5

3 & I ; 1 Ii 1 I 3 2 !ll 1 [ 12 8 : 8 8 1 ] B| 1 1 1 1 1 8 I 2 6 1 0 2 8 'l 1 1 1 0 SPl 1 1 6 5 18 3 I 0...

Question

3 & I ; 1 Ii 1 I 3 2 !ll 1 [ 12 8 : 8 8 1 ] B| 1 1 1 1 1 8 I 2 6 1 0 2 8 'l 1 1 1 0 SPl 1 1 6 5 18 3 I 0

3 & I ; 1 Ii 1 I 3 2 !ll 1 [ 12 8 : 8 8 1 ] B| 1 1 1 1 1 8 I 2 6 1 0 2 8 'l 1 1 1 0 SPl 1 1 6 5 1 8 3 I 0



Answers

$$\left|\begin{array}{rrrrr} 3 & -2 & 4 & 3 & 1 \\ -1 & 0 & 2 & 1 & 0 \\ 5 & -1 & 0 & 3 & 2 \\ 4 & 7 & -8 & 0 & 0 \\ 1 & 2 & 3 & 0 & 2 \end{array}\right|$$

Okay, This problem, we have equals to falling. And it's also a three by tweet matrix. So we have negative. 310 and then zero negative. 31 and four Negative. Eight two. Now we can obtain the characteristic equation again. As follows. The same exact procedure as the previous problems. We have a negative Lambda cute minus four. Lambda squared minus five. Lambda minus two equals zero. So, Landau, one comma to come on three are gonna equal native one negative one. And negative, too. Now, for Lambda equals negative too. We want to solve the following equation for the Eiken victor. A plus two i times u equals zero. Then we'll obtain u equals T where Ty's every parameter, as always, times 111 And for Lambda equals negative one. We saw this equation a plus. I times you equal zero. And when we solve this, we will get you is equal to a T times 1/2 1 and two or equivalently team times one, two and four. Because this is just the Eiken victor skilled differently, scaled up. And so we have our answers

This video, We're gonna go to the answer. A question of a 13 from Chapter nine White three for us to find the inverse off. The matrix minus two minus one 210 31 minus four. So let's combine this with the identity matrix once there is, There is there were once they were serious, they were What? Yeah. Reduce. So that's that three altitude of the first row to the bottom room. So that's going to go to zero. Ah, mine is 1/2 minus one ad for you, too, is 1/2. I want us to be over twos to you too. Keep a zero and one. And let's also add one of the first road to the second round. Get rid of this too. We're all scared of this wall. Uh, this becomes a wall 10 Top row stays the same minds to you. Minus one. Ah, whoa! 100 Next up, less subtract one of the middle row from Sapporo. So that's gonna be minus two minus one zero. Uh zero minus one zero. Minimo stays the same. 0011 What? Zero. That's also most black bottom are about to but zero minus 11 302 Next up, let's subtract one of the middle row from the bomber. That's gonna be zero minus one. That's zero at three months. Ones, too. They're minus one minus. Y T minus zero is too. Keep the middle. Where was it? Is seriously, Rabban. War hero. And keep the top roses minus two minus one. They were. They were minus one zero. Okay, let's subtract one of the bottom row from the top room. So I'll get rid of this month's one at zero minus two is minus two minus one minus 110 Uh, zero minus two is much too, kid made about the same there. Is there a woman? Rome on zero on dhe bomber. We can multiply by one, get zero. What? Zero. So most by my minus 1010 too, because minus two minus one equals one. T because minus two. Now, what we can do is most by the top row by minus, huh? It's gonna be born zero zero. Whoa, zero. What? Now you'll see that the form two rows. Uh, if we just flip these around, which you can do it, bro. production on. Then we get the I don't see a downside. So 010 That's what was the bottom room minus 21 minus two in the middle ground, which is not about tomorrow. 001 Well, zero on Dhe. This matrix here is the inverse off the matrix that we started with.

So in this question, we have to make this transformation. My industry are one plus R two. So here are one will remain until changed one minus 15 minus six are you will be operated US three minus 30 three plus three. That this six minus one minus 15. That this minor 16. And this is then plus 18 that this 28 on our three will also remain intent. 13 to five. So that is my answer.

So in this question we have to make two transformations to our one plus Arto Onda minus r one plus R three. So here, only the first tour event as it is untainted. Oneto one toe this will become a zero. Do those are four minus one That this three This is two plus before And this five plus for their this main He had a vin one minus 10 three miners toe that is one minus two minus on that this minus three and minus eight minus. So that is my understanding. So that is my


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