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CuncentrationData: Concentration 'NaOH solution, 0.1472MNet Ionic Equation:Trial ]Trial 2Final Vincgar buret reading mL 3350 q.sln SJure + Initlal Vinegar burc...

Question

CuncentrationData: Concentration 'NaOH solution, 0.1472MNet Ionic Equation:Trial ]Trial 2Final Vincgar buret reading mL 3350 q.sln SJure + Initlal Vinegar burct reading; mL 53 ImL 33Sm Sample Volume of - Vincear. 28m 2 AGmL Final NaOH Buret reading. mL LL4ln4 "6 214L [241+bz Initial NaOH Buret reading mL aml 0.41 Volume of NaOH added. mL 12.41 18L Moles of NaOH added_ mol Calculation RequiredMoles of Acetic Acid,molCalculation RequiredConcentration of Acctic Acid MCalculation RequiredA

cuncentration Data: Concentration 'NaOH solution, 0.1472M Net Ionic Equation: Trial ] Trial 2 Final Vincgar buret reading mL 3350 q.sln SJure + Initlal Vinegar burct reading; mL 53 ImL 33Sm Sample Volume of - Vincear. 28m 2 AGmL Final NaOH Buret reading. mL LL4ln4 "6 214L [241+bz Initial NaOH Buret reading mL aml 0.41 Volume of NaOH added. mL 12.41 18L Moles of NaOH added_ mol Calculation Required Moles of Acetic Acid,mol Calculation Required Concentration of Acctic Acid M Calculation Required Avcrage Acetic Acid Calculation Requircd % RAD Calculution Rcqulred Obteral Itions: Contimie han Puz fiedd General Chemistry Laporatory GRU Chm



Answers

Calculate the concentration of an acetic acid solution using the following data. Three $25.0-\mathrm{mL}$ samples of acetic acid were titrated to a phenolphthalein end point with $0.121 \mathrm{M}$ NaOH. The volumes of NaOH were $19.96 \mathrm{mL}, 19.73 \mathrm{mL},$ and $19.79 \mathrm{mL}$

And this problem. We're given a lot of information about a base in an acid and asked to calculate the polarity of the asset. To this end, we're gonna use the equation for malaria and a peaceful to number of moles divided by volume and leaders. I noticed that this equation can be written in three different ways. We can solve for polarity, consult for moles, and Ripe says, and the times, um, is equal number of moles. Or we can call for volume and find the volume A sequel to number of Moles by mole Aridity. These will serve you well as you move through these. Now, I'm gonna go to this thing a lot of detail if you're just here for the solution and you want to see the one step shortcut way of Stoke Yama tree pill tree. Um, but I will take the time to explain each step conceptually. So if you want to skip ahead to the end, you can go ahead and do that. So we have, uh, a lot of information about the space over here knows we have volume and the polarity. So we're gonna use that information to find the missing piece that's the number of mulch to our first step is going to be to find the number of malls of anyway. H the reason why we want more than a wage. Because in this reaction, we're told by nature of the reaction that one more of any U. H reacts with one roll of acetic acid so that I can use the multi more ratio to find malls of the feet of Katherine. So notice that would that does is it gives us more of this substance, and with the volume we can then find the polarity that we're after. So that will be. Our final step is to find similarity up the acid history seal, too. So let's start with that. First, I need my volume in leaders. So this is 0.947 leaders. Polarity it serves us to remember, can be written as you're appointing 00 molds for every one leader. I noticed that when I multiply these together, the leaders cancel out nicely and their product is you're a point. You're a point hero who want each night four well, sodium hydroxide. Okay, now recall that we said that for every one more sodium hydroxide. We have one more of acetic acid, so I don't really need to do any math here. I just know that because of this want to one ratio that I have just as many moves of acetic acid as I did sodium hydroxide. No math involved. I just already know the next step. And then now what? I have multi story of acetic acid volume of the Vedic acid. I confined the polarity by the fighting, given the definition, Willard. So I have 0.1894 more divided by the volume, which in leaders his Euro point Nero to 50 leaders motive units of molds divided by leaders. This is equal to 0.7576 mold over leaders, which is the same thing. Moeller and I'm going to round three significant figures, given that I had three significant for years and all of my initial givens with 0.758 look okay, now let's talk about the shortcut. You have a good grip on all of these things. You can kind of conceptual work your way through it all in one go. So let's start with the volume of acid, just as we did at the top. I have this many leaders of nitric acid, so I need to multiply by the polarity of nitric acid you can treat this polarity is a conversion factor. She could write it either with moles in the numerator, leaders in the numerator and the unit that comes before is gonna guide you. I mean, those us to cancel Next. Remember, we had to change substances. We do that using multiple ratio. One more of acetic acid reacts with warm bowl. Sure, I am. Keep writing H in the three. My God. And the problem back there should be any Uhh you don't really know when will the new age. And finally, I can't divide this results by the volume. Remember, that's for what I have, leader. So your small small This whole product gives me multiple acetic acid and I'm gonna divide mulled by leaders Europe with 0 to 50 beaters, acetic acid solution And what that will give me Smalls, former leaders or polarity. All of that is equal to the same 0.758 Moeller. I don't know, it's the same. I basically did the exact same process the whole way down. This is it in one

