5

0/4 points Previous AnswersMy NotesAsk Your TeacherUse the Rydberg equation calculate the wavelength (in A) of the photon absorbed when hydrogen atom undergoes tran...

Question

0/4 points Previous AnswersMy NotesAsk Your TeacherUse the Rydberg equation calculate the wavelength (in A) of the photon absorbed when hydrogen atom undergoes transition from to at least significant figures.to n 2. (Report your answerYour response is off by multiple of ten. 4~/4 pointsMy NotesAsk Your TeacherCalculate the energy difference (AE) for the transition from figures; Jmolenergy levels of hydrogen per mol of H atoms. (Report vour answer to at least significant-/4 pointsMy NotesAsk Your

0/4 points Previous Answers My Notes Ask Your Teacher Use the Rydberg equation calculate the wavelength (in A) of the photon absorbed when hydrogen atom undergoes transition from to at least significant figures. to n 2. (Report your answer Your response is off by multiple of ten. 4 ~/4 points My Notes Ask Your Teacher Calculate the energy difference (AE) for the transition from figures; Jmol energy levels of hydrogen per mol of H atoms. (Report vour answer to at least significant -/4 points My Notes Ask Your Teacher How fast must 146 baseball travel in order to have de Broglie wavelength that is equa to that of an X-ray photon with ms 100 Pm?



Answers

What wavelength does a hydrogen atom emit as its excited electron descends from the $n=5$ state to the $n=2$ state? Give your answer to three significant figures. From the Bohr model we know that the energy levels of the hydrogen atom are given by $\mathrm{E}_{n}=-13.6 / \mathrm{n}^{2} \mathrm{eV}$, and therefore $$ \mathrm{E} 5=-0.54 \mathrm{eV} \quad \text { and } \quad \mathrm{E} 2=-3.40 \mathrm{eV} $$ The energy difference between these states is $3.40-0.54=2.86$ $\mathrm{eV}$. Because $1240 \mathrm{~nm}$ corresponds to $1.00 \mathrm{eV}$ in an inverse proportion (i.e., the more energetic the photon, the shorter the wavelength), we have, for the wavelength of the emitted photon, $$ \lambda=\left(\frac{1.00 \mathrm{eV}}{2.86 \mathrm{eV}}\right)(1240 \mathrm{~nm})=434 \mathrm{~nm} $$

So the wavelength of the light that is emitted can be found using planks formula. So thanks formula is equals H C over Lambda, where Landry's wavelengths and just in case you didn't know boundaries represented by that symbol, where is our energy? We've given this value we needed in jewels, so it's an S I units ages. Plank's constant nights on the screen see a speed of light also on the screen. So all of the numbers you need are on the screen in order to calculate our wavelength. So what we need to do is rearrange our equation for wavelength, which I've done So it's Lambda equals H D over E. And then we plug in our numbers, which is up on the screen already. And this generates a value of Lambda equals 4.8 times 10 to the power negative 7 m

So here we're looking at the change in energy for a transition involving two energy levels and a hydrogen atom delta E. Is equal to E. Final takeaway E initial which is also equal to negative 2.179 times 10 to the minus 18 jewels, multiplied by one over N. F square. Take away one over N I squared. Where we can relate the wavelength to the change in energy where lambda is equal to hc over delta E. Here we have a series of values to plug in from N equals 12 and equals four. So I change in energy is equal to -2.17, 9 times 10 to the -18 jules, multiplied by 1/4 squared take away 1/1 squared. So I change in energy is 2.04, 2 times 10 to the minus 18 jules. And then what we need to do is plug this into our second equations. We've just used equation want, we're moving on to equation to now. So what we have is λ is equal to six 6-6 times 10 to the negative 34 jewels per second, multiplied by 2.998 times 10 to the eight m per second. Then we divide that by the change in energy valley. We just calculated which is 2.42 times 10 to the -18 jewels to get a land value of 97.28 nm.

