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Question #: 22 What would be the final product of the following reaction? 1) LiAIOC(CH3l3H CH3NH2 C6HsCOCI 2) Hyot CsHsCHzNCH3 CsHsCH-NCH3 CsHsCHzCHANCH3...

Question

Question #: 22 What would be the final product of the following reaction? 1) LiAIOC(CH3l3H CH3NH2 C6HsCOCI 2) Hyot CsHsCHzNCH3 CsHsCH-NCH3 CsHsCHzCHANCH3

Question #: 22 What would be the final product of the following reaction? 1) LiAIOC(CH3l3H CH3NH2 C6HsCOCI 2) Hyot CsHsCHzNCH3 CsHsCH-NCH3 CsHsCHzCHANCH3



Answers

Complete the following reactions.
$$
\begin{array}{l}{\text { a. } \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}+\mathrm{CH}_{3} \mathrm{OH} \rightarrow} \\ {\text { b. } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{HCOOH} \rightarrow}\end{array}
$$

Or this question were just asked. You complete each of these reactions. So part A, we have a car boxlike asked. Here. I'm gonna go ahead and draw this out to make it easier to see. This is a car buffs like acid and alcohol and will react a carb oxalic acid with an alcohol to get an Astor and water as a byproduct. So that Esther looks like this. We just basically replaced the always here with whatever the alcohol is. So it becomes O. C. H three. And like I said, water is also produced as a byproduct there. And then for part B, we have a similar situation here. So we have our alcohol and another car box look, acid. So this one looks like this, um, And so when we react days again, we're just going to replace the O. H on the carb oxalic acid with whatever is on the alcohol. So that will look like this. And again, we'll get water as a by product. There

In this problem we are given the reactant is to an acid base reaction. And we want to complete and balance the giving chemical equation and also identify the names of both the reactant in the products. So on left hand side here I went ahead and wrote out the two reactors given for the first chemical equation. We can go ahead and name these to react IDs now. So this reactant here is called acetic acid, and the other reacted that we have present here is magnesium hydroxide. Now, in a typical acid base reaction, we end up producing a water and some form of salt. So we know that one of our products is going to be liquid water. And we also know that we're going to donate this hydrogen and basically do a double displacement reaction switch or hydrogen and switch or magnesium. So the salt that ends up being produced is this product here, and by looking at our Celje bility rules, this salt is soluble in water. So now we can name the products that we have listed. We know that this is water and this salt is magnesium acetate. So our final step that we have left is to balance our equation, and we need to look on both little break and left hand side to see where we haven't imbalance of her. IOM's right off the bat. I can see that we have two of these acid Tate ions on the right hand side, while there's only one on the left hand side, so we can go ahead and add a coefficient of to here to balance that out. By doing that, we end up with an imbalance off our hydrogen ions on both sides, so we can remedy that by adding a coefficient of to here to our water, similar to the last equation we looked at. We already have our to react INTs for this chemical equation so we can go ahead and mean these two reactions. This first compound is perk Lorik acid, and the second compound is ammonia, and this reaction is also considered to be an acid base reaction. This ammonia is actually a special base that doesn't look like the typical Basie would see where you have the hydroxide attached to an eye on. So in this case, we're just going to end up with one product by combining these two and by looking at our Celje bility rules in her table, we know that this is soluble with water. We can also name this product that we find and this product is called Ammonium Herc. Laurie, Our last step is to look and see if we have any imbalances on the right or left hand side of this equation. And by the looks of it, we don't have anything to balance. So we're going.

In this problem, the reaction will happen something like this. Let's look at it carefully. CS three CS 2. I will react with alcoholic A ohh, it to give A which will react with we are to BP and which will react with Casey and to give C. And the product. See here, E and CCH two CH two, NC CH two CH 2 CN two according to the option in this problem, option, age, correct answer for this problem.

So what are we going to get if we react this carbon eel? They're beautiful. I mean, so of course this nice region is going to attack. We're going, Tio, lose water and you'll end up for replacing that oxygen with a nitrogen carbon double bond. And you'll end with this. I mean, he can generate an mean only when you have a primary a mean and he can lose two of these hydrogen tze with this oxygen in the case of water. But if we were to react with Dia Philomene, then of course, this is going to react, but you'll only lose hydroxide and you'll be left with this The mini um ion, Of course, it's a mini, um ion is not very stable at all, So we'll go through a tot memorization to generate this in. I mean so again. When you have secondary, it means you'll generate the Inamine we have primary. It means you'll generate the mean And if you have a tertiary, I mean, you'll have no reaction at all. Next we have this and hydride, I knew if we react this with our beetle mean, then we'll just generate our Amit. Yeah, will lose this acid and generates this. Um, I'd In this case, the same thing can occur with our secondary. I mean, because again, we're only needing to lose one of our hydrogen atoms. So will generate a tertiary Hamid and anhydride has the same reactivity as an easel Chloride. It's, of course, where their beetle mean and this pencil chloride, we'll simply generate the secondary and lied. And if we use the awful mean will generate the tertiary, Um, I'd


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