In this problem. We're trying to determine the concentration of our So do my drugs, said Solution that we use 28.34 milliliters of 0.1085 Mueller hcl to neutralize. So first we should start by figuring out how many moles of hundreds and house we used to neutralize our solution and we can figure that out by multiplying our concentration. All right, this is molds for leader can multiply this by our volume used two yet the number of moles we used which is 0.0 zoo 30 or seven moles of hydrogen ions since there is a 1 to 1 ratio of hydrogen ions to each CEO. So if we use this many moles of hydrogen ions, we had that many moves of hydroxide ions in our solution. So you know that the concentration of our solution is equal to the concentration of hydroxide ions in our solution, because there's a 1 to 1 ratio which equals the number of moles we used over the volume we had which was 25 milliliters or 0.25 leaders. And this gives us a final concentration of 0.1230 Moeller

So the question here is going to talk about acid base reactions here. So in this case, we have an acid based hydration where we have sodium hydroxide reacting with hydrochloric acid again, both being strong here. So in this case, they're going to go into reaction. And once we do, our substitution reactions, but we're gonna add is assault. So he inquired and water as our reaction products here. So again, for the first part, it wants us to find the moles of hot of protons in HCL. So essentially that's gonna be the as we recall, moles is gonna be the volume times the concentration. So 24.58 over 1000 times 0.102 for be here. It wants us to find a polarity, the moles rather of hydroxide in the n a o H solution. So again, find moles. We essentially need Thio know that in this particular case, um, as we are taking 23.91 minute leaders of sodium hydrogen and that neutralized, in other words, is gonna be at equivalents point of the penetration. We know that the moles of hcl so the moles of hcl is gonna be equal to the moles of N a. O. H. Therefore, to find the polarity, we're essentially going to take our moles here and divided by 23.91 over 1000 here as we have to convert that into leaders. Um, lastly, for part C here, it's asking us to obtain the polarity of N a O H from O H minus. So again, as we know that this is going to be one toe, one reaction C is gonna be equal to the answer that you get to be here.

This question is a titillation calculation question. For arbitration calculations, we need a balanced chemical reaction. So we know the story geometry. The balanced chemical reaction is provided. One mole acetic acid reacts with one mole sodium hydroxide, producing one mole water and sodium acetate. To calculate the concentration of acetic acid. We need to know the moles of acetic acid and the volume of the acetic acid solution. The acetic acid solution is vinegar and the volume of the vinegar was provided. But we do need to calculate the moles of acetic acid. We can do that by starting with the volume of the N. H. O. H. That reacted with acetic acid. We have 16.5 mL, which we can convert to leaders by dividing by 1000. We can then convert the leaders into moles of sodium hydroxide by multiplying by the more clarity of the sodium hydroxide solution. Once we have moles sodium hydroxide, we can then convert it into molds acetic acid, recognizing the 1 to 1 relationship. Now that we have moles acetic acid, we simply divided by the leaders of the vinegar solution. 10 mL is point to one leaders, and we get a concentration of 10.8 to 5 molar acetic acid in the vinegar solution.


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