Okay. In this problem, we have Compton scattering foran. Incoming actuator. Gamma ray with a wavelength of lambda is scattered off a free electron at rest that gamma ray or X ray light light has a resulting wave length of Lambda Prime, and it's scattered at some scattering angle data. And this electron, after being scattered that we'll have a glossy Avi. What's interesting about this problem is that this velocity V is very is a very, very large fraction of the speed of light. We're asked to find the original wave length of the incoming light and the scattering angle given the end wavelength and the end velocity of this electron. So we're going to use the typical Compton scattering equation, which relates the change in lambda for the light to a scattering angle theta. We're gonna use the energy of each vote of this photons of each photon in our light. But what's interesting about this problem is that we're gonna actually have to use the relativistic expression for the kinetic energy M C squared gam eyes one where Gama is. This relativistic factor for Constance will use planks Constant and Jules Jules seconds as usual speed of light and mass of an electron. So notice this If the speed of light is three times ten the eight meters per seconds than one point eight times ten of the eight meters per second, that's that's close to sixty six percent of the speed of light, Which is why, which is what justifies our use of this relativistic expression. So before we played numbers and morass to actually derive expressions using symbols only for Lambda and Data So let's jump into it. Okay, so starting out we can use conservation of energy. Well, sorry that actually we should find gamma First we know the velocity of this electron. We know how gamma is defined as one minus V squared over C squared. All this is a negative one. So if we plug in our one point eight even the eight meters per second all that squared over three Idiot Hey, squared tonight of one we played this in we'LL have a resulting gamma of one point two five. We'Ll need that for later now to find our original Lambda instead of using the Compton scattering equation which involves will involve two unknowns Lambda and Data. We will start using by using conservation of energy. So before this scattering our light or photons will have a energy of HC over Lambda after the scattering our light Well, I was a new wavelength. So its energy will be a sea over land a prime and we have to consider the kinetic energy of our electron. Show them the square gram wise one. So with this expression, we know everything except for Lam the original Lambda so we can solve for it. Algebraic Lee can divide both sides by H. C. And we could move some stuff around. And we will We'll do it in two steps. I could start off with Lis, emcee of rage, you know, minus one Okay and then we can simply inverse everything good And that's our expression for the original Landa given land a prime and the gamma of our particular Elektron. So it's one step If we plug in all of our numbers which were given, we will find that this lambda is three point three four times ten to the negative twelve meters. So now let's go a new page and look att how to find Mato So now we would start with the Compton scattering equation Booth. It's strawberry doing that much better. A little better. So So all these air H. O Francie is a constant. And actually I can quote its value for you instead of using a gem and see all the time. It actually is useful as a rule of thumb to have this number memorized or at least written down somewhere two point four reset for two seven either negative twelve meters is this expression. We use it so often it might be useful. Just simply happen. So assuming that we know both Lambda Sze we solved for the original Lambda in the previous page, we can find data doing just a little bit of algebra began multiply We'LL sides by M c R h And then we can isolate data in the usual way of one minus. This stuff should with a little bit of room inverse co sign everything all of this and that will be our expression. So plugging in our values For Lambda Lambda Prime, we would have a result of seventy four point zero four five degrees. Great. So this is solving this finding these expressions for data and Lambda algebraic Lee and certain numbers. It's the same procedure that you would see and it really any confidence scattering problem. The only twist in this particular problems that we have a electron scattered electron which has energy comparable to the speed of light, meaning we have to use a relativistic expression for its kinetic energy. That's the only twist on this problem. We've found Lambda and we found data, and that's all we're asked to solve for so thank you very much.

For discussion. We have a four time x ray photo on coming in. Dan Electron scared us off. We've some kinetic energy, and it's for LCS given to be. So we got to find the initial rethink Lambda and himself prying miss off the electron s feisty frosty. So by energy conservation, you know that, uh, you show energy just given s you see? Well, must be close to the final energy just given us. You see the prime. Plus, you can add energy off the electron Just half mv squared in this case, Uh, if we want to do it relative sickly, right? If you want to account for relativity, we have to Youth. Come on. Minus one times, EMC squared Kennedy energy. Right? So d we're gonna finest e we Thank you. So we could have rearranged the secret of it. Bring the lump tied everyone up. Don't have to see what by you see William the prime. The US government. It's one time Miss EMC squid. Of course, you have to bring my cell comma. But to simplify this expression of it we can do is to once play one of, ah, see one of a hissy to both Newbury 30 nominator in this very it's what? Deploying lumped up trying to both numerator denominator. So what we get? Yes, prime. You gotta buy one thus come on. So you loved a prying times M c square, do you, father? By each see so see, what can celebrities square and then we have come on minus one. Well, uh, comma. Yes, we turn s one over. Skirt off. What? Minus the square of Ah, see square? No, for the second, all of these questions gonna find What is the angle that the photo is scattered pie. We used the Compton scattering Former under minus. Stand up trying. He's a case number prime minus lambda goes to each over M c one minus sign detail. So you wanna find waste Ito putting thesis delta Lebda like, just basically change a shift. Rethinks then, Uh, religious bits. So we have shift times M c you better by each one. My school scientist. So the ankle they want is a co sign off one minus shifting riffling times. EMC over each Now to a very great the expressions that we have got using actual values. So we have, um uh for the scattered photons. Just under prime s 5.1 Time said Paul Ministry millimeters. Try to substitute that into fine our or is, you know, wave so they see expression. But of course leads to neato. Come on, minus one. We believe government by itself ceases. No, you would be quite messy. One minus peace Group C Square. So we have given it to be one point it time sent for eight. It's 1.25 Therefore couple minutes. What is your point? 25? You're gonna substitute that in two. Very. This expression maybe should get about 3.34 It's Ted, Home Ministry. Nana Rita's with this very off London. We can don't find the shift given this 5.1 Time said our mystery ministry points you full and we're gonna use this in finding our angle. It'll she's just sign one minus the shift. But you have to convert this nanometers in to eat us so much. About 10 point mice Night times, M C time divided by each I think the angled ever get is about 74.0 degrees


