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Suppose you exert a force of 182 N tangential to a 0.26-m-radius solid disk). 74-kg grindstone ( a) What torque is exerted?47.32Nm6) What is the angular = accelerat...

Question

Suppose you exert a force of 182 N tangential to a 0.26-m-radius solid disk). 74-kg grindstone ( a) What torque is exerted?47.32Nm6) What is the angular = acceleration assuming negligible opposing friction?18.9rad /s?What is the angular = acceleration if there is an opposing frictional force of 30 N exerted 1.432 cm from the axis?rad / 8-

Suppose you exert a force of 182 N tangential to a 0.26-m-radius solid disk). 74-kg grindstone ( a) What torque is exerted? 47.32 Nm 6) What is the angular = acceleration assuming negligible opposing friction? 18.9 rad /s? What is the angular = acceleration if there is an opposing frictional force of 30 N exerted 1.432 cm from the axis? rad / 8-



Answers

Suppose you exert a force of 180 N tangential to a 0.280-m-radius, 75.0-kg grindstone (a solid disk). (a)What torque is exerted? (b) What is the angular acceleration assuming negligible opposing friction? (c) What is the angular acceleration if there is an opposing frictional force of $20.0 \mathrm{N}$ exerted $1.50 \mathrm{cm}$ from the axis?

