answers
A gas occupying a volume of $725 mathrm{~mL}$ at a pressure of $0.970 mathrm{~atm}$ is allowed to expand at constant temperature until its pressure reaches $0.541 mathrm{~atm} .$ What is its final volume?
A gas occupying a volume of $725 mathrm{~mL}$ at a pressure of $0.970 mathrm{~atm}$ is allowed to expand at constant temperature until its pressure reaches $0.541 mathrm{~atm} .$ What is its final volume?...
5 answers
Given the equation x =y+v8y- on the interval 2 <y<5 Set up integral for the area of the surfaces generated by revolving the curve about the y-axis. (5 points)
Given the equation x =y+v8y- on the interval 2 <y<5 Set up integral for the area of the surfaces generated by revolving the curve about the y-axis. (5 points)...
5 answers
0 %o % 0 1 "6, 8 2 4 1 9 0 % 8 work - 1 1 1 1 % 2 1 1 8 1 "6, 8 1 1 2
0 %o % 0 1 "6, 8 2 4 1 9 0 % 8 work - 1 1 1 1 % 2 1 1 8 1 "6, 8 1 1 2...
5 answers
Problem 18.A.06Three point charges are arranged along straight line, as shown, with d = 18.5 cm, qB 1.96 pC and 4c 3.87 pC. The total electric force on qc (due to the other two charges) is 3.86 directed to the right: 4A 48 4c2dWhat is 4AHC
Problem 18.A.06 Three point charges are arranged along straight line, as shown, with d = 18.5 cm, qB 1.96 pC and 4c 3.87 pC. The total electric force on qc (due to the other two charges) is 3.86 directed to the right: 4A 48 4c 2d What is 4A HC...
5 answers
Phosphorus pentachloride decomposes according to the chemical equationPCI,(g) = PCI;(g) + Cl,(g)Kc = 1.80 at 250 '*CA 0.2600 mol sample of PCl, (g) is injected into an empty 3.35 L reaction vessel held at 250 "C. Calculate the concentrations of PCl, (g) and PCI; (g) equilibrium.[PCI,]0.002535[PCI;]
Phosphorus pentachloride decomposes according to the chemical equation PCI,(g) = PCI;(g) + Cl,(g) Kc = 1.80 at 250 '*C A 0.2600 mol sample of PCl, (g) is injected into an empty 3.35 L reaction vessel held at 250 "C. Calculate the concentrations of PCl, (g) and PCI; (g) equilibrium. [PCI,] ...
5 answers
(b) Use a graphical utility to find the indicated partial sum Sn10152025Sn
(b) Use a graphical utility to find the indicated partial sum Sn 10 15 20 25 Sn...
5 answers
Find a polar equation that has the same graph as the equation in $x$ and $y$.$$x=5$$
Find a polar equation that has the same graph as the equation in $x$ and $y$. $$x=5$$...
5 answers
Using a random sample (large enough) from a population with aknown standard deviation, we have constructeda 95 % confidence interval for the population mean(μ) as [ 10 , 15 ]. What wouldthe 92 % confidence interval for μ be ifit was created by using the same sample?
Using a random sample (large enough) from a population with a known standard deviation, we have constructed a 95 % confidence interval for the population mean (μ) as [ 10 , 15 ]. What would the 92 % confidence interval for μ be if it was created by using the same sample?...
5 answers
Guntjx vPeirce Jl64t4t} U3a teeto phase malhod t0 !orte Urie Yallbwia Mnx 201 tr2 A83 301 +2r2 tr4 2f1 +12 T1a T2. "3.2 0
Guntjx v Peirce Jl64t4t} U3a teeto phase malhod t0 !orte Urie Yallbwia Mnx 201 tr2 A83 301 +2r2 tr4 2f1 +12 T1a T2. "3.2 0...
5 answers
An initial investment of S3000 grows to S4500 in 9 years in an account that earns interest that is compounded continuously. Find the interest rate as a percentage rounded to the nearest hundredth:
An initial investment of S3000 grows to S4500 in 9 years in an account that earns interest that is compounded continuously. Find the interest rate as a percentage rounded to the nearest hundredth:...
5 answers
1. (6, pS) H Meale Jad is (circle C9k V 3 3V (A)v= (B) vg+0 (C) tC V=6 " (D) +C (E) v %7C27' (F) y #CI #+C
1. (6, pS) H Meale Jad is (circle C9k V 3 3V (A)v= (B) vg+0 (C) tC V=6 " (D) +C (E) v %7C27' (F) y #CI #+C...
5 answers
Find three linearly independent solutions olne given third-orde differential equation and write genera soluton 35 an arbitrary linear combinaton 0fthe252" 1252 =A general solution z) =
Find three linearly independent solutions olne given third-orde differential equation and write genera soluton 35 an arbitrary linear combinaton 0fthe 252" 1252 = A general solution z) =...
4 answers
1 Find the Laplace transform of f (t) = 4 sinh 3t18 e 5t(15 POINTS)2. Find the Laplace transform of f(t) = cos2 2t (15 POINTS) NOTE: Used your Laplace transformation table; be able to simplify your final answer
1 Find the Laplace transform of f (t) = 4 sinh 3t 18 e 5t (15 POINTS) 2. Find the Laplace transform of f(t) = cos2 2t (15 POINTS) NOTE: Used your Laplace transformation table; be able to simplify your final answer...
5 answers
"The structure of polysaccharides is well adapted to serve specific functions within living things; Using evidence from at least two named examples; evaluate this statement: (6)
"The structure of polysaccharides is well adapted to serve specific functions within living things; Using evidence from at least two named examples; evaluate this statement: (6)...

-- 0.020065--