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You are Chief Scientist for the Butterfly RestorationEffort to conserve a population of a rare butterfly species. Youare tasked with calculating the number of gener...

Question

You are Chief Scientist for the Butterfly RestorationEffort to conserve a population of a rare butterfly species. Youare tasked with calculating the number of generations for a new SNPallele to reach 10% of the standing variation through mutationalone. Show your work for each question.a. Calculate the number of generations to have afrequency of 0.1 for a new allele in this population. (mutation rate for SNPs = 1 X 10-8 / locus)b. What would be your calculation if thismutation was a microsatelli

You are Chief Scientist for the Butterfly Restoration Effort to conserve a population of a rare butterfly species. You are tasked with calculating the number of generations for a new SNP allele to reach 10% of the standing variation through mutation alone. Show your work for each question. a. Calculate the number of generations to have a frequency of 0.1 for a new allele in this population. (mutation rate for SNPs = 1 X 10-8 / locus) b. What would be your calculation if this mutation was a microsatellite or an allozyme instead of a SNP? Why?



Answers

It has been suggested a population of a flowering plant is being jeopardized by population declines in a butterfly species thought to be the primary pollinator of the plant. Identify data that could best be used to either justify or refute this suggestion.
a. nectar energy provided to the butterfly species per visit to a flower of the plant species in a field
b. number of fruits produced per flower of plants in a section of a field screened off from access by the butterfly species
c. number of butterfly visits per flower per day in various fields throughout the growing range of the plant
d. species of flowers visited by individual butterflies in a field and frequency of visits to each flower species

So we're looking just awful as we read in the laboratory, and these are some 11 million minimum of me. Wait, let point 55 millimeters and not a very system with the right age. I love 0.35 soon points so that businesses want to slip female with ways that our point for two in that makes it with the male. That's 20.56 We got a point for two mating with, uh, 0.56 What a waste. Take the wing that the ball is going to be. If it has a narrow since aerials up one. That's the first question one. And then when this picture was suspected, will you listen the narrow I mean, what's expected? Linguine Salisbury in the narrow sense here built is zero. So we know male deviation. So being 0.56 minus that the meat, which is 55 with this house basement, it gives us what zero What and female deviations will be point for two minus 20.5. This gives us a native because it's smaller than me. And so that tells us that the mean deviation is gonna be 0.1 for us. If I imagine was used as a data 0.6 and then I used to. So I will say one Once I was one template. We know that the narrow senses when that were my environment of after throwing time my jeans and it was speaking. That gives us a 0.6 and the way So I expect the gene. It's one day the points it's making. I stated to Jean let to be equals 25 waas, which equals 0.49 now if we sent H 200 What? We don't have sense calculation. Just think about it, mate. Do anything with zero calculation because remember is gonna be zero time. So in this case basis zero you do zero times because there's nowhere built so nothing can change. That's resulting almost plan this time. Slow math Clearly age to remember one major do have variation to lead zero No, very curious. Always variation. You can't have changed the way to show that that man is just won't fly About 00 you get zero and that needs to be linked with just do point out some that change

This question asks us about fitness in a situation where the Hamas August dominant BB as a fitness of one headers, I guess, also has a fitness of one. But the home is egas. Recessive has a fitness of zero, so those individuals won't survive so and were asked how, um, the population of Q. How Cuba will change? Because, remember, we do have some of meals here of the little be Leo, so they'll be present in the population for a while to come. So remember that fitness. Yeah, I can be calculated just finding the average for this. Ah, using this formula just an extension of the Hardy Weinberg equation and then queues Quito. And it's the fitness of little bee Elio from another Gina type. Now, remember that this is zero, right? So this whole term is gonna drop off when we plug in the numbers, get 0.9, try square. And of course, this is one That's the value right there. So we know it's one. And then to peak you this 0.95 and 0.5 when they count the 95 and five, Of course from the question not not making those numbers up myself. And then times 1.0 and the course that's plus Euro. And if you do the arithmetic here, um, you got 0.90 to 5 plus 0.0 95 So this is close toe one. So it's 10.99 75 And so that's the average fitness for this population. And then we want to figure out how Q is gonna change over time and their different ways to do this. I'm just gonna do it sort of generative Lee, until I actually think that's probably quicker. Um, where we have this formula, uh, over the average fitness. So this tells us the next generations P values based on this generation's P value times the fitness of B, which, of course, is gonna be one divided by the average fitness. And so that's P crime. You called 0.9 Fine. So that's our current P value times one over the average fitness, and that gives us a P prime value of 0.952 And that's going up, which is what we'd expect, right, because the fitness of those air one, of course, the fitness of the B L. E. A list zero. So we expect more and more big ble Osama population. Remember, we can get people's Q equals one so we can just get Q prime my taking one, um minus 29 5 to So when my next 0.952 and that gives the Cirque you prime value of 0.48 so that numbers dropped from 0.5 and then we can do the same thing. We can call this the P two generation Ah, and just start over here. Well, we might want to re calculate the average fitness. It will change, but it won't have changed much. And so it's not really going. Teoh have, ah market impact on our results. In fact, it won't change that much at all. So we just have 0.9975 again and this gives us RP to value. Uh huh. 0.954 for that number is continuing to rise. And if we take it, just do this attraction like we did above the cue to value is going to be 0.0 for six. The second part of the question changes the, um, terms of the problem a little bit in that it makes the headers. I go, um it gives it a fitness of zero, and you conduce the math and it's exactly the same math. Here. You just calculate the average fitness and then calculate with the P and Q values are. But if this is now zero, that means no individuals who have a little be alil in the population will survive. Right? And so once we've done this after in the next generation, um, P will goto one and Cue will go to zero. So and you could get do this show that show it with the math. And I did actually do this. Um, but you can just sort of reason it out, right? Is this. If any individual who has a little little Pia Leo is lethal, lettuce has a fitness of zero. Then in the next generation, no individuals with the little Delia will exist. And so everybody will have the big Bigby. I'm trying little be illegal. The opilio and the only individuals that will survive have the big be Bigby. And so the B will have ah, frequency of one and Q a high frequency of zero

We want to find the sum of the infinite Geometric series 1000 plus 1000 times you plus 1000 times 0.8 squared life. And so what? Basil? From this we can see that our anyone and it's equal the 1000 and our our is equal to zero point. So using the formula for infinite sum, we get us a sequel to Big One over on minus R. So this is going to be 1000 over one minus zero point. So this is 1000 divided glide 10000.2, but this is going to be equal to 5000.


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