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Which of the following 'pairs . compounds are isomers? CH3-CH2- 0-CH2-CH3 and CH2-0 - CH2 - CH3CH3CH3-CHz-C- CH3andCH3 - CH2 - CH2- CHOHCH3-C CH2-€ CH-OH...

Question

Which of the following 'pairs . compounds are isomers? CH3-CH2- 0-CH2-CH3 and CH2-0 - CH2 - CH3CH3CH3-CHz-C- CH3andCH3 - CH2 - CH2- CHOHCH3-C CH2-€ CH-OH and CH3 - CH- CH2-C CH3CH3D) CH3-CHz-CH2-OHandCHz-0-CH3CH:CHzOH and HC CH3

Which of the following 'pairs . compounds are isomers? CH3-CH2- 0-CH2-CH3 and CH2-0 - CH2 - CH3 CH3 CH3-CHz-C- CH3 and CH3 - CH2 - CH2- CH OH CH3-C CH2-€ CH-OH and CH3 - CH- CH2-C CH3 CH3 D) CH3-CHz-CH2-OH and CHz-0-CH3 CH:CHzOH and HC CH3



Answers

Which of the following structures are isomers?

Ice Immers or molecules that have the same formula but different connective it ease of the atoms. So if we look at these structural formulas here, which show us how the atoms were combined and connected, we can look at their formulas to see which of these are ice immersed by adding up the number of each different Adam in that. So when we look at our first molecule, we see that contains carbon, and there are 12345 carbons and hydrogen. There are 34 5678 9 10 11 and one chlorine atom. So this is the molecular formula, and this is the structural formula. Looking at the second, we can see that it contains 12345 carbons again or hydrogen are 3456 789 10 11 and one. Corinne. So these two molecules are examples of ice simmers. When we look at the third we see it has 123 for five carbons. We count our hydrogen ins. There's 345 6789 10 11 In one quarry. Also a nice summer. Looking at the last molecule, we count our carbons 123456 We see there are six of them. So already I know this cannot be a nice summer. I finished my formula H 34567 10 13 and one Cory. So the first year I simmers, but the last is not.

For the following pairs of molecules, which are constitutional licenses and which are not a constitutional ice summer. We'll have the same molecular formula, but a different structural formula. So for a who we decide for our formulas on the left, we have C for H 10 and on the right. We have C for H ate. So these are not ice Immers. And the reason why is he have a different chemical formula for be, um, they are ice summers because the both have, um c nine h 20 as their chemical formula there just, uh, oriented in a different way. So that is the definition of a nice summer. Same chemical formula, but different structural configuration for C thes air, not ice MERS, as they have a different chemical formula for three left and right and molecules given. Andi, if we look at, um de, they both have the chemical formula C two h three c l um, but they do differ. Instruction. Uh, they're not ice summers there, actually, identical as there's no, um, difference in a structure, they're both the same chemical formula, correct, connected in the same orientation and then for for e um, thes air. Not I Summers. They have the aromatic ring theano to group. Is that the same position in both? So these air identical there's no difference in the structure is just rotated, um, clockwise. And for it, f we have, um, got the No. Two group in a different position. So these are ice summers of one another. Uh, because seeing chemical formula, But, um, the N 02 group is attached. Yeah, to a different carbon.

The ocean is identify the compound which has a studio center here. Still you center is the center that have Also four different groups. That that's what that center. Okay. So we can observe in the fashion molecules. This is the studio center because four groups there are attached with dead center are different. I represent the time and this complete group in this complete group. Right? In the B option. This thing that is the one center because at this carbon, both are all the food groups are different. Mm This family and blow blow this morning. You have plane of symmetry. That's why this carbon have both of these groups, honesty. That's what will not studio center in the last talks on this centuries viral center The title nine this group and also this group. So correct option will be A. B. Energy. Okay.

So for questions for its asking which of the following compounds has a carbon that is asymmetric. So what that means is that the compound has a Cairo carbon and a Cairo carbon is a carbon that has four unique groups. So, I've already gone ahead and drawn all of the compounds as they were seen in the textbook. And we'll stay with them with question A. So, if we look at this carbon here, it is attached to an ethyl group, a methyl group, a chlorine and also hydrogen that's not shown. So, since this carbon has four unique groups attached to it, it is a Cairo carbon and therefore it's an asymmetric carbon, so A is asymmetric has an asymmetric carbon. B. This card was attached to three hydrogen, so it won't be Cairo this one has two hydrogen, so it won't be Cairo because of the staff for unique groups. So, if you look at this carbon here, it's attached to one ethyl group, but it is attached to to medical groups. and these two groups are identical. So it cannot have four unique groups. So B is not Cairo. So it does not have an asymmetric Carmen moving on to see this compound here. If we look at this carbon, it is attached to a methyl group, an ethyl group and also appropriate group. So three carbon chain in a bromine. So all of these four groups are unique. Therefore, this is an asymmetric carbon part D. This carbon is attached to 123 hydrogen. So this can't be asymmetric. This carbon is attached to hydrogen, so it can't be asymmetric because it cannot have 14 8 groups. So D. Is not and it does not have an asymmetric carbon. For E. If we look at this carbon here, yeah, is not Cairo because it is attached to two ethnic groups. Those groups are the same. So it cannot be attached to four unique groups. So E. Is not an asymmetric carbon. And, lastly, for F, if you look at this carbon here, it is attached to this carbon carbon double bond. Those ethnic groups is attached to a methyl group and N. H. Two and also hydrogen. That's not drawn. These four groups are unique, so therefore F has an asymmetric carbon. So the answer will be a see and, uh.


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