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HI(aq)+O2(g)→H2O(l)+I2(s)Express your answer as a chemical equation. Identify all of thephases in your answer....

Question

HI(aq)+O2(g)→H2O(l)+I2(s)Express your answer as a chemical equation. Identify all of thephases in your answer.

HI(aq)+O2(g)→H2O(l)+I2(s) Express your answer as a chemical equation. Identify all of the phases in your answer.



Answers

Describe the steps involved in balancing a chemical equation.

And the problem. 11. They give you the picture, right? But we have toe violence in the equation. Usually us close fear No. They send for nitrogen dress They sent for oxygen and white. They send full hydrogen and therefore you can write a question in this element. Single like this hydrazine react with di di nitrogen. Their job side and you get the product is water and magic and gas. They This is unbalanced equation. So before the abandoned question you have tow Tell the number the up atom in both side. Now that the left side and the right side our nitrogen here nitrogen on the left side floor and and the rise I get to also featured on the left side that for and in the rice I got one hydrogen left side fall and writes hi to in this this element because you see on the left off oxygen outnumber the right Sorry the right side off the equation The old sacre is that part number. So I want you balance the autumn above us. That is the rule. So you look for right here, right? So now you count oxygen. Most sign oxygen equal right And now you look at the hydrogen hydrogen because you just put for on the water on you. Count the hydrogen on the left side. The right side, you see? Eight. Then that's the only fall. So you have to go through right here. And now you see the now you can on the left side After you put your belt on hydrogen. Now you can in the left side now becomes sick, right? And adviser, only two. So we have to balance nitrogen for both are equal. So you got three right here. And now you check. Mhm. You check. I think you see hydrogen. 1910. Also region. Now you can hear hydrogen left side Ate rice. I ate right oxygen left side four and rice I four and nitrogen left side. Sick. Right side. Sick. So this equation is balanced.

And this problem were asked to write a balanced chemical reaction for the reaction between men, Guineas and oxygen creating some kind of man Guineas oxide compound. But we're not actually explicitly told what the formula is or the compound were making were given. Information that will allow us to figure it out, though were given a value for the total mass of the compound produced on we're told of that. 1.142 grams is oxygen. That means just by subtracting the mass of man, Guinea's is one point nine six two grands. And that's just by simply subtracting 3.10 for minus 1.142 grids. Okay, now I'm going to go to my periodic table and look up the molecular weights. I'm using the molecular weight of atomic oxygen because that means when I do my calculation, it will tell me how many oxygen Adams I have and for manganese, that's the molecular weight given on the periodic table. So I want to use a formula, and I'm actually including and sub w as a formula for molecular weight. Often you'll just see it written as a capital in There's some potential confusion because later, in a different context, Capital M has a different. So I like to sneak in a little w there, and there's a formula that relates the molecular weight and the mass and the number of moles. And one way we can write that is molecular weight equals pass, divided by number of moles. I've got a cute little will, a memory trick, but I like did to use. If you write it in a triangle, then it makes it's kind of a shortcut for the algebra for rearranging it. So I'm gonna write it as a little triangle here. And the cute thing here is if you imagine just covering, say this guy, then molecular weight is given by mass divided by number of moles. Like I wrote here, we actually want to calculate number of moles. So if you cover up, this guy that's just given by mass divided my molecular weight, and it's just a little short cut that lets you work around actually doing the algebra and rearranging the equation all the time. It's a very simple equation, So number of moles of oxygen atoms, remember, is mass invited by molecular weight, which in this case is 1.1 or two grams, and I'm a big fan. Always carry your units divided by 16 grams. Her mole and I like to do this because now you didn't see the grams cancel and the moles on the bottom comes up to the top. It's your dividing fractions. Invert and multiply, and just dividing their gives us an answer. Zero point 07 14 rounded to four decimal places. And I like carrying the units because that kind of reassures us that we did it right. We got unanswered and bulls, and that's what we're expecting for a number of moles. So doing the same over here for our Mangan's is we have one point nine six to rams divided by 54 point nine or grams per mole again being good and carrying my units. And that gives zero point 03 57 And again, the grandes cancel models come up to the top and our units here are moles, just like we expect. We're trying to calculate number of moles. So now what we really want to know in our compound is what is the ratio of oxygen atoms, Teoh Benjani's Adams, and we can get that just by dividing them both by it doesn't really matter which one we do. Let's take a number of moles of Man Guinea's and divide by zero point 0714 and again now the moles air going to cancel entirely because we're just calculating a ratio and that comes out to 2 to 1. And we had the as backwards that comes out as 0.5. Or we could write that as one, the two, and that for the ratio of man Janie's, you know, oxygen. So the formula for our compound is I am in oh to a perfectly reasonable formula for man Guineas oxide. So that tells us what our little X and why here are so that's just man Guinea's oh, too. And now to balance our equation, we have one man Guineas, one man Guineas to oxygen to oxygen and everything's balanced

In this problem, we're balancing a Cem simple chemical reaction. The reaction between ammonia and oxygen. Cuba News my dream monoxide and water. And to begin well, the nitrogen zehr balanced initially Ah, hydrogen. We have three here and to hear and that's not balanced. So we could write a three halves here. But that's kind of messy because then we'd have happen old two year. So I'm going to put a three here which makes two times three is six. Hydrogen is, which means we needed to hear. But now our nitrogen is aren't balanced, so we need to here. So now I two nitrogen to nitrogen six. Hydrogen, six hydrogen. But let's count oxygen. Here we have to oxygen's and here we have three oxygen for a total of five, so we could fix that by putting a five halves here and then everything is balanced. But if we like the clear that fractional coefficient, which is perfectly acceptable, but it's a little neater with it it within multiply the whole equation by two and we end up with for ammonia. Why vote to giving for Eno and sex age duel

So for this problem, we're actually going to be looking back to Question 72 and at the four reactions that are shown. And we want to classify each of these reactions into one of the four categories where we have synthesis, combustion, decomposition and replacement reaction. So let's look at this first problem. So we have lithium solid, which is displacing this gold to form lithium chloride. So if you see you have lithium to replace gold to form our lithium chloride, so this has the overall. If we want to just generalize the different components, it would be a plus. B X forms a X plus be. And so because this is the case, this is going to be a replacement reaction. More specifically, a single replacement reaction. So for part B, we have iron plus 10 for nitrate to form iron three night tree and 10 and again you can see that we have our iron metal is displacing our 10. So where is we had 10 nitrate? Now we have iron night tree, so this also for has the general formula of A plus B X to form a X plus B. So this is also going to be a single replacement reaction. So for part C Now, if you notice we have a nickel to chloride plus oxygen to form nickel to oxide and die chlorine pent oxide. So any time you have some type of substrate will call this a plus oxygen to form a O. This is going to be an example of a combustion reaction because we're reacting nickel to chloride with oxygen, So this is going to undergo combustion for a part D. Now, if you look, we have lithium crew me plus barium chloride to form lithium chloride and bury improve me. So between our reactions and our products, we have lithium crew me in a reaction to form lithium chloride, and then we have barium crewmate as our product. So this is actually going to be an example off. Let's say if we have a X plus B y to form a Y plus B X, which is a double replacement reaction


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