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Nania1L) Write the acid ionization constant expression for sulfate ion. HSO ;, in the ionization of the hydrogen aqueous solution: 1 K [Sox J[H;Ot] [KSO_IH,0h] b. K...

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Nania1L) Write the acid ionization constant expression for sulfate ion. HSO ;, in the ionization of the hydrogen aqueous solution: 1 K [Sox J[H;Ot] [KSO_IH,0h] b. K [HSO; I[H,0] [HSO; ] [HSO4] [HASO, I[H,0 ) [H,SO 4 I[OH ] d. K. [HSO;I0H,QL [HSO;] e K. [SO;I[H;0 ) 12) Consider the reaction NH4CI(s) NH3(g) HCl(g) Ifthe pressure is decreased on an equilibrium mixture of these equilibrium will because three substances: shift to the right; lower pressure favors fewer moles of b. shift to the right;

Nania 1L) Write the acid ionization constant expression for sulfate ion. HSO ;, in the ionization of the hydrogen aqueous solution: 1 K [Sox J[H;Ot] [KSO_IH,0h] b. K [HSO; I[H,0] [HSO; ] [HSO4] [HASO, I[H,0 ) [H,SO 4 I[OH ] d. K. [HSO;I0H,QL [HSO;] e K. [SO;I[H;0 ) 12) Consider the reaction NH4CI(s) NH3(g) HCl(g) Ifthe pressure is decreased on an equilibrium mixture of these equilibrium will because three substances: shift to the right; lower pressure favors fewer moles of b. shift to the right; lower pressure favors g1s more moles of gas shift to the left: lower pressure favors fewer moles of d shift to the left; lower pressure favors more moles Of gS gas unchanged; solid NH4CI does not appear in the cquilibrium constant _ expression



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Given the chemical equation for the ionization of hydrofluoric acid $$ \mathrm{HF}(a q) \rightleftarrows \mathrm{H}^{+}(a q)+\mathrm{F}^{-}(a q) $$ Predict the direction of equilibrium shift for each of the following stresses: (a) increase [HF] (b) increase $\left[\mathrm{H}^{+}\right]$ (c) decrease [HF] (d) decrease $\left[\mathrm{F}^{-}\right]$ (e) add solid NaF (f) add gaseous HCl (g) add solid $\mathrm{NaOH}$ (h) increase $\mathrm{pH}$

If hydrogen sulfate reacts with water in an equilibrium reaction it will produce sulfate and hydro Nehemiah on K. A. Will be equal to the hydro knee um concentration multiplied by the sulfate concentration divided by the hydrogen sulfate concentration. To calculate the hydrogen ion concentration. Without making any assumptions, we need to use the quadratic equation so we'll take the K. Value provided at 1.2 times 10 to the negative. To set that equal to the hydrogen ion concentration squared divided by the concentration of hydrogen sulfate 100.1 minus the hydrogen ion concentration. Using the quadratic gives us 6.5 times 10 to the -3 moller. If we don't use the quadratic and we make our assumptions, we get a ridiculous number of 1.1 times 10 to the negative to Mueller. We can't get a hydrogen ion concentration greater than the concentration we're starting at the error. Then associated with this will be What we got. Making the assumptions minus what we were supposed to get. If we didn't make the assumptions divided by what we were supposed to get times 100 and we get a 69% error

When a reaction is at equilibrium, doesn't matter what type of reaction. In this case, we're looking at an ionization reaction of the weak acid H. N. 02 The if disrupted. When an equilibrium, the reaction will shift in a direction to reestablish equilibrium that partially offsets the disruption. So if we have an equilibrium of H. N. 02 going to H plus an N. +02 minus and we decrease the no. Two concentration. Once it's at equilibrium, we would have generated a hole on the left hand side to partially offset the whole, the reaction needs to shift to the left. If we decrease the H plus concentration, we now have a hole on the right hand side so it shifts to the right to fill that hole. If we increase the No. Two concentration, we've now bulked up the left hand side so it needs to shift to the right to get rid of that bulk. If we increase the No two minus concentration, we've bulked up the right hand side so it needs to shift to the left to get rid of that bulk. If we add something not even involved in the chemical reaction actually, if we add K. N. 02 that's going to increase the No two minus concentration. And when we increase the two minus concentration we bulked up this a right hand side so it shifts to the left, we had something not part of the chemical reaction. No shift occurs If we add solid potassium hydroxide, the hydroxide can actually react with the H plus, decreasing the H plus concentration. If this decrease is we have a hole on the right so it shifts to the right to fill that hole, increasing ph also decreases the H plus concentration, so it shifts to the right.