Similar Solved Questions

5 answers
Thequadrilateral ABED % 16, whatna 0 Eectancke ABCm2Suprr that ahd aatinty !e {alloning Innqualtice 44$ ] 0 Svs8 Find the paaihle valura Io rach Ubr folkrnt Ura inerqualtir t derctile Your anamu (ue (bp (ul)
the quadrilateral ABED % 16, what na 0 Eectancke ABCm 2 Suprr that ahd aatinty !e {alloning Innqualtice 44$ ] 0 Svs8 Find the paaihle valura Io rach Ubr folkrnt Ura inerqualtir t derctile Your anamu (ue (bp (ul)...
5 answers
Question of 6 (1 point) AttemptUnlimtedVlel queation In POPUPTimes Spent in Rush-Hour Traffic sample of 13 drivers shows the time that they spent (in traffic on specific snowy day last winter; Round your answers to one decimal place. 72 70 60 61 49 46 48 75 72 78 71 50 51Send Jata BrcelPart of 3Find the rangeThe range isPart: 1 / 3Part 2 of 3Find the variance_The variance is
Question of 6 (1 point) Attempt Unlimted Vlel queation In POPUP Times Spent in Rush-Hour Traffic sample of 13 drivers shows the time that they spent (in traffic on specific snowy day last winter; Round your answers to one decimal place. 72 70 60 61 49 46 48 75 72 78 71 50 51 Send Jata Brcel Part of ...
5 answers
Aolem 1.125 Points) Considar the function f(x) xelue Thls tuncton has two crical nugbersand B =Foreach ot the tollowing intotvals Icll wnetht f"(x posttive (typo In +} or nepalve (ype In ~1(-m.a):(4,B):(8.0)Thus tra concluda that f(x) hus 0(type [ Maxt UM ad IocalRite: You can arn partia} cradit 0n thls probam
Aolem 1. 125 Points) Considar the function f(x) xelue Thls tuncton has two crical nugbers and B = Foreach ot the tollowing intotvals Icll wnetht f"(x posttive (typo In +} or nepalve (ype In ~1 (-m.a): (4,B): (8.0) Thus tra concluda that f(x) hus 0 (type [ Maxt UM ad Iocal Rite: You can arn part...
3 answers
The probaility that an interval estimate contains the true value of a parameter is a. standard errorb: point estimatorC. confidence leveld.sample size margin of error
The probaility that an interval estimate contains the true value of a parameter is a. standard error b: point estimator C. confidence level d.sample size margin of error...
5 answers
You can uSC the Substitution Ruledx I (1 + (lnz)?)fIvi-rdr
You can uSC the Substitution Rule dx I (1 + (lnz)?) fIvi-rdr...
5 answers
Draw both chair conformations for this structure. (6 pts. each) Which more stable? (4 pts.)Mre Stable
Draw both chair conformations for this structure. (6 pts. each) Which more stable? (4 pts.) Mre Stable...
5 answers
QUEsTIoNMe tullo Ind graphsomcmhlc Ghve Ihe Ieomofpnlem and explaln be :tepede-Idlna on :Mnerenot a"coliect akccnthmi; bu -hefe areat mleiakes tat can hifpen 1 tlecin onialve pamlal ciedit It unceratand "rahappenlaomle-ske cccurte_8D
QUEsTIoN Me tullo Ind graphs omcmhlc Ghve Ihe Ieomofpnlem and explaln be :tepe de-Idlna on : Mnere not a"coliect akccnthmi; bu -hefe are at mleiakes tat can hifpen 1 tle cin onialve pamlal ciedit It unceratand "ra happenlao mle-ske cccurte_ 8 D...
5 answers
Toustucy eok? The mean rosponaz the 432 Frdoul many mours typical class suryey large ciass far first-ycar college studcnts askcd, distribution wlth standard devlatlon hours Intha population otoli Suppase that K0 know that tne study Ume follons Notna Kuiciaaeselnk a-dat InoMns Fce-Vcr tandenls theuniversitWhat995 coniidcnct inlarvolOQ [} for the papulatiam micon?Conlidence Interval trom nouts