So let's first take the moment of inertia of the disc of the grindstone, which will model. That's a solid disc and so the moment of inertia. But this could be 1/2 times the mass of the disc, times the radio to the discus squared. This would be 1/2 times 75 kilograms, most applied by 0.28 meters. So let's take the moment of inertia. So let's first find the moment of inertia for the grindstone disk, the moment of inertia for a discus equaling 1/2 times the mast of the the mass of the disc times the radius squared, quantity squared. This is equaling 204 kilograms meters squared, and so we can say for part A, the torque would be equaling the force. So let's first find the moment of inertia for the grindstone disk, the moment of inertia for a discus equaling 1/2 times the mast of the mass of the disc times the radius squared and this would be so exerted, and the are the radius of the grindstone. This would be equally 180. Newton's multiplied by 1800.2 eight meters, and this is equaling 50 0.4 Newton meters. This would be your answer four part and this would be so. Let's first take the moment of inertia of the Disc of the Grindstone, which will model as a solid disc and so the moment of inertia. But this could be 1/2 times the mass of the disc times the radius of the disc squared. This would be 1/2 times 75 kilograms, most applied by 0.28 meters quantity and then for part B. So let's first take the moment of inertia of the Disc of the grindstone, which will model as a solid disc and so the moment of inertia that this could be 1/2 times the mass of the disc times the radius of the disc squared. This would be 1/2 times 75 kilograms, most applied by 0.28 meters quantity squared. This is equaling to be when we want to find the angular acceleration. We know that the torque is equaling the moment of inertia, times the angular acceleration. So to find the moment, the angular acceleration this first take the moment of inertia of the Disc of the Grindstone, which will model as a solid disc and so the moment of inertia that this could be 1/2 times the mass of the disc times the radius of the disc squared. This would be 1/2 times 75 kilograms, most applied by 0.28 meters quantity squared. This is equaling 2.94 kilograms meters squared and so we can say for part A. The torque would be equaling the force to be equal to the torque 50.4 Newton meters, divided by the, um, moment of inertia that we have found previously. 2.94 kilograms meters squared. And so this is equaling 17.14 radiant per second squared and e squared. This is equaling 2.94 kilograms meters squared and so we can say for part a, the torque would be equaling, the force exerted and the are the radius of the grindstone. This would be equally 180. Newton's multiplied by 1800.2 eight meters, and this is equaling 50 0.4 Newton meters. This would be your answer for part A. This would be our answer for part B 0.94 kilograms meters squared and so we can say for part A, the torque would be equaling, the force exerted and the are the radius of the grindstone. This would be equally 180. Newton's multiplied by 1800.2 eight meters, and this is equaling 50 0.4 Newton meters. This would be your answer for part a and then for part B and then for part C, they want us to find exerted and the are the radius of the grindstone. This would be equally 180 Newton's multiplied by 1800.2 eight meters, and this is equaling 50 0.4 Newton meters. This would be your answer for part a and then for part B. When we want to find the angular acceleration, we know that the torque is equaling the moment of inertia, times the angular acceleration. So to find the moment, the angular acceleration, this is the net. Ah, the angular acceleration taking account, the frictional force. And so we can say that the network with the equaling the force exerted times are minus the force of friction And times are Sabbar arse of our being the perpendicular we can say our someone other, and then for part B when we want to find the angular acceleration, we know that the torque is equaling the moment of inertia, times the angular acceleration. So to find the moment, the angular acceleration this would be equal to the torque 50.4 Newton meters, divided by the, um, moment of inertia that we have found previously. 2.94 kilograms meters squared. And so this is equaling 17.14 radiance per second squared our someone being a train. When we want to find the angular acceleration, we know that the torque is equaling the moment of inertia, times the angular acceleration. So to find the moment, the angular acceleration, this would be equal to the torque 50.4 Newton meters, divided by the, um, moment of inertia that we have found previously, 2.94 kilograms meters squared. And so this is equaling 17.14 radiance per second squared. This would be our answer for part b perpendicular distance from the point at which the frictional forces acting to the axis of rotation. And so we can say that then this is gonna be equaling. Be equal to the torque. 15.4 Newton meters, divided by the, um, moment of inertia that we have found previously. 2.94 kilograms meters squared. And so this is equaling 17.14 radiance per second squared. This would be our answer for part B and then for part C, they want us to find the net. Ah, the angular acceleration taking account The frictional force 180 Newton's times point to eight meters minus 20 Newton's times 0.15 meters and we find that the net torque is now. This would be our answer for part B and then for part c, they want us to find the net. Ah, the angular acceleration taking account, the frictional force. And so we can say that the network with the equaling the force exerted times are minus the force of friction And times are Sabbar arse of our being the perpendicular we can say our someone other equaling 50.1 and then for part c, they want us to find the net. Ah, the angular acceleration taking account, the frictional force. And so we can say that the network would be equaling the force exerted times are minus the force of friction and times are so far arse of our being the perpendicular We can say our someone rather our someone being attributed meters. And we can then say that this is gonna be equal to the moment of inertia, times the angular And so we can say that the network with the equaling the force exerted times are minus the force of friction. And times are so far arse of our being the perpendicular. We can say our someone other, our someone being the perpendicular distance from the point at which the frictional forces acting to the axis of rotation. And so we can say that then this is gonna be equaling toleration someone. And so now the angular acceleration is decreased. For part C, we have that the angular acceleration someone is now equaling 50.1 Newton meters divided by again 2.94 kilograms. Our someone being the perpendicular distance from the point at which the frictional forces acting to the axis of rotation. And so we can say that then this is gonna be equaling. 180 Newton's times point to eight meters minus 20. Newton's times 0.15 meters and we find that the net torque is now eater squared. And so the anger, that ridiculous distance from the point at which the frictional forces acting to the axis of rotation. And so we can say that then this is gonna be equaling. 180 Newton's times point to eight meters minus 20 Newton's times 0.15 meters, and we find that the net torque is now equaling 50.1. New toleration now decreases to 17.4 radiance per second squared. This would be our final answer for part C that is the end of 180 Newton's times point to eight meters minus 20 Newton's times 0.15 meters, and we find that the net torque is now equaling 50.1 newton meters. And we can then say that this is gonna be equal to the moment of inertia times the angular accepted solution. Thank you for what

I have. Everyone here is given this a having the months six getting on initial Anguilla Validity 3 60 rpm Gloved by direction Radius off is given if you millimeters march This be having the mosque ticketea on initially. Yet it is that wrist that this are brought together by Apply force off until you can So the excel of noticed it So this is the force applied on a origin Please We'll bring it and be together If a picture the picture, it's white bun fight neglecting very friction Fight by a angular acceleration off each final and globality off each there to see it. Why Sim Ping occur A friction Fourth up blood It's applied. So that is and have a gun. But so this could be moment off. Energy off a This will be How am I? A Are a squid six in tow 60.8 the square. So it will be Why do you know 19 toe? You mean square forced a polite on it is be this is the force off beat. Continue Tunisia plight So here it will be a normal election on this will be the friction this is in so submission off course. If the big will get n Scotto, be that it's continued. Friction will be mewing too. Well, newest 0.1 pipe you will get. Did you get no moment of points on a conflict robbed By taking positive? You will get hair into our A B I a. In tow for a substitute. The value and fine course we have, major, you can radius is a 800. That is point, but it is all the time. So it why didn't you eat meat? Moment off. Inner Soviet calculated 0.0 192 in tow Bar A. So from here, angular acceleration off You will get well when fight Radian per second Not similarly on B. This is that re This is the direction off normally action and he edited in order to see you. It's a moment often say you may calculate, huh? Marcel T in tow, RV square mask off. He's given Katie releases while 06 but it's a moment. Don't taste. Why did you do it? You know 54 Caity Peters Square. No moment. Ophuls off about three point contract dropped by sticking positive in tow. R B movies. Curto Ivy in tow. For me, so is three neutral. Radius is 30.6 moment. Often it's already BM calculated. So angular acceleration off beaches, you will get 30.3 of radiant farcically square. This is the answer part. This problem. Thanks for watching.

