Homework: Practice for at Score: 0 of 1 pt5.3.75Perform the indicated operation and reduce the answer to40 50 60 7} 40 50 %-0Enter your answer in the answer box and...

Use a graphing calculator to perform the indicated multiplications.$$\left[\begin{array}{rr} -7 & 8 \\ 5 & 0 \end{array}\right]\left[\begin{array}{rr} -90 & 100 \\ 10 & 40 \end{array}\right]$$

Okay. One performance operation here. On first off, when you've got two minus signs for each other, you can turn into a positive. So you have minus 20. Plus 30 here, then minus 50 plus 40 and business community stiff. So you could bring you Fay and for you up front and add them together to get 75 70 from minus 20. Minus 50 on Dhe. You could bring a minus one in front of these two negatives so that you've got 70 minus one lot off 20 plus 50 on 2050 degree, simply 17. So you're 70 lots 70 minus one. A lot off 70 which minus one time. 70 70 70 minus 70. Well, that's simply zero.

Could you? So let's solve the phone for a remove our A's to arm right now inside and are constants to our left time side. So this gives us a 100 is equal to 10 a and now let's divide both sides by 10 and we get that A is equal to 10.

Way have 1940 s, minus 34 years, minus 1/40 notice. We already have a common denominator of 40 for each fraction, so we can combine all the numerator is 19 minus three minus one. All over 40. Well, 19 minus three is 16 minus one is 15/40. 15 is, uh, five times three and 40 is five times eight and the fives would cancel. And so 15. 40 this is the same thing is 3/8

Suppose you want to find the limit of the function, erase the two x minus one All over each of the X -1 As X approaches zero. Now evaluating this directly, we get E to the 0 -1 over E to the 0 -1. That's just one minus one. 0/1 minus one is just also zero. This value is indeterminate. Which means that we need to find a function G. Which is the reduced form of F of X. And use this to find the limit of Yeah, no, Eat the two X -1 over. Eat the X -1. This is the same as Eat the X -1 times. Eat the x plus one all over. E. To the X -1 in which we can cancel it. Eat the X -1. And we left with E to the X plus one, suppose this is our G of X. Now we can use this to find the limit of F of X. That means Limit of the function. Eat the two x -1 Over either the X -1 A sex approaches zero. This is equal to The limit as X approaches zero of G of X, which is just E to the X plus one. This is equal to eat the zero plus one or one plus one, which is just too. Therefore the limit of dysfunction is two. You can verify this using this graph right here and see that as we move closer to the row, either from the right side or left side of the graph, the value of the function goes to two. Therefore the limit of this function is indeed two.