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3. (a) Fill in the blank to complete the nuclear reactionshown. 2H + 3He ==> 4He + ________ (b) Calculate the Q value for this reaction.(c) Assume t...

Question

3. (a) Fill in the blank to complete the nuclear reactionshown. 2H + 3He ==> 4He + ________ (b) Calculate the Q value for this reaction.(c) Assume the 2H particle is a projectile withkinetic energy equal to your first lucky number when measured inMeV and that it is hitting a stationary 3He. Can thisreaction occur? If so, what would be the total kinetic energy ofthe products after the reaction?First lucky number: 6

3. (a) Fill in the blank to complete the nuclear reaction shown. 2H + 3He ==> 4He + ________ (b) Calculate the Q value for this reaction. (c) Assume the 2H particle is a projectile with kinetic energy equal to your first lucky number when measured in MeV and that it is hitting a stationary 3He. Can this reaction occur? If so, what would be the total kinetic energy of the products after the reaction? First lucky number: 6



Answers

Consider the nuclear reaction
$$_{1}^{2} \mathrm{H}+\stackrel{14}{7} \mathrm{N} \rightarrow \mathrm{X}+_{5}^{10} \mathrm{B}$$
where $X$ is a nuclide. (a) What are $Z$ and $A$ for the nuclide $X ?$ (b) Calculate the reaction energy $Q$ (in MeV). (c) If the $_{1}^{2}$ H nucleus is incident on a stationary $14^{\circ} \mathrm{N}$ nucleus, what minimum kinetic energy must it have for the reaction to occur?

For this part correction you define What is the final kinetic energy of the products given that STI unit energy off duty on JC ish too. You, Clay ihsaa 36.3 and maybe find What is he you kinetic energy? Or do you find over the last year I need you find what if the very way we should tell us where the energy is being released or being absorbed by these particular reaction batteries to find a chance You mess. What about by C Square? Did you miss simply thinking the mess off? The initial reluctance minus away. Team s off the fighter products and God might violating by C Square. Well, this messes can be looked up or true on the resources. Let me go to substitute in C Square to be actually 1.5 m e v call you because ah, during the for the mess units, you This will have us to cover into MTV very quickly. It's audio cue value 5.3 to 6 on TV. This tells us that our energy is being released in response motive. This energy is released and given as additional character energy to the final products. And so, given the initial amount of energy we at this value in to get D final kinetic energy, we should get 41.6 MTV.

We want to find out that total kinetic energy off the products of this reaction. So for that, let's find out the Cuba, you, the Cuba, you will simply be acid that you did on us myself. The carbon minus mass of nitrogen minus massive neutron times C squared. Now, by looking up, the Masters will simply have substitute. You know, the Do Theron has a massive 2.1408 to you. Well, okay. The U C square out common. Coughlin has a mass off 13.33 by fight. This is carbon toward Ian, by the way, minus nitrogen has massive 14.3074 documents minus neutron has the mass of 1.8665 Now that we have, this was simply to comfort the sick unity. And for that, we use the tractor. I 31.5 Mega lac on board Or use the square uses queer gets cancelled and we have the total final energy 5.0 55308 Maker Electron Woods. No, this is the amount of energy released just by the reaction when we already have. Ah, 44 point for me, Miguel. A Congolese kind of energy in the reactions. So the total final kind of guarantee off the products will be the some off the school which is 44 14 Let's buy 0.308 Miguel upon worlds, which corresponds to 49 47 mega electron towards

For the following chemical reaction. We wish to identify Nuclear X, which has mass number a importer number zit. So we firstly can see that the mess number a must balance on both sides of the equation. So it must be to plus 14 from the night left hand side, minus 10 from the night inside. And hence we have a mess number off. Six for the unknown nuclear. Similarly, for the proton number, Zed said must be one plus seven, which is a to the left hand side, minus five from the boron, and we're left with three. So we are looking at a nucleus with mass number six and proton number three, and this corresponds to lithium six. So are no nuclear is lithium six. Now. Secondly, we need to calculate the mass decrease and find the energy equivalent off this mass decrease, and so we can tell if energy is released or absorbed by the reaction. So, on the left hand side, we have hydrogen two and nitrogen 14. So the equivalent masses on the left hand side, an atomic mass units from our table is 2.1 for 102 atomic mass units plus the mess off nitrogen is 14 point 003074 atomic mass units and this gives us total mass on the left hand side off 16 0.1 7176 atomic mass units. So that's the left hand sides. Total mess, the right hand side off. This chemical reaction includes lithium inborn. So the mess is of these, uh, six 0.1 51 to one atomic mass units and tim 0.1 to 937 atomic mass units, respectively, and ends the total mass. In the right hand side is 16.2 a 058 atomic mass units so we can see the mess is higher on the right hand side. So this means that energy is absorbed by the reaction and the Q value is the difference in these masses multiplied by C squared so the energy absorbed que is equal to 16 0.1 7176 atomic mass units minus that on the right hand side, which is 16.2 805 eight atomic mass units Time C squared, which is 931.5 mega electron balls, atomic mass unit hands to get so we can see that the energy is negative and against in negative energy off minus 10 0.14 Mega electron False. So if we have a negative mass defect or negative energy, that means that energy is required to be absorbed by the components in the left hand side, unable to form in order to be able to form the products in the night. 10 side. So that's our cue value, our energy absorbed by the action. Now we wish to calculate the kinetic energy ke off the bombarding particles. So the available energy in the collision kinetic energy See KCM in the sent off mess reference fame is late to the kinetic energy ke off the bombarding particle migration 43.24. So the Connecticut need that must be available to cause the reaction is 10 point 14 mega electron volts EV calculated above so OK for the center of mass is equal to 10 0.14 mega electron volts. The mass M off the stationary target, which is nitrogen, is equal to 14. You and the mass little em off The colliding particle is the mass off hydrogen, which is to you so we can use the secretion and we can find the kinetic energy ke off the book body in particle. So this is the creation we're talking about. Okay, Is equal to the mess off nitrogen. That's the mess. Little m off the hydrogen double Bonnie particle divided by the mess off the nitrogen times this kinetic energy K C m. So this is equal to 14 year for nitrogen. Unless to you, for the hydrogen, the diatonic. I was a molecule over 14 you for the nitrogen, and this is multiplied by 10 0.14 Mega electron Voss. So obviously we use cancel for first time and we're left with an energy, which is the energy off the bombarding particles and that's 11 0.59 mega electron volts.


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