5

Lear OtFrequencySenvice 71-5 6-10 11-15 16-20 21-25 26-30...

Question

Lear OtFrequencySenvice 71-5 6-10 11-15 16-20 21-25 26-30

Lear Ot Frequency Senvice 71-5 6-10 11-15 16-20 21-25 26-30



Answers

Draw a scatter diagram using the given ordered pairs and a line that you think fits the data. Use graph paper. Complete the missing entries in the table by reading them from your graph. Answers may vary. $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Weight } \\ \text { (thousands } \\ \text { of Ib) } \end{array} & \begin{array}{c} \text { Stopping } \\ \text { Distance } \\ \text { (ft) } \end{array} \\ \hline 2.0 & 96 \\ 2.4 & 110 \\ 2.7 & 130 \\ 2.8 & 130 \\ 2.8 & 142 \\ ? & 160 \\ 3.7 & 180 \\ 3.8 & 180 \\ 4.0 & ? \\ \hline \end{array} $$

On this question were being asked to determine the relationship between the weight and thousands of pounds compared to the stopping distance and feet. So here is our weight and dozens of pounds of this would be £2000 in this one right here would represent 96 feet. So we're looking to determine what is the relationship and what is the lean yer value that we can use to determine this information. So part of this question is not only graphing but also to determine the line of best fit and then last not least finding these missing values in the table. So in order to do this, we need to do a little bit of guessing check work. I have scaled this out so that we're dealing with very large numbers were going from zero through five on my X axis, but 50 through 250 on my Y axis, which means that we're gonna be dealing with some very large slopes here to get from here up to here within two units on the X values, we have to have a very large slope. So I'm going try. Why equals 50 X and see what that gives me an and look at that. It's it's pretty close. Umm, I might want us bring this down a little bit. So I'm gonna go ahead and do Ah, minus three. And that looks pretty good. But as I look at this line, I'm thinking to myself, Okay, this doesn't quite look exactly like I wanted to. It's looking a little steeper. Someone dropped this to 49 I think that bad line looks more accurate according to the data points. So this is gonna be the line that I use. Now, the question says that you will have different results. Your answer should probably be somewhere around these two numbers 49 negative three for your y equals MX plus B. Now, I'm gonna use these to determine my input value for this 160 foot stopping distance, and I'm going to use these £4000 to determine how long we need to stop. So coming over here, I'm gonna start by inserting and substituting the 160 into this y that you saw 100 60 feet is how long it takes to stop what type of car though, or what type of vehicle is when I'm assuming this problem is asking us. And then I'm just gonna go through my algebra work of adding, subtracting and dividing to get my answer. So just quickly do that gonna add three to both sides, plus three plus three That gives me a grand total of 163 on the left hand side, On the right hand side, I'm left with 49 x and a nice thing about padding the positive and negative of the same number they add to zero. Now I want to divide both sides by 49 so that I get a coefficient of one. The nice thing about this, the reason we want to divide it so that this becomes one and so I'm left with X is approximately equal to, and I'm going go ahead and around to one decimal place because this is a significant digits that we were given. So 3.3. So coming over here, I'm gonna put 3.3 into this and look at that. It's pretty close. Not perfect, but it's pretty close to the line. And that has to do with rounding differences now for the 2nd 1 The second blink, uh, high. Remember, replace the X with a four. Because it's selling as we have £4000 something and we want to determine how long it takes to stop this. I'm guessing vehicle. So we need to most by this out and then combine our like terms. So 49 times four is 196 minus three, 196 minus three Will then give me 193. And this should fall exactly on the line. 193. And look at that. It does so. There you go. Ladies and gentlemen, thank you very much.

Given in the question is this tiny circle 30 year old age of frequency 1.5 mega homes and amplitude 50 world is completed modulated by sinus several voltage of frequency 10 kHz which is producing The 15% of the modulation. Here we have to find the lower and upon side bend frequencies. The given values frequency of the carrier will is one point family heard mega hot which is the constituent 1500. Hey look out the frequency of the modulated view Is given us 10 kHz. Where for the lower side band the frequency will be fc minus fn. This will be 1500 -10. Low heart Equals to one for 90 you know heart. And for the upper frequency will be and this is and this example fc blast FM unknown adding both the frequencies. We will have the aqua band frequency As 1510 in your heart. Does we have the correct option for both frequencies is a.

This question asked us to use the data to make a frequency table has given the data. We know we're gonna be measuring time versus frequency in our table. And we know we can split up time. Given the fact that our last data point we can split up our last point given to 49 we can split up by nine. So ending in nines. So 1 49 and then 1 50 to 1 69. And then we know that we have 1 70 toe 1 89 1 92 209 And then we have two ton 2 to 29. And then lastly, we have 2 32 to 49. Now we're looking for how many data points are between 1 30 and 1 49 We know we have one data 10.1 35. We don't have to data points between this interval to data points, three data points, which is the most, and then to data points for these last two

In this problem were given an equation of the form. Wyche was a sine omega T and asked to find the period and the frequency we can use. Theo Quy Asian Buried equals two pi over Omega to find the period and frequency equals omega over two pi. To find the frequency in this case are Omega is going to be to kind times 9.15 times 10 to the seven because it is in the Omega position and it is next to the T. So we just pulling in our Omega into our two equations. We get that the period is equal to 1.9 times 10 to the negative eighth and the frequency is 9.15 times 10 to the seventh.


