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The ka for a weak monoprotic acid HA is 6.7 ×10-8. Calculate the concentration ofA- in units of M for a solution containing 0.055 MHA and 0.11 M of a strong mon...

Question

The ka for a weak monoprotic acid HA is 6.7 ×10-8. Calculate the concentration ofA- in units of M for a solution containing 0.055 MHA and 0.11 M of a strong monoprotic acid.

The ka for a weak monoprotic acid HA is 6.7 × 10-8. Calculate the concentration of A- in units of M for a solution containing 0.055 M HA and 0.11 M of a strong monoprotic acid.



Answers

A 0.185 M solution of a weak acid (HA) has a pH of 2.95.
Calculate the acid ionization constant (Ka) for the acid.

So the pH of the solution is three point to night. So from Ph, you could calculate the proton because calculating the proton concentration, which is tend to the night there's three points too high, equals five point one three times ten to the negative. Forthe Moller. And we know that Kay is age three o plus concentration times a minus concentration divided by H. A. And we could use the approximation this case in a top this three h real plus equals a milers equals the same number. So he used five for one one three times ten to the negative fourth square divided by the A J concentration, which is point one one five more and we've got a value is two point tonight times turn to the nectar of six.

In this question will calculate the acid ionization constant for a weak acid. Give him P. eight is 2.95. And concentration of the acid. Yes. 0.185. What now ph minus law. Hydro near my own concentration. Therefore. Hi dani. Um concentration will be 10 to the power negative P. H. Which is 10 to the power negative 2.95 Which is 1.1-2 Times 10 to the power negative three mona. So now we have the concentration of high Dona mile. Now we'll set up the ice table and still that. Oh plus needs to yeah. In my nurse blast is to your class. Of course. Yeah. Yeah. Yeah. Yeah. Yeah. All right mm. Mhm. Okay. Hair. I initial concentration change concentration and E. For equilibrium concentration Concentration of the sed s. Mullah and Will ignore this one. No concentration. Hair. No concentration here then minus six blah six plus eggs. Now equilibrium concentration will be 0.185 minus X. And here it will be X. And concentration of high Dona man. We just calculated that is 1.1 to 2 Times, tend to depart -3. Now we have the concentration of high Dona Mayan. Now concentration of a minus a minus also equals to the X. Value or fix. So concentration of a minus will be 1.1 to 2 times 10 to the power negative three molar. And concentration of the acid H. A .185 minus X. So .185. My not 0.001122 which will come 0.18 388 more. Like. Okay so we have all the concentration now we have to calculate the ionization, acid ionization constant. K. A. E concentration of a minus times concentration of high Dona Mayan divided by concentration of the acid. Mhm. Mhm. No concentration of a my nest is 1.1 to 2 times 10 to the power minus three Hatoyama ion, also same value 12 to 10 to the power negative three, And concentration of the acid 0.183, 8, 8. And it will come 6.8 Times 10 to the Power -6. Therefore, acid ionization constant that is K A. Is 6.8 times 10 to the bar -6. Yeah.

Yes in this question. 0.185 Muller. We guess it is given Which has a ph of 2.95. We have to calculate that as a dissociation constant. K. A. Now Speech of the Assael is giving us 2.95 which means negative law. Hi Dona. My own concentration which is equal to 2.95. The concentration of Hatoyama will be 10 to the bar negative 2.95. So consultation of hydrogen helium ion is 0.00112. And now let's write the ionization equation of the acid H. Is desi Plus H. two more produces in my nurse Plus is three your plus. Now let's make that I stable here Initial concentration. 0.185. Okay. Change concentration minus six plus six plus six equilibrium concentration 0.185 minus six. X. X. Now. Right. The expression for key E. Key is concentration of a minus times concentration of a studio plus divided by concentration of that week. C 80 equilibrium concentration. Now, concentration of high Donia man is A which is equal to concentration of a minus so X. Square divided by 0.185 minus X. Now exist the concentration of Macedonia mar, which we have already calculated. So there are four E. S 0.00112 sq. If I did by 0.185 -0.00112. And the value is 1.2544 times 10 to the poor negative six, divided by 0.18388. So the hello for K. A is 6.8 times 10 to the bar negative six. This is the hello for K. Of that weak acid.

Okay, so we have a quick 185 polarity solution of a weak acid A J that has a ph of 2.95 We have to calculate the asset ionization constants case, too. Okay, a critical acid. Okay, so you know that the pH you go to the negative log of R H three old concentration. Well, in this case, we're trying to look for the concentration of H 30 plus That's equal to 10 to power of our pH value, but a negative. Hey, Charlie, kids are pages 2.95 That gives me 1.12 polarity. Okay, Now that we have this concentration, we can actually create our table. So we have a reacts with some water to produce a minus and age people. Plus, we don't include our. It's too old in our ice table because that's disappear liquid. So it's not gonna change any of its concentration. Your initial, um, concentration for a is 0.18 We know at equilibrium are it's real class. Concentration is one point 1 to 2 times 10 to the negative three and me, So our initial value for a product is though I change in our reactions isn't made of X and in our product is positive. You know, some those together. Okay, so we have it. So let's start by solving for our change in X. You see that in our it's three old pluck home that is supposed to equal to this concentration here, right? Since the changes from zero x X is actually equal to this from here. So we actually know our eckstrom are X is equal to 1.1 to 2 time tension, and they're gonna pay. Okay, sit in our concentration for, um a k pretty quick to 0.185 minus X, which is equal to 0.185 minus 1.1 to 2 times 10 in the negativity. What did you go to? 0.1838 polarity. Okay, so it's on the equal, even concentration for a J. And we also have to find it for Do you mind it? But that's equal to this extra 1.1 to 2 times tension in a group rate. All righty. Okay, Now let's find our K value. RK value is equal to a minus times H reo divided by a J. Well, we actually have all these. All these just all for all of them. So at 1.12 still times, can't you see? And since the value or these concentrations of the time, the same on a new murder roof before that. And then divide that by 0.183 Okay, which is our concentration for a change, and that gives me 6.8 times 10.


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