Toustucy eok? The mean rosponaz the 432 Frdoul many mours typical class suryey large ciass far first-ycar college studcnts askcd, distribution wlth standard devlatlon hours Intha population otoli Suppase that K0 know that tne study Ume follons Notna Kuiciaaeselnk a-dat InoMns Fce-Vcr tandenls theun...
1 answers
Differentiate the following functions. $$y=\frac{\ln x}{\ln 2 x}$$
Differentiate the following functions. $$y=\frac{\ln x}{\ln 2 x}$$...
5 answers
15 [-/1 Points]DETAILSDifferentiate the function_5 +
15 [-/1 Points] DETAILS Differentiate the function_ 5 +...
5 answers
Which of the following total shipping cost for the transportation problem using the Jowest cost method Capacttl Secn
which of the following total shipping cost for the transportation problem using the Jowest cost method Capacttl Secn...
4 answers
Tabla Results of Regression AnalysisMultiple R R Square Adjusted square Standard Entor55424 45759 45725 42173(5,244) 4.578 DooVariableBETAProducts fcatures Number sale smen Population density Purchasing power Promotional eflectiveness768DOO 0oo 467 089 Odo
Tabla Results of Regression Analysis Multiple R R Square Adjusted square Standard Entor 55424 45759 45725 42173 (5,244) 4.578 Doo Variable BETA Products fcatures Number sale smen Population density Purchasing power Promotional eflectiveness 768 DOO 0oo 467 089 Odo...
5 answers
Nitrogen and water react to form nitrogen monoxide and hydrogen, Iike this: N,(9)+2H,O(g)--2NO(9)+2 Hz(g)Write the pressure equillbrium constant expression for this reaction:
Nitrogen and water react to form nitrogen monoxide and hydrogen, Iike this: N,(9)+2H,O(g)--2NO(9)+2 Hz(g) Write the pressure equillbrium constant expression for this reaction:...
5 answers
Let X1, Xn be independent identically distributed with probability mass function if € =-13 f(w;0) ={6i-00, if x € {0,1,2,...}, where 0 € 0 = (0,1)_ (a) Prove that T = (C I-1}(Xi), CXi) is minimal sufficient
Let X1, Xn be independent identically distributed with probability mass function if € =-13 f(w;0) ={6i-00, if x € {0,1,2,...}, where 0 € 0 = (0,1)_ (a) Prove that T = (C I-1}(Xi), CXi) is minimal sufficient...
5 answers
[6 marks] A radioactive decay diminishes the quantity of a material to half its original quantity in 12 hours How long will it be before it decays by 90% of its initial quantity?b. [6 marks] A 6 meter ladder leans against a building: The foot of the ladder is pulled away from the building at a rate of 0.61 m/s How fast is the top of the ladder falling when the foot is 5 meters from the building:
[6 marks] A radioactive decay diminishes the quantity of a material to half its original quantity in 12 hours How long will it be before it decays by 90% of its initial quantity? b. [6 marks] A 6 meter ladder leans against a building: The foot of the ladder is pulled away from the building at a rate...
5 answers
Ji the indefinite integral #+fd:
Ji the indefinite integral #+fd:...
5 answers
If you are going to perform an electrophilic aromatic substitution of benzene; what would be the most logical rate determining step in this reaction?Addition of an electrophile & loss of protonFormation of an electrophileThere are no rate- determining stepls) in this ' reaction.Formation of a sigma complexLoss of a proton from the sigma complex:Benzene cannot be substituted through this mechanism:None thcse
If you are going to perform an electrophilic aromatic substitution of benzene; what would be the most logical rate determining step in this reaction? Addition of an electrophile & loss of proton Formation of an electrophile There are no rate- determining stepls) in this ' reaction. Formatio...

-- 0.019641--