There is a grinding wheel with a radius of this brought to rest by a friction force. Yes, yeah. The torque, Which is 76 Newton m, is force times distance, So the force would be 76 over our five. That's going to be 217 news and looking in the back of the book. That's correct. Thank you for.

There are people here. It is given this A having the much for pity on the radio. Three and eight millimeter, that is 0.3 m. Find it initial angular velocity. He ended at our beer in group by direction Gets to be having the months 1.6 Katie radius 1 80 millimeter. I'm at rest and is first bad. It is brought into contact. Visited it, knowing that Opie Center friction. And why do you fight between that deflecting bearing friction can play and wheeler acceleration off each disc and for a on Alfa BV have to calculate on the reaction after support. See, this is the support. So reaction courtesy. Let us see it. They got a free body diagram for this could be And the disk it at a fear of the disc Me in the event, baby, don't burn friction Mucha into well and under the action moment Submission of work done by axis V zero. There is no motion along that, but by excess be considered to be what you'd tip submission off their plate. Much to be, you know, so n minus bit. A normal reaction is called Taubate. After this to be that is Marcelo be into G. So friction you will get muche eight In doing that is UK and being duty. No moment for about three point in Contra Prague by we are taking to the positive Never see it frictionless 10 angels Dudovitz torque is developed. All the forces are acting at a point or petition dark. You do them Bill video and that will be I be into well, Bobby Force mucus. Marcia, be into G RV moment off the receptor disco hot Ahmadis quit on solving it. Angular velocity off leaders. You will get rice off empty G upon RV said the city question. But on this will be in counter clockwise direction. No. By using that giving values, you can calculate this value open center attraction is given when three fight acceleration due to gravity. Nine. Point it on your side Audiences given but a few millimeters That is Point Bunny meeting. So it would be 38.1 pipe really in particular square. So this is the one of done apart it no so meat, you know, to be zero because that it's not an engine, was it? And long right? We are taking particulate It's gunmen. Internets have minus reaction. B Bill video. So reaction on me you will get It's going to F and F. It's called toe Mucha and being duty new cage 0.35 Wait off the disc he's given. Sorry, Mark is given 1.6. So on solving it reaction be on the You will get my point for 936 Well in laughter direction now for the disk it This is our disk A f B in this direction. This is a normal reaction on a and it will move in Contra clock direction. This is a thinker. It the moment of forces About a point you can fight. Contract rocked by We are taking positive the addiction into our a movie moment of inertia off disk into its angular acceleration. Friction is Mu Kate. MB and Judy are a moment off. Energia, Huh? Um it audience where? For it. So by solving it and good acceleration off this, you will get so I saw muche it g and be a point. Ari in tow, in contra club by direction. This is the question toe. No, substitute the medic. So from given value Al Fi we can find muche 8135 g. It's 9.8. Must be is 1.6 radius off a 23 weeks masses. For it will be 9.16 radio per second squared. So we can right here and wheeler acceleration off this you will get 9.16 radial per second squared. No, we can complete the reaction remission oak worth it Acting on that disk A along right direction considering toe positive. That must be dio because there is no motion along it. You will get Are it my last f? It's called 20 Just a moment. Have already we have completed for 8.4 night 3 16 different words, right? No, along by exits the mission off all forces on the disc A long right direction to be zero vertically about we consider positive that you would get are a bite movie march off it lesson myself. T that is four plus 1.6 into a 9.8. Yeah, So people get people would point 936 nuclear in a bar direction. Okay, No reaction XY So these are supported acting on T submission off FX but video. So see excellently hero submission off every bite. It's called a hero. So she write his photo. People point 936 Newton. No moment off couple, actually much. Do you know that's all for this problem? Thanks.


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