Similar Solved Questions

5 answers
D) 6) 2 Skecch the its inverse f(x) f(x) = graphs W Jg0 X+2 4 2 the 12+6 +4x+1 8 and following X< X<0 0 >x '(x) 8 functions the Statce' the uruop ow and 1 Hence;
d) 6) 2 Skecch the its inverse f(x) f(x) = graphs W Jg0 X+2 4 2 the 12+6 +4x+1 8 and following X< X<0 0 >x '(x) 8 functions the Statce' the uruop ow and 1 Hence;...
5 answers
Page 1 ofQuestion 1 (1 point) What would be the regent used to complete the Following reaction? CH,CH,CH;CI CH,CH,CH,CH;SOClz, pyridine0 Mg/etherLi; NH3(CHalCuLiNext PagePage 1 of 1
Page 1 of Question 1 (1 point) What would be the regent used to complete the Following reaction? CH,CH,CH;CI CH,CH,CH,CH; SOClz, pyridine 0 Mg/ether Li; NH3 (CHalCuLi Next Page Page 1 of 1...
5 answers
[opts _ 7. At R0OOoC the equilibrium constant for the reactionRNO(g) < + Na(g) Ox(g)18, Keq = 1.RxlO-& If the initial pressure of NO is 37.3 atm _ what are the equilibrium pressures of NO, Nz, and Oz?
[opts _ 7. At R0OOoC the equilibrium constant for the reaction RNO(g) < + Na(g) Ox(g) 18, Keq = 1.RxlO-& If the initial pressure of NO is 37.3 atm _ what are the equilibrium pressures of NO, Nz, and Oz?...
5 answers
ProblemIYGYK The net force applied to a 3 kg mass is 12 Nata 55 degree angle relative to the positive X-axis. Find the x andy components of the object s acceleration X-component 2.625 m/s? 2.835 m/s? 2.240 m/s? 2.710 m/s? 2.294 m/sz 2.795 m/sz1-1Y-component 3.162 m/s? B 3.936 m/s? 3.034 m/s?3.239 m/s2 3.947 m/s 3.27 m/sE
Problem IYGYK The net force applied to a 3 kg mass is 12 Nata 55 degree angle relative to the positive X-axis. Find the x andy components of the object s acceleration X-component 2.625 m/s? 2.835 m/s? 2.240 m/s? 2.710 m/s? 2.294 m/sz 2.795 m/sz 1-1 Y-component 3.162 m/s? B 3.936 m/s? 3.034 m/s? 3.23...
5 answers
Quesnon 1A #2 nave covered class this week and last; the standard error computed from which two components?Lhc mean and thc vahicsolt andth Valugnalard dcvlation and samdle0 The standard deviation and scorcUhichthc follovrng statemncnts Aizin dron thc centra umit (neorem?nuinvolted:tuccntnenetenhpurulnoUnali_DUEDEnIIna OtnpoC_LonmotnilnGton 54LUd FetElDomon KhnthtQuestionsearch
Quesnon 1 A #2 nave covered class this week and last; the standard error computed from which two components? Lhc mean and thc vahic solt andth Valug nalard dcvlation and samdle 0 The standard deviation and scorc Uhich thc follovrng statemncnts Aizin dron thc centra umit (neorem? nuinvolted: tuccnt n...
5 answers
Value E 1 1 W Jo threa eloniaceni IJunce 1 1 Djoruro IIL
Value E 1 1 W Jo threa eloniaceni IJunce 1 1 Djoruro IIL...
5 answers
1. Find power series representation for the function and determine the radius of convergence: Vr2. Use party (1) to expressdx as the sum of numerical series: +x3. Use party (2) to approximatedx correct to within 10 > [ +x
1. Find power series representation for the function and determine the radius of convergence: Vr 2. Use party (1) to express dx as the sum of numerical series: +x 3. Use party (2) to approximate dx correct to within 10 > [ +x...
5 answers
(3) A nationwide study conducted by the federal government; which employed random sampling techniques; reports that sevemty-six percent of college and university students in the United States have tried eestasy cocaine, or heroine. random sample of 300 college and university students from the United Stales, you tind that 240 have tried eestasy; cocaine; or heroine. At the 0,05 level (0r 0,S), there enough evidenee to reject the federal govetnments claim?
(3) A nationwide study conducted by the federal government; which employed random sampling techniques; reports that sevemty-six percent of college and university students in the United States have tried eestasy cocaine, or heroine. random sample of 300 college and university students from the United...
1 answers
Find the inverse of each function. Is the inverse a function? $$ f(x)=\frac{\sqrt[3]{x}}{3} $$
Find the inverse of each function. Is the inverse a function? $$ f(x)=\frac{\sqrt[3]{x}}{3} $$...
1 answers
In the astronomical triangle shown in Figure $36.14,$ with sides defined by light paths, the sum of the interior angles is greater than $180^{\circ} .$ Is there any astronomical triangle whose interior angles sum to less than $180^{\circ} ?$