Let's calculate the concentration of all saw it species in each of the following acids air bases and we'll have to apply the 5% rule to see if the assumptions we make are valid for a we have a weak acid. A 0.92 Moeller hcl Oh, we're told that is a weak acid. We can look up. It's K a value which is 35 times 10 to the negative eight at the the concentration of all species. First by starting to rate, Brown said. Lower equilibrium for a weak acid initial polarity pleader race table. No assumption here We're gonna assume that 0.9 to minus X is approximately equal. The 0.92 and a K expression Que is 3.5. It was 10 of the negative. Eat Yeah, solving for X. I get 1.8 times 10 to the negative five. Let's verify your assumption. Okay, so assumption here 5% of 0092 is equal to 4.6 times 10 to the negative four. So X, which is 1.8 times 10 to the negative five, is less than 46 times 10 to the negative four. Therefore, since it is less according to the 5% wrote, the assumption is valid. And now we can report the concentration of all species the concentration of H 30 plus sequel of the concentration of ceelo minus one. Whereas table this was X which is equal to 1.8 times 10 to the negative five Mueller on the concentration of HCL Oh is equal the 0.92 molars. Our assumption is valid for be We have zero 78 four Moeller C six h five and h two and we're told that it is a weak base for the week base. Well, look up the K B value, which is equal to 4.6 times 10 to the minus 10. Let's calculate the concentration of all species. That's right. The equation for the week base initial polarity is 0.784 Peter a stable here K b expression way. No, the baby values We're gonna assume here E didn't write the assumption here, but we will squeeze it in here. We're gonna assume that 0.784 minus X is approximately equal 2.784 will include that in our expression here, the K B, we found out, was 4.6 times 10 to the negative 10 from the appendix people that x x and our assumption here is 0.784 solving for X. Here we find that X is equal the 6.0 times 10 to the negative six. Let's were this above here. Uh, let's look at our assumption here. 5% of 0.784 is equal to 39 times 10 to the negative three. Therefore, X, which is 6.0 times 10 to the negative six, is less than 39 times 10 to the negative three. Therefore, the assumption is valid concentration of C six, h five and H three plus Z equal to the concentration of O H minus and their ice table. That's they're both equal. The X of these were both equal to 6.0 times 10 to the negative six Mohler and the majority of the C six h five and H two is equal to 2.0 784 Moeller. There would be the concentration of all species proceed, we have weak acid. 0.0 810 Moeller h c n We can look up the value for H C N, which is equal to 40 times 10 to the negative 10. It's Richard Brown said Lowry. Equation for h c n initial polarity. That's your 810 minus x x and x. We're going to assume here the 0.810 minus X is approximately 0810 que c h 30 plus C and minus over eight c N Katie value 4.0 times 10 to the minus 10. Take the x x Clinton 0810 X is equal to 5.7 times 10 to the negative. Six. Let's look at our assumption for the assumption to be valid will apply the 5% rule of 5% of 50.810 and that would be equal to 4.1 times 10 to the negative three. Therefore, X, which is 5.7 times 10 to the negative six, is less than 4.1 times 10 to the negative three, and therefore the assumption is valid, and the mill arat e of the H 30 plus sequel of the military of the CN minus, which is equal to X. These air equal to you 5.7 times 10 to the negative. Six. Smaller The morality of the H. C N equal the 0.810 Moeller for D. We have a weak base. 0.11 Moeller C. H. 33 and we can look up the K B value for this week base and find that the baby value is equal to 7.4 times 10 to the negative. Five. Start by writing a bronze that Lowery equilibrium here over Get ch 33 and each plus and which minus I C e 0.11 Peter writes table one minus x x and X, and we could make our assumption here. Assume that 10.11 minus X is approximately 0.11 K B is equal to C H 33 n h plus Oh H minus over C h that again ch 33 and and our Kate value was 74 times 10 to the negative five Sequel to you x x 0.11 solving for X here with the assumption. We find that it's equal to 2.9 times 10 to the negative three. And let's verify your assumption. With the 5% rule, 5% of 0.11 would be equal to 5.5 times 10 to the negative three. So X, which is 2.9 times 10 to the negative three, is less than 5.5 comes 10 to the negative three. Therefore, the assumption is valid, and the concentration of CH 33 n H plus is equal to the concentration of O H minus, which is equal to X. According to Reis Table. These are both equal to 2.9 times 10 to the negative three Mueller on the concentration of ch 33 and is equal 2.11 Moeller for eat. We have a weak acid 0.1 to 0 Mueller F E. H. 206 to plus and were given its K in the question. It's equal to 1.6 times 10 to the negative seven. It's greater once, said Lowry. Equation here for a weak acid h 30 plus at f E. H. 20 five o. H. And this would be a, um plus one a que? Yes, that would be correct. Initial change Equilibrium. This is 0.1 to 0 00 minus x plus X plus x went 1 to 0 minus x x and x que expression here would be h 30 plus over f e h 205 oh h plus over f e h 20 six two plus on the K A. Here is 16 times 10 to the negative seven sequel. The X x on, um, make our assumption here. We're gonna assume that 0.1 to 0 minus X is approximately 00.1 to 0. So 0.1 to 0 in the denominator. Here, solving for X here will get X equal toe 1.4 times 10 to the negative four, and we'll verify your assumption. Here. 5% of 0.1 to 0 is equal to 6.0 times 10 to the negative three. So X, which is 1.4 times 10 to the negative four, is less than the 5% 6.0 times 10 to the negative three. Therefore, the assumption is valid and the malaria t of the H 30 plus is equal to the majority of the F D H 205 oh h plus just these air body called X 14 times 10 to the negative four Moeller and the morality of the F E H 206 to plus through the this would be equal to 0.1 to 0 Mueller.

