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7) The solubility of 0 in water is 2.18 10 'Matm: Hlow many grams of oxygen would be dissolved in a [0 L fish tank under total air pressure of 742 mm Hg; where...

Question

7) The solubility of 0 in water is 2.18 10 'Matm: Hlow many grams of oxygen would be dissolved in a [0 L fish tank under total air pressure of 742 mm Hg; where air is 21% oxygen?8) A solution is prepared by dissolving [73 grams of CO. in 634 grams of I,O at 25"C. Given the faet that the normal vapor pressure Of water at this temperature is 23.8 mm Hlg; what is the vapor pressure of the solution?

7) The solubility of 0 in water is 2.18 10 'Matm: Hlow many grams of oxygen would be dissolved in a [0 L fish tank under total air pressure of 742 mm Hg; where air is 21% oxygen? 8) A solution is prepared by dissolving [73 grams of CO. in 634 grams of I,O at 25"C. Given the faet that the normal vapor pressure Of water at this temperature is 23.8 mm Hlg; what is the vapor pressure of the solution?



Answers

At $25^{\circ} \mathrm{C}$, the vapor pressure of water is 23.8 torr. What is the vapor pressure of a solution prepared by dissolving $65.0 \mathrm{~g}$ of $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ (a nonvolatile solute) in $150 \mathrm{~g}$ of water? (Assume the solution is ideal.)

A problem. 67 would need to calculate viper pressure off glycerin solution a day given temperature. And that's for us to write home asked you to get here, so we know massive glycerin investigation is 24 or five grass. We also know that we are dissolving it in volume off water, we just equal to 135 milliliters. We also know the density off the water with human to be 1100 Asper, the leader. Mmm. I only know the pressure off fewer water at the given temperature. I'm gonna market with the You want water, and the 30 degree sells his We're breaking up. Um, is 31.84 Okay, so these are givens. And in order to calculate the pressure of the solution, we need to, um, Ryan some vain. That is called rewards Law. And it dictates that B, which is the follow pressure off a solution is equal to the Moler fractional component. So in this case, that would be h 20 water times the pressure over your component. So this law dictates that pressure off each, um, component determines the final vapor pressure. So one thing we already have is, uh, pressure off pure water at the given conditions. The only thing that we need to calculate in order to be able to solve this equation, it's the heat, which we've done that. Okay. And he is the more fraction in this case, water, which is defined as the amount off, uh, salut, which I will, or in this case, because it's water. Our salute is water dissolved and blister, and you can think about this one. Um, so the amounts off water, which I will mark with 20 and, uh, divided by and control for this particular situation, it will be h 20 divided by and H 20 Gus and glycerin. Okay, so now we know how to calculate the he, um, the only two things we have to charming before that, um are you, uh, announced of our water growth Blistering. So let's do that. And hd all, it's equal to muss divided by molecular weight, more or less, which we know for order from periodic tables. So let's just say they're self some ready and say 1 35 Um right. 1 35 Millet leaders a density off one means that we will just multiply these two together I will get 135 grounds. And now we're divided by their more likable wins. 18.1 mole for water that we get 7.50 most What? So what about the glycerin? Same procedure. 24.5 droughts divided by 92. Is the more mass magic 0.1 grand from results in full on Tuesday, six homes, the cloister and enough solution. So no, we wouldn't do just place those values in the more fractions solution. And then we get 7.50 balls. Divide that by 7 45 0 moles of our water plus 4.266 holes for littering. Which gives us the mole auction off all 0.966 And this has unit. So the only thing that's left for us to do is to put that into the mold question. Are you here? So 0.966 a muller faction times. So do you want 18 door? He closed too. 30.7 for, um, of ourselves. So yeah, this is that final result

Chemistry. And so we have the major component of the solution. This is identified as the solvent. And we often find out this will be in the same phase as the solution and the minor component. So we can have one or more. These are identified as the sole cute. So here we're looking at collaborative properties and these are the properties of solutions and mixtures that depend upon the concentration. So they do not depend on which sold it is added to the pure substance. For example, we can have the freezing point depression, boiling point elevation, vapor pressure lowering and osmotic pressure. So here's what we have is the following equation. So we have delta P. So that's the formula for vapor pressure lowering. That's equal to I. P. A. Star XB. So here the eyes is the number of irons. And then when we have P. A. Start, this is the vapor pressure of the pure solvent and XP is the mole fraction of the salt lake. So here we can fastly calculate the number of moles of 24.8 g of sucrose, so and be is equal to 9.9725 moles. And then we can calculate the number of moles of 17.1 g of sucrose. So that's an A. It's equal to 3.89 moles. So the mole fraction of sucrose, that is XB. That is equal to N. B. So that's not points, not 7 to 5, divided by 9.97 to 5 at 3.89 So what we get is not point not one A three. So then we can go back to our equation for delta P. So that is equal to 11 I are multiplied by 42 point to miller meters of mercury, multiplied by 9.9183 The value we just calculated to get 9.772 millimeters of mercury.

Okay, so in this question, we have to compute the vapor pressure of a solution. To do that, we used Rose low that says that the pressure off some species a gonna be equal the pressure of that species when it's pure. So say the pure solvent times the Moeller ratio off that particular species, the Moeller fraction. So we have the pressure of the water when it's pure 31.8 tour or millimeters of mercury. And we have the masses off both water and sugar so we can compute the moderation. And then we can multiply both to get the vapour pressure off our our solution. So let's go ahead and do that. So let's start by computing the number of moles off the sucrose, which is the sugar zeros Sawyer. And we have 309 6 Gramps. So we used the molar mass to convert that to, uh, most. The molar mass off sucrose is 342 grams, so when you compute them, you will get 1.16 moat. Who now we can go and do the same for water. The number of malls off water. It's going to be equal 624 Gramps, That's ah was given in a question. So we convert that to most, using the more mass again. The Mormons of water is 18 grams. So cancel the units here. Sanity check. And then the value should be 34 0.7. Great. So now we have all the most they are needed so we can compute the total and therefore Dimel aeration. So let's go ahead and compute the Moeller ratio from water. Some alterations symbolized here by X. So that's gonna be the number of most of water. So 34 0.7 mol, divided by the total. So you repeat that 34 0.7 from modern. But you also add the number of malls off the Salyut. Okay, the sugar and that's your more racial. So compute that you should get 96.8. Sorry. 0.968 And, um, this is always gonna be mole ratio has always needs to be below. One cannot be won if it's one you mean is pure is just one thing there. So make sure the a number that you get makes sense came. So that's it. All we need is here, so we go back to Rose formula. And so the pressure of water going to be the pressure when the water is pure, so is 31 point a millimeters of mercury times the molar. Atia. There we go. So you do this little computation here, and you should get 30 0.8 millimeters off mercury. That's your final answer.

To calculate the vapor pressure of the Acquis solution containing sodium chloride, we need to use the rails law equation, Which is the pressure of the solution will be equal to the pressure of the pure solvent. In this case, water at 20°C at 17.5. Tour, multiplied by the mole fraction water. So if we have .1 kg, we have 100 g of water which we can convert two moles of water by divided by the molar mass of water. Well then divide that by the total moles of the solution, which will be the moles of water as we calculated above, multiplied by the total moles of solute. Because we are assuming sodium chloride completely dissociates that the total moles of solute will be two times the moles of sodium chloride. Where the moles of sodium chloride is the mass of sodium chloride, divided by the molar mass of sodium chloride. And we get 15 3 tour


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