In the astronomical triangle shown in Figure $36.14,$ with sides defined by light paths, the sum of the interior angles is greater than $180^{\circ} .$ Is there any astronomical triangle whose interior angles sum to less than $180^{\circ} ?$...
5 answers
A 747 jetliner lands and begins to slow to a stop as it movesalong the runway.A) If its massis 3.49×105 kgkg, its speedis 74.0 m/sm/s, and the net braking forceis 4.30×105N4.30×105N, what is itsspeed 10.0 ss later?Express your answer using three significant figures In m/sB) How far has it traveled in this time?Express your answer using three significant figures in m.
A 747 jetliner lands and begins to slow to a stop as it moves along the runway. A) If its mass is 3.49×105 kgkg, its speed is 74.0 m/sm/s, and the net braking force is 4.30×105N4.30×105N, what is its speed 10.0 ss later? Express your answer using three significant figures In m/s B) How f...
5 answers
ANQvASignificance 0.05046Regression Resldual Jotel67 39475 23222 175.,8769767,39475 437047.67248Coehficients 14 44820 +0.22826Standard Eiror 3797 0,03206Stat 40.47491 '6-90447P-value @00004 0,C0046Lower 95* 407217 0.30315Upeer 9516 1782423 ~0.14737nlurcedtStep 10 o/ 10: Use the mode] t0 pred ct thic number of skck days per year for _ emobyee wto 1 S0 yeats old Round tho nearest whote number.arratorpolnteTablei Keypjd Key board Shortcuts
ANQvA Significance 0.05046 Regression Resldual Jotel 67 39475 23222 175.,87697 67,39475 4370 47.67248 Coehficients 14 44820 +0.22826 Standard Eiror 3797 0,03206 Stat 40.47491 '6-90447 P-value @00004 0,C0046 Lower 95* 407217 0.30315 Upeer 9516 1782423 ~0.14737 nlurcedt Step 10 o/ 10: Use the mod...
5 answers
16.A sample of a mixture of KCIO3 and KCI weighs 5.454 grams When it is heated several times, the final mass of the mixture weighs 4.348 grams. The reaction that occurs is the loss of Oz(g) to the air from KCIO3 producing KCI The unbalanced equation is shown below. What is the weightlweight percent of the KCIOs in the mixture?KCIOaKCI 0z
16.A sample of a mixture of KCIO3 and KCI weighs 5.454 grams When it is heated several times, the final mass of the mixture weighs 4.348 grams. The reaction that occurs is the loss of Oz(g) to the air from KCIO3 producing KCI The unbalanced equation is shown below. What is the weightlweight percent ...
5 answers
Question 14cpQ DO.esHore; whch 30Amno257e Arn ]Tnete ard 10 Jre @aand dmnjs R tnd C euchhaccholllnrcrnfauintnlnadneetEann DraB n 4 volom |l You have #vellu box, whal ( the chance Ih a Branj o 0? Enict You Jrsnct Iractcn m crettlertiu M4
question 14 cpQ DO.es Hore; whch 30 Amno 257e Arn ] Tnete ard 10 Jre @aand dmnjs R tnd C euchhaccholllnrcrnfauintnlnadneetEann DraB n 4 volom |l You have #vellu box, whal ( the chance Ih a Branj o 0? Enict You Jrsnct Iractcn m crettlertiu M4...
5 answers
4. The number of arrivals at a car wash is Poisson distributed with a mean of 6 cars per hour What is the probability that at least 2 cars will arrive in the next hour?
4. The number of arrivals at a car wash is Poisson distributed with a mean of 6 cars per hour What is the probability that at least 2 cars will arrive in the next hour?...
5 answers
A four-year study of various brands of bottled water found that 25% are just tap water packaged in a bottle: In multiple samples of 10 brands, what is the expected mean number that contain tap water?0
A four-year study of various brands of bottled water found that 25% are just tap water packaged in a bottle: In multiple samples of 10 brands, what is the expected mean number that contain tap water? 0...
5 answers
Pre-Lab Questions(0.5 ptsJA student ties thread loop with circumference of 22.3 cm_ Determine the area of the loop- Show your work_22.3/2(3.14) = 3.55 =3.14(3.55)^2 39.57 cm^ 2(0.5 pts)Using the loop from question the student forms monolayer of molecule with an ared of 15,2 * 10-17 cm? Determine the number of molecules in the monolayer. Show your work_Click to enter text
Pre-Lab Questions (0.5 ptsJA student ties thread loop with circumference of 22.3 cm_ Determine the area of the loop- Show your work_ 22.3/2(3.14) = 3.55 =3.14(3.55)^2 39.57 cm^ 2 (0.5 pts)Using the loop from question the student forms monolayer of molecule with an ared of 15,2 * 10-17 cm? Determine ...

-- 0.030083--