Cushion is right ionization equations and ionization constant expressions for these acids and bases. Okay so we know that acid in the reaction donate its matchless and based in the reaction except edge bliss. So now we have first part in the question that is F minus will have reactivity festival. So what will happen? F minus is the best. And as to who will act as a city and we will get HF class and it is liquid. It is reckless. Mhm. Mhm. Okay let's oh that's my list. Okay. As F minus is the base. So KB will be defined for the base. So expression for Tv will be that concentration of the concentration of products yoga, concentration of reactive so concentration of HF concentration of which minus divided by concentration of F minus Here, concentration of S. two will not consider right because pure liquid does not change its modularity as a kilogram is established so as to a molecule were not considered in the expression of KB. Okay. Be part rehab ammonia plus X. To your liquor and it will be established. So ancestry is the best and we will get NH four plus plus H minus and K. B. Will be the concentration of um minus. And it's four plus divided by concentration of Okay in C. Park we have introduced bless extra work. If you live in will be established and we will get at ceo three minus plus. As to your class. It is a quest, it is quest, it is literate and it is happiness. So at 203 will act as here. Yes sir and four acid. We will define A K. A. So concentration of ex ceo three minus concentrate enough to your plus divided by concentration of exports studio. Okay in the part we have That's creepy. 04 plus X. Jewel. And we will get that's too pure for minus less. Extreme. Yes and 48. Yeah. That's two for minus. That's true. Yes. They were everywhere concentration of extreme fear for okay in the back we have acetate. I am. So this will act as a base because they do not have any pathetic I want to donate and water molecule will act as a as a kill them. Well established and we will get acetic acid plus to watch minus. So K. P. Will be defined as watch minus c. s. three syllable language. The bank. Yes it did. I. For F. Part We have S -2. Yes at school. H. Is minus bliss. Well that's tremendous. This is the base and KB will be defined by consent vision of this minus consent region of work minus divide by concentration of S minus. Okay thank you.


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