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[ump to PJObjective 1: Compute Dot Product For Exercises 7-14, for the given vectors, find4YC# # (Sce Examplel)Excrcise: Introduction t0 the Dot ProductPDE Transcri...

Question

[ump to PJObjective 1: Compute Dot Product For Exercises 7-14, for the given vectors, find4YC# # (Sce Examplel)Excrcise: Introduction t0 the Dot ProductPDE Transcript for Exercise: Introduction to_the Dot ProductT.v= (-3,5) #= (10;ANer 8V=E (6,-7>,W= ( 4 93 = (3 "( 4 Anec 10. ' = (}a"( : IL.v = 64 w =Jj nahc 12.Y 2,w = I4i 13."Hi 6.8j.w 0Ai 03jAe 14: ~0.5i H.6j;W0li 23jFor Excrcises 15-18,usc the dot product to find the magnitude af the vector LSDNi

[ump to PJ Objective 1: Compute Dot Product For Exercises 7-14, for the given vectors, find 4Y C# # (Sce Examplel) Excrcise: Introduction t0 the Dot Product PDE Transcript for Exercise: Introduction to_the Dot Product T.v= (-3,5) #= (10; ANer 8V=E (6,-7>,W= ( 4 93 = (3 "( 4 Anec 10. ' = (}a"( : IL.v = 64 w =Jj nahc 12.Y 2,w = I4i 13."Hi 6.8j.w 0Ai 03j Ae 14: ~0.5i H.6j;W 0li 23j For Excrcises 15-18,usc the dot product to find the magnitude af the vector LS DNi



Answers

Find the dot product for each pair of vectors. $$2 \mathbf{i}+4 \mathbf{j},-\mathbf{j}$$

So in the given question, we have two vectors. Do I plus four days and another big did minus 30. So we are told to find the door correct of these victors. So to find the door product of a vector ai plus B J with another victor CI plus e g, we suggest multiply the corresponding magnitudes of these Victor's. Right. So the horizontal component that is the magnitude of the I component art A and C. So we will reply them eight times, See, plus the vertical components or the J components are B, J and D. J. So we take the magnitude of these factors, then it would be the time speed, So this would be the required document. So similarly, we can do the same with two. I lost four j and we can write minus J as zero I minus 10. Right. So then we can take the DOT Product of these vectors has two times zero, which is zero less four times minus one. So this would be four times minus one. So they required doctor at this. Mentors would be minus four. So I hope you understood the method. Thank you. Uh huh.

Okay, so we want to find a dot product between these two factors. So it's so very writing this. So that's four I. So that's four comma zero, and then we have five common negative nine. So let's find a dot product between four comma zero hands, five on the negative nine. So that's going to be the product of our vertical or horizontal component. So that's four times wind, plus the product of our medical components, So this is equal to 20 plus zero, which is equal to 20.

Okay, we're going to find the dot product of the given vectors. Now with the equation, the equation tells us if we have two different vectors, A, B and C. D, we multiply the X's plus, multiplying the wise. Well, it's going to be the same for this case. They've just given it to us in our component form, but we know that our first vector is one comma two, and our second vector is a negative one comma one. So we can just multiply our one times negative one and then add that to our two times one. So that will give us a negative one plus two or a dot product of one.

So in the given question, we have two vectors minus 38 minus 38 and another Victor seven minus fight. And we're told to find the door product of these vectors. So to find the dot product off of a dead baby and CD, we should just might apply the corresponding to warrant of a B with A B and C D. So what we get is eight times C plus billion times speak, which will be the doctrine. So, using this, we can Okay, find the dot product of the given with this that is minus 38 and seven minus five as minus three times seven plus eight times minus five. So this will be equal to minus 21 minus 40 which is equal to minus of 61. So this is the dark direct of the victors minus 38 and seven minus five. So I hope you understood the method. Thank you